RayMarching | Основной код с которым можно поиграться находится в
kandi X-RAY | RayMarching Summary
kandi X-RAY | RayMarching Summary
Основной код с которым можно поиграться находится в RayMarching.shader с 31 по 133 строки, все остальное - вспомогательное, чтобы шейдеры правильно работали с камерой Unity.
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Trending Discussions on RayMarching
QUESTION
I am adding a plane to the scene like this:
...ANSWER
Answered 2020-Sep-13 at 16:35You can easily achieve such a fullscreen effect by using the following setup:
QUESTION
I'm running into a bug with my shaders. For the vertex:
...ANSWER
Answered 2020-Jan-17 at 16:14The issue is caused, because (from OpenGL ES Shading Language 1.00 Specification - 4.3.5 Varying)
varying variables are set per vertex and are interpolated in a perspective-correct manner over the primitive being rendered.
To make your algorithm work, you have to interpolate the direction of the ray noperspective
.
Since GLSL ES 1.00 does not provide Interpolation qualifiers you have to find a workaround.
Compute the ray in the fragment shader:
QUESTION
I recently read this paper about raymarching clouds (careful it´s an PDF, in case you dont want that: http://www.diva-portal.org/smash/get/diva2:1223894/FULLTEXT01.pdf) where the author goes on about optimizing (page 22ff.) the algorithm via reprojection. He states that by raymarching only 1/16th of all pixels per frame (the selected pixel hopping around in a 4x4 grid) and reprojecting the rest, he got about 10 times a performance increase.
I now tried implementing this as well in Unreal Engine 4 (custom HLSL shader) and I got the raymarching as well as the reprojection working now. However I´m stuck at actually only running the raymarching on the necessary pixels. As far as I´m aware with any branching in HLSL both sides of the branch will be calculated and one will be thrown away. I therefore can´t do something like this pseudo code in the pixel shader: if(!PixelReprojection) { return 0;} else { return Raymarch(...); } as it will calculate the Raymarch even for pixels that are getting reprojected.
I don´t see any other way though to archieving this... Is there any kind of branching in HLSL that allows this? It can´t be static as the pixels subjected to raymarching and reprojecting change every frame. I´m really curious on any ideas how the author could have achieved this tenfold increase in performance as he is writing the code on a GPU too, as far as I´m aware.
I´d greatly appreciate any kind of input here.
Regards, foodius
...ANSWER
Answered 2019-Nov-16 at 04:06TLDR: use the attribute [branch]
in front of your if-statement.
As far as I´m aware with any branching in HLSL both sides of the branch will be calculated and one will be thrown away
This is actually not fully correct. Yes, a branch can be flattened, which means that both sides are calculated as you described, but it can also be not flattened (called dynamic branching).
Now, not flattening a branch has some disadvantages: If two threads in the same wave take different paths in the branch, a second wave has to be spawned, because all threads in a wave have to run the same code (so some threads would be moved to the newly spawned wave). Therefore, in such a case, a lot of threads are "disabled" (meaning they run the same code as the other threads in their wave, but not actually writing anything into memory). Nonetheless, this dynamic kind of branching may still be faster than running both sides of the branch, but this depends on the actual code.
One can even remove this disadvantes by smart shader design (namely, ensure that the threads that take one side of the branch are in the same wave, so no divergence happens inside a wave. This, however, requires some knowledge of the underlying hardware, like wave size and so on)
In any case: If not stated otherwise, the HLSL compiler decides on its own, whether a branch uses dynamic branching or is flattened. One can, however, enforce one of the two ways by adding an attribute to the if-statement, eg:
QUESTION
I'm trying to set up a pipeline to do some raymarching-rendering.
At first I set up a vertex and a geometry shader to take just 1 arbitrary float, and make a quad so I can use just the fragment shader, and input data via passing it through all shaders or uniforms.
But then I came across the compute shader, and found some tutorials but all just did nearly the same, making a quad and rendering compute-shaders output to it, I think that's pretty stupid, if you have the possibility to render how you want with the compute shader and still do tricks to get your result.
After some further research i found the function 'glFramebufferImage2D' and as far as I understood it, it attaches an ImageTexture (the one I wrote to with my compute shader in my case) to the Framebuffer (the buffer thats displayed as far as i understood it). So i dont have to do the quad generating trick. But the code I wrote just shows a black screen. Did i get something wrong? or did i missed something in my code?
This is my code: (I'm not worrying about warnings and detaching shader-programs yet. I just wanted to test the concept for now.)
main.rs
...ANSWER
Answered 2019-Sep-21 at 22:19There is an issue when you generate the texture. The initial value of TEXTURE_MIN_FILTER
is NEAREST_MIPMAP_LINEAR
. If you don't change it and you don't create mipmaps, then the texture is not "complete".
Set the TEXTURE_MIN_FILTER
to either NEAREST
or LINEAR
to solve the issue:
QUESTION
I'm working on a RayMarching Program(HomeWork) and I want it to go faster so I use the GPU with the ALEA extension. I have a problem because I can't Use The class camera In the parallel for (GPU). Thanks for your help.
I already tried to change the tag of the class and creating them inside the Parallel for
...ANSWER
Answered 2019-May-17 at 10:16You should set some variables to be the camera's variables and use them in the parallel for loop, you should also make static versions of the camera's functions and use them in the for loop. while I'm not sure this will fix it, it's something I think you should try because you said you can't use the class camera in the parallel for and now you won't be using it in there.
QUESTION
I'm raymarching Signed Distance Fields in CUDA and the scene I'm rendering contains thousands of spheres (spheres have their location stored in device buffer, so my SDF function iterates through all of the spheres for each pixel).
Currently, I'm computing distance to sphere surface as:
sqrtf( dot( pos - sphere_center, pos - sphere_center ) ) - sphere_radius
With the sqrt()
function, the rendering took about 250ms for my scene. However, when I removed the call to sqrt()
and left just dot( pos - sphere_center, pos - sphere_center ) - sphere_radius
, the rendering time dropped to 17ms (and rendering black image).
The sqrt()
function seems to be the bottleneck so I want to ask if there is a way I can improve my rendering time (either by using different formula that does not use square root or different rendering approach)?
I'm already using -use-fast-math
.
Edit: I've tried formula suggested by Nico Schertler, but it didn't work in my renderer. Link to M(n)WE on Shadertoy.
...ANSWER
Answered 2019-May-02 at 21:08(Making my comment into an answer since it seems to have worked for OP)
You're feeling the pain of having to compute sqrt()
. I sympathize... It would be great if you could just, umm, not do that. Well, what's stopping you? After all, the square-distance to a sphere is a monotone function from $R^+$ to $R^+$ - hell, it's actually a convex bijection! The problem is that you have non-squared distances coming from elsewhere, and you compute:
QUESTION
i' am implementing an algorithm of volume rendering "GPU ray casting single pass". For this, i used a float array of intensity values as 3d textures ( this 3d textures describes a regular 3d grid in spherical coordinates ).
Here there are example of array values:
...ANSWER
Answered 2019-Apr-13 at 16:32I do not know what and how are you rendering. There are many techniques and configurations which can achieve them. I am usually using a single pass single quad render covering the screen/view while geometry/scene is passed as texture. As you have your object in a 3D texture then I think you should go this way too. This is how its done (Assuming perspective, uniform spherical voxel grid as a 3D texture):
CPU side code
simply render single
QUAD
covering the scene/view. To make this more simple and precise I recommend you to use your sphere local coordinate system for camera matrix which is passed to the shaders (it will ease up the ray/sphere intersections computations a lot).Vertex
here you should cast/compute the ray position and direction for each vertex and pass it to the fragment so its interpolated for each pixel on the screen/view.
So the camera is described by its position (focal point) and view direction (usually Z- axis in perspective OpenGL). The ray is casted from the focal point
(0,0,0)
in camera local coordinates into theznear
plane(x,y,-znear)
also in camera local coordinates. Wherex,y
is the pixel screen position wit aspect ratio corrections applied if screen/view is not a square.So you just convert these two points into sphere local coordinates (still Cartesian).
The ray direction is just substraction of the two points...
Fragment
first normalize ray direction passed from vertex (as due to interpolation it will not be unit vector). After that simply test ray/sphere intersection for each radius of the sphere voxel grid from outward to inward so test spheres from
rmax
tormax/n
wherermax
is the max radius your 3D texture can have andn
is ids resolution for axis corresponding to radiusr
.On each hit convert the Cartesian intersection position to Spherical coordinates. Convert them to texture coordinates
s,t,p
and fetch the Voxel intensity and apply it to the color (how depends on what and how are you rendering).So if your texture coordinates are
(r,theta,phi)
assumingphi
is longitude and angles are normalized to<-Pi,Pi>
and<0,2*Pi>
andrmax
is the max radius of the 3D texture then:
QUESTION
I'm trying to mix raymarching and usual geometry rendering but I don't understand how to correctly compare the distance from the ray with the depth value I stored on my buffer.
On the raymarching side, I have rays starting from the eye (red dot). If you only render fragments at fixed ray distance 'T', you will see a curved line (in yellow on my drawing). I understand this because if you start from the ray origins Oa and Ob, and follow the direction Da and Db during T units (Oa + T * Da, and Ob + T * Db), you see that only the ray at the middle of the screen reaches the blue plane.
Now on the geometry side, I stored values directly from gl_FragCoord.z. But I don't understand why we don't see this curved effect there. I edited this picture in gimp, playing with 'posterize' feature to make it clear.
We see straight lines, not curved lines.
I am OK with converting this depth value to a distance (taking into account of the linearization). But then when comparing both distance I've got problems on the side of my screen.
There is one thing I missing with projection and how depth value are stored... I supposed depth value was the (remapped) distance from the near plane following the direction of rays starting from the eye.
EDIT: It seems writing this question helped me a bit. I see now why we don't see this the curve effect on depth buffer: because the distance between Near and Far is bigger for the ray on the side of my screen. Thus even if the depth values are the same (middle or side screen), the distances are not.
Thus it seems my problem come from the way I convert depth to distance. I used the following:
...ANSWER
Answered 2017-Aug-27 at 12:04You're overcomplicating the matter. There is no "curve effect" because a plane isn't curved. The term z
value litteraly describes what it is: the z coordinate in some euclidean coordinate space. And in such a space z=C
will form a parallel to the plane spanned by the xy
-Axes of that space, at distance C
.
So if you want the distance to some point, you need to take the x
and y
coordinates into account as well. In eye space, the camera is typically at the origin, so distance to the camera boils down to length(x_e, y_e, z_e)
(which is of course a non-linear operation which would create the "curve" you seem to expect).
QUESTION
I am playing around with webgl
copied from this page. I want to use mouse to control the light position.
If I just send the static value from js
to fragment shader
it will work:
ANSWER
Answered 2017-Oct-08 at 09:44Finaly decided to put this answer (edited).
As Gman commented, there is apprently nothing wrong with your code. Technically, this should work. However you pointed out a real tricky aspect of the WebGL/Javascript couple compared to OpenGL: The typage. And due to how Javascript variables works, you easily generate strange bugs.
Imagine this absurde situation:
QUESTION
I have a simple THREE.Scene where the main content is a THREE.Line mesh that visualizes the keyframe based path that the camera will follow for some scripted animation. There is then one THREE.SphereGeometry based mesh that is always repositioned to the current camera location.
The currently WRONG result looks like this (the fractal background is rendered independently but using the same keyframe input - and ultimately the idea is that the "camera path" visualization ends up in the same scale/projection as the respective fractal background...):
The base is an array of keyframes, each of which represents the modelViewMatrix for a specific camera position/orientation and is directly used to drive the vertexshader for the background, e.g.:
...ANSWER
Answered 2017-Mar-13 at 11:47Finally I have found one hack that works.
Actually the problem was made up of two parts:
1) Row- vs column-major order of modelViewMatrix: The order expected by the vertex shader is the oposite of what the remaining THREE.js expects..
2) Object3D-hierarchy: i.e. Scene, Mesh, Geometry, Line vertices + Camera: where to put the modelViewMatrix data so that it creates the desired result (i.e. the same result that the old bloody opengl application produced): I am not happy with the hack that I found here - but so far it is the only one that seems to work:
- I DO NOT touch the Camera.. it stays at 0/0/0
- I directly move all the vertices of my "line"-Geometry relative to the real camera position (see "position" from the modelViewMatrix)
- I then disable "matrixAutoUpdate" on the Mesh that contains my "line" Geometry and copy the modelViewMatrix (in which I first zeroed out the "position") into the "matrix" field.
BINGO.. then it works. (All of my attempts to achieve the same result by rotating/displacing the Camera or by displacing/rotating any of the Object3Ds involved have failed miserably..)
EDIT: I found a better way than updating the vertices and at least keeping all the manipulations on the Mesh level (I am still moving the world around - like the old OpenGL app would have done..). To get the right sequence of translation/rotation one can also use ("m" is still the original OpenGL modelViewMatrix - with 0/0/0 position info):
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