crossbow | The minimalist feed aggregator

I've been learning Python off and on over the last 8 months. I understand the syntax for lists, tuples, sets and dictionaries. For fun I'm trying to create a character generator sheet for Dungeons and Dragons. I've got the program to randomly roll for my strength, charisma etc. Now I want to be able to ask the user, "What type of weapon do you want to use?" Get_Weapon_Choice, then pull up a list of that weapon type. I've tried creating a list weapon_Choices = ['Bow', 'Sword', ]. Then I created 2 other lists, bow = ['short', 'long', 'crossbow'] and swords = ['short', 'long'] I know how to get input from the user, but I don't know how to take that input and print the list, I'm printing the variable name.

chooseWeapon = input('What type of weapon would you like? Bow or Sword?')

How do I use chooseWeapon to compare to weapon_Choices to make sure they didn't enter something like Spells, then use chooseWeapon to print either the bow[] list or the swords[] list?

Do I need to use MySQL along with Python? and create tables and then search the tables instead of lists?

TIA! Don

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Short background:

I am editing a video game that has four factions. I want to make all the factions enemies but only the 'arch wand' and 'crossbow' are enemies. Here is the code defining the clans in the clan table:

Im trying to produce a very simple adventure text game and i tried to produce a minimal reproducible example in this case(my code may appear to be slightly long but i cant delete anymore or else it becomes difficult to understand).

The problem with my codes right now is that it wont proceed to go to the forest when the user is prompt to choose a choice = input("Go to the shop, go to the tavern, go to the forest: ").

And the other problem is that the user must enter tavern 2 times in order to proceed and after that it will show the error "dexterity not defined" at the line if dexterity >= 5: even though i have earlier listed it as part of the dictionary list...