Competitive-Coding | algorithmic question of various online judges | Learning library

 by   saurabhjn76 C++ Version: Current License: MIT

kandi X-RAY | Competitive-Coding Summary

kandi X-RAY | Competitive-Coding Summary

Competitive-Coding is a C++ library typically used in Tutorial, Learning applications. Competitive-Coding has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A repository for my solutions to hackerrank problems(& CodeChef(Please feel free to contribute.
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              Competitive-Coding has a low active ecosystem.
              It has 27 star(s) with 9 fork(s). There are 2 watchers for this library.
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              It had no major release in the last 6 months.
              There are 0 open issues and 2 have been closed. On average issues are closed in 6 days. There are 4 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of Competitive-Coding is current.

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              Competitive-Coding has no bugs reported.

            kandi-Security Security

              Competitive-Coding has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              Competitive-Coding is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

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              Competitive-Coding releases are not available. You will need to build from source code and install.

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            Community Discussions

            QUESTION

            compute minimum clicks needed to perform in order to clear out a picture
            Asked 2019-Aug-18 at 09:34

            I have been trying to write a program for some question taken for competitive-coding of Cs-academy site.

            The question is as following:

            Suppose we were going through a bunch of black and white pictures and all of a sudden, a quirky idea struck to your mind – how many clicks does it take to convert all the white pixels into black and clear out a picture using brushes? So, we scanned and converted several pictures into binary data. Each pixel of the binary pictures are now represented by an integer, 0 for a black pixel and 1 for a white pixel.

            To modify a picture, we can only use one of the three brushes each time:

            +(plus) - When used, the pixels at the left, top, right and bottom of the current pixel are also colored in the same color.

            x(cross) - When used, the pixels at the top-left, top-right, bottom-right and bottom-left of the current pixel are also colored in the same color.

            *(star) - When used, all 9 pixels around the current pixel are also colored in the same color.

            (Here is an illustration:https://publicmedia1.csacademy.com/public/1507909042-2157482298.png)

            Each of these brushes, when used, works recursively. So if you color a pixel, its neighbors will get colored, then the neighbors of the neighbors, and so on.

            Our task is to compute the minimum clicks you will have to perform with each brush in order to clear out a picture: First we will have to compute the minimum clicks that are needed to clear the picture using only the + brush, then compute the minimum clicks that are needed to clear the picture using only the x brush and finally compute the minimum clicks that are needed to clear the picture using only the * brush.

            Input begins with a single number t (1≤t≤100) which denotes the number of pictures to process. Each test case begins with a line, which contains 2 space-separated integers w and h denoting the width and the height of the picture in pixels (1≤w,h≤1001). Following there will be h lines denoting the w pixel values (either 0 or 1) of each row of the picture.

            For each test case output, 3 space separated integers which denote the minimum number of clicks needed to clear out the picture for each of the three brushes: +, x and *.

            I wrote a program which calculates recursively - using separate functions - the count for each of 3 options:

            ...

            ANSWER

            Answered 2019-Aug-18 at 05:36

            You're not reading the input correctly.

            When you run cin>>mat1[i][j], since mat1[i][j] is an integer the entire line of input will be read in. So for the first (small) example, mat[0][0] will have the value 1011001 (one million, eleven thousand, and one). What you should be doing is reading the input matrix a character at a time, then storing an appropriate value in your matrices, taking care to handle the newline correctly (and checking for errors in the input).

            Another problem is that you don't output any spaces, so all three numbers run together to form one bigger number.

            Source https://stackoverflow.com/questions/57541827

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

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            Install Competitive-Coding

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            If you have a solution that's currently not included or solution in another language, please open an issue or pull request! If you're including new content, please make sure you have permission to publish the content you are adding. Also make sure that it is an accepted solution. ##Note: These codes are available for help only. Do not intend to copy codes, copy pasting code only spoils the point of the challenge since one don't get to learn anything. It's more rewarding when one find his own way through a challenge.
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