iii | iii - Eye-Fi card manager daemon open source implementation
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kandi X-RAY | iii Summary
iii - Eye-Fi card manager daemon open source implementation
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QUESTION
looking for a quick solution to pick up the text following a numeric value that looks like this:
text to extract
...ANSWER
Answered 2021-Jun-04 at 07:28We can use re.findall
here as follows:
QUESTION
I want to filter a df with respect to working days.The df is:
...ANSWER
Answered 2021-Jun-15 at 05:26If need exlude only Sundays use offsets.CustomBusinessDay
:
QUESTION
I need to make several nested loops like this, but with a generic number of looping indices:
...ANSWER
Answered 2021-Jun-14 at 13:30Use itertools.product
to generate tuples of the desired indices. For example:
QUESTION
I am new to zimpl and I am currently trying to modell the GTSP. The setting is that we have nodes which are grouped into clusters. My problem is i dont know how to implement in zimpl which node belongs to which cluster.
What I did so far:
set V:= {1..6};
set A:= { in V*V with i < j};
set C:= {1,2,3};
set W:= { in C*C with p < q};
set P[]:= powerset(C);
set K:= indexset(P);
I am guessing something is missing because i want to group node 1,2
in cluster 1
, 3,4
in cluster 2
and 5,6
in cluster 3
.
Some background Information:
Let G = (V, A)
be a graph where V=1,2,...,n
is the set of nodes and A = {(i, j): i, j ∈ V, i ≠ j}
is the set of directed arcs (or edges), and let c_ij
be the travel distance (or cost or time) from node i to node j. Let V1, V2, ... , Vk
be disjoint subsets of V such that union of these subsets equals to V. These subsets are called clusters. The GTSP is to find the tour that (i) starts from a node and visits exactly one node from each
cluster and turns back to the starting node (ii) never
visit a node more than once and (iii) has the minimum total tour length.
Associated with each arc, let x_ij
be a binary variable equal to “1” if the traveler goes from node i to node j, and “0” otherwise.
Thats the mathematicl model I want to model:
min∑i∈V ∑j∈V\{i} cijxij
subject to:
∑i∈Vp ∑j∈V\Vp xij = 1 (p= 1, ..., k)
∑i∈V\Vp ∑j∈Vp xij = 1 (p= 1, ..., k)
∑j∈V\{i} xji − ∑j∈V\{i} xij = 0 (∀i∈V)
xij∈{0,1} ∀(i, j)A
up−uq+k ∑i∈Vp ∑j∈Vq xij+(k−2)∑i∈Vq ∑j∈Vp xij ≤ k−1 (p≠q;p,q=2,...,k)
up≥0 (p=2, ..., k)
(Thats the link for the paper: http://www.wseas.us/e-library/conferences/2012/Vouliagmeni/MMAS/MMAS-09.pdf)
Maybe someone can help! thanks
...ANSWER
Answered 2021-Jun-12 at 15:36You can use an indexed set (just as u did to implement the powerset of C
) and assign the sets as needed. Try this for example:
QUESTION
matrixA =
[['AAA', 'BBB', 'CCC'],
['PPP', 'QQQ', 'RRR', 'SSS'],
['DDD','EEE','FFF'],
['GGG', 'HHH', 'III']]
...ANSWER
Answered 2021-Jun-11 at 05:23You can get the index
of listA
within matrixA
and then slice with it:
QUESTION
How to do that?
...ANSWER
Answered 2021-Jun-11 at 03:24For a single remove you can use list.remove()
QUESTION
How to do that? i mean it is some kind of search on the matrix. I need to search search_matrix on main_matrix. Special rule is: if search_matrix is a included in beginning 4 elements of main_matrix then it can be a output. I mean if search_matrix is not in main_matrix's beginning (4 elements) it cannot be a in output_matrix. and element order is most important. elements must be in order.
...ANSWER
Answered 2021-Jun-10 at 09:59I don't know that it's a solution, but just to understand: Is this the result you're after?
QUESTION
ANSWER
Answered 2021-Jun-09 at 03:27If you know the index of an object in arr and you know it won't change then you can use index
to get the object and then destructure it
QUESTION
im webscraping and it seems that this site hides their images within the JS..
...ANSWER
Answered 2021-Jun-07 at 10:26You can use json
module to parse the data. For example:
QUESTION
I am trying to filter financial records on a MySQL table A based on mapping constraints stored on two separate tables B and C where: i. Table 1 has Budget and Expenditure amounts by Project Donors, Work Breakdown Structure IDs , and Year
...ANSWER
Answered 2021-Jun-02 at 05:08The logic of process is not described at all.
But, looking on column names and values I propose the next query:
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