quinoa | Adaptive computational fluid dynamics | Performance Testing library
kandi X-RAY | quinoa Summary
kandi X-RAY | quinoa Summary
Adaptive computational fluid dynamics - Quinoa is a set of computational tools that enables research and numerical analysis in fluid dynamics. Using the Charm++ runtime system, we employ asynchronous (or non-blocking) parallel programming and decompose computational problems into a large number of work units (that may be more than the available number of processors) enabling arbitrary overlap of parallel computation, communication, input, and output. Then the runtime system dynamically and automatically homogenizes computational load across the simulation distributed across many computers. Our ultimate goal is to simulate large and complex engineering multiphysics problems with a production-quality code that is extensible and maintainable, using hardware resources efficiently, even for problems with a priori unknown, heterogeneous, and dynamic load distribution. This software has been acknowledged by the U.S. Department of Energy / National Nuclear Security Administration for open source release, C20072. For more details on philosophy, documentation, software design, journal papers, license, and contributing see the documentation.
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QUESTION
By array intersection I mean, the inventory has a lot more elements than each document ingredients array, and the result I want to get from the query is all documents which all array elements are contained within the inventory. $all will get me zero results since the inventory has more elements than can be found in ingredients even if all ingredients are found within the inventory,
I have thousands of docs that have an array field of strings
...ANSWER
Answered 2021-May-29 at 06:48You can try aggregation operator in mquery using $expr
expression condition,
- first of all you can join the array of string by
|
order symbol and make a string, and use it in$regex
search, $filter
to iterate loop ofingredients
$regexMatch
to match element has any matching word$size
to get the total size of filtered elements$eq
to match filtered result and actualingredients
is equal
QUESTION
I need some help with the bootstrap accordion
I want to add the border-bottom-color: red
for the header of an item "Collapsible Group Item" div when it's open
and remove it when the div is closed
I am trying to add the class through Jquery and that class will have the border-bottom-color: red
CSS.
but it's not working, can someone tell me where I am wrong
Expected:
When the div is open the class will get add else it will get removed
Result of the code I have written:
The color is getting added to all the div at the same time irrespective of open div
ANSWER
Answered 2021-May-20 at 07:14If I understand you, you want to add a red border when the accordion is open?
Bootstrap already provides a class when it's open, so add styling when the class is NOT there.
QUESTION
I have a standard Bootstrap accordion and I don't want the option to have all cards closed at the same time, I have two total.
Right now... If I click on one, it opens and if I click on it again it closes. The first card starts open and I want it to automatically open the second one if I close the first and vice versa. This way one will always be open.
Here is my code, I appreciate your help.
...ANSWER
Answered 2021-May-02 at 14:25You can add click
event on button-link
. So , whenever your button is clicked check if it has collapsed
class or not depending on this get data-target
of another button and show that div using collapse('show')
.
Demo Code :
QUESTION
am looking to match everything before (and after) zero or more from a list of items. Here is what I am currently using: (?<=\))(.*)(?=(or|,|\())
In this case, I want to match everything after a closing parenthesis )
and everything before or
,
or )
. This works ok (probably not optimally), however, if there are none of the 3 items match, there are no matches.
For example, the sentence 2 cups (500 ml) mushroom, or vegetable broth
matches for mushroom,
however, 2 cups (500 ml) mushroom
doesn't match anything.
Basically, my goal is to find the ingredient from the ingredient + qty string, with the above sentence matching mushroom
and the sentence salt
matching the whole string salt
Here are more examples:
1 thyme sprig
should match thyme sprig
1 garlic clove, chopped
should match garlic clove
1 cup (180 g) quinoa, rinsed and drained
should match quinoa
2 tbsp (30 ml) olive oil, plus more for serving
should match olive oil
Vegan Parmesan, to taste
returns Vegan Parmesan
The difference between the first 2 and last 2 is tricky, as if there is a closing parenthesis (as in the last 2 examples), the ingredient should be after the closing parenthesis. If there are no closing parenthesis (as in the first 2 examples, everything after the number should be taken.
...ANSWER
Answered 2021-Mar-19 at 21:22Add |$
(end of string) to the ending group: (?<=\))(.*?)(?=(or|,|\(|$))
Edit: After testing here, I found you also need to make the main group non-greedy.
QUESTION
I created a macro to parse the "title" and "ingredients" of each recipe from three identical recipe links. This is the output.
If I run the macro for the second time and more, the data are overwritten. It should start writing data from the new row.
I could use lastrow logic to start writing data from the next available row but the problem is the data of the two rows are not of the same length which is why I get stuck.
...ANSWER
Answered 2021-Feb-04 at 09:22respect for a well formulated post ...
Firstly only write headers when cell A1 empty:
QUESTION
I am getting a TypeError in this code
...ANSWER
Answered 2021-Mar-05 at 09:23"the output of the API is dictionary inside a list"
quote from this, maybe you add a list in a list ?
after this code: all_orders.append(requests.get('API location next page').json())
, the all_orders
will have inner list.
maybe get the value by:
QUESTION
I Have a Bootstrap 4 accordion, I am very new to the Local Storage concept in Jquery, My codes are below for accordion. However, I wish to implement
- If the user is accessing the page for the first time- All accordions need the show class append so all accordion is open on page load.
- If the user is accessing the page again, the accordions should be closed on page load remove the show class
ANSWER
Answered 2021-Mar-01 at 15:12As per Using the Web Storage API you can test for a variable:
QUESTION
I have a basic bootstrap accordion like below.
I want to be able to style the .card-header
element of only the expanded .card
element without affecting the other .card-header
elements.
How do I select just the expanded item?
...ANSWER
Answered 2021-Feb-24 at 19:11There is no way in css to select the previous siblings. The only way left for you is to loop over all the buttons and add an event listener. On click on each link you check whether its collapsed or not. If its collapsed remove styles from its grand parent otherwise add desired styles to its grand parent.
QUESTION
Currently i am trying to get a feature which is i have a md-3 section and inside this section got a button and when clicking on the button, it generates more button and these button are draggable. When i click the button, i get a form on the md-9 and inside this form got toggable section and a save button there too. When i save on the particular sections, it displays on the md-3 section under the button.
But i have this issue where i want to make the sub section of the button to be draggable and deletable too.
Here is my code for: HTML:
...ANSWER
Answered 2021-Feb-22 at 03:03QUESTION
I have around 70 categories (it can be 20 or 30 also) and I want to be able to parallelize the process using ray but I get an error:
...ANSWER
Answered 2021-Feb-18 at 01:31This error is happening because of sending large objects to redis. merged_df
is a large dataframe and since you are calling get_meal_category
10 times, Ray will attempt to serialize merged_df
10 times. Instead if you put merged_df
into the Ray object store just once, and then pass along a reference to the object, this should work.
EDIT: Since the classifier is also large, do something similar for that as well.
Can you try something like this:
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