bfunc | Open Source , Breadboard-Friendly Function Generator Design | Generator Utils library
kandi X-RAY | bfunc Summary
kandi X-RAY | bfunc Summary
These are the source files for bfunc, a function generator I've been desiging, building, and programming in my spare time.
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QUESTION
In one of my projects, I'm getting the error "the associated constraints are not satisfied" for one of my C++20 concepts. It appears to me that my code is correct, so I must misunderstand something about the language.
I have rewritten the code to remove all of the obviously extraneous details.
Here are the include statements:
...ANSWER
Answered 2021-Oct-06 at 14:23template
requires requires (BLikeType t, Args... args) {
{t.Bfunc(c_->Cfunc(args...))};
}
std::array Afunc(Args... args) {
return c_->Cfunc(args...);
}
QUESTION
In this code sample, B extends A so a B-value can go into a A-variable. But, for some reason I don't understand, this is not true for function parameters :
...ANSWER
Answered 2021-Aug-27 at 16:09Because function type parameter positions are checked contravariantly, you can assign the other way around i.e. bGetter = aGetter works but not aGetter = bGetter. See playground.
QUESTION
Suppose I have two packages, foo and bar (and thus, foo.go, foo_test.go, bar.go, and bar_test.go.) bar depends on foo. In bar_test.go, I want to use some faked types that are defined in foo_test.go. But since it isn't allowed for *_test.go files to export types, I moved them into a test package for foo, ie footest, that both foo and bar depend on.
Suppose foo.go has some interfaces like this:
ANSWER
Answered 2021-May-03 at 03:37package foo will not depend on package footest as long as you use package foo_test in your foo_test.go file. In that case, foo_test will be compiled as a separate package. However, you won't have access to non-exported types in package foo.
e.g.
foo.go
QUESTION
Look at the pseudo-c++ code below:
...ANSWER
Answered 2021-Apr-01 at 15:29You can use std::get to fetch a value by its type from a tuple and std::tie to bundle your arguments into a tuple of references.
Obviously, this only works if your argument types are unique.
Make sure std::get uses a reference type to avoid unnecessary copies.
QUESTION
If I run the code below it acts as expected. (Expected being that both normal code languages AND JavaScript have "local scope" in functions) Thus the variable is not changed by the sub function.
...ANSWER
Answered 2021-Mar-22 at 20:17In the two loop examples you've shown, your variables are not formally declared, so they become global by default.
QUESTION
class a{
private:
class b* b = new b;
int getSomeWhatValue(){
}
};
class b{
private:
void bFunc(){
//I want to call an getsomewhatvalue() here
}
};
ANSWER
Answered 2020-Nov-25 at 07:38Your scenario will cause a cyclic calling (i.e. never ending loop of A creating an instance of B which in tern creates an instance of A and the loop continues), so its not permissible.
You have two options:
- Declare "int getSomeWhatValue()" as static, and call it through the class (instead through an instance).
- Pass a pointer to the function you want to call (int getSomeWhatValue()) and delcare the prototype somewhere outside of class A or B.
QUESTION
This question is a follow up question for the one in
Boost Spirit x3 conditional (ternary) operator parser
The original question context did not show (my bad!) the ast attributes and the answer therefore could not take all the moving parts into account. This question now shows how the ast attributes looks like and how the ast is used to evaluate the expression with a symbol table.
The follow up question is therefore that how the correctly spelled ternary conditional should change the ast types and how the conditional and expression interact together (according to my understanding it is now not part of the x3::variant as it is to be removed from primary parser choices)
Here is how the ast attributes and declared symbol definitions look like
...ANSWER
Answered 2020-Jan-21 at 16:52So, the top-level attribute exposed is expression, which is, frankly, not representing an expression at all.
Rather, it is representing an artificial unit of expression input syntax, which could perhaps be dubbed "operation_chain".
This is also going to make it hard to use your AST for semantically correct transformations (like e.g. expression evaluation) because crucial information like precedence of operations is not encoded in it.
In fact, if we're not careful it's very possible that this information - if present in the input - would be lost. I think it's possible in practice to go from your AST and reconstruct the operation tree with dependent operations in order of their precedence. But I usually err on the safe side of explicitly modeling the expression tree to reflect the operation dependencies.
That said, the conditional_op is not a chaining binary operation, so it doesn't fit the mold. I'd suggest making the "top level" rules expose an ast::operand instead (so it can fit the conditional_op or expression both just fine).
However, due the "lazy" way we detect the conditional, this requires some semantic actions to actually build the proper attributes:
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