Glimpse | The open source diagnostics platform for the web
kandi X-RAY | Glimpse Summary
kandi X-RAY | Glimpse Summary
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Glimpse
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Glimpse Examples and Code Snippets
def extract_glimpse_v2(
input, # pylint: disable=redefined-builtin
size,
offsets,
centered=True,
normalized=True,
noise='uniform',
name=None):
"""Extracts a glimpse from the input tensor.
Returns a set of windows cal
def extract_glimpse(
input, # pylint: disable=redefined-builtin
size,
offsets,
centered=True,
normalized=True,
uniform_noise=True,
name=None):
"""Extracts a glimpse from the input tensor.
Returns a set of windows cal
Community Discussions
Trending Discussions on Glimpse
QUESTION
i've been writing wirting a program in Spring Boot Web with JPA and i'm using a query to access some data with a 'contains' and 'ignorecase' filter, i've done this before in other programs and it has worked fine, but now i'm getting this error, i'm completely lost at this point since i can't find anything in google, i went really far down the rabbit hole looking as to why it happens and so far i don't see anything out of place in my code, the type of variable declared seems to be okay but as i've said, i'm lost. It's important to mention that for some reason when I do the query on my website for the first time, everything works fine, i get the proper results and all, but when I go back to home and try with another query (or even the same) i get the error. Code below:
Model
...ANSWER
Answered 2022-Mar-28 at 15:19According to the Spring Data JPA issue #2472 this seems to be a problem in Hibernate 5.6.6 and 5.6.7.
The Hibernate bug is HHH-15142.
The solution is to either downgrade to Hibernate 5.6.5 or wait for a Hibernate patch to solve this issue.
QUESTION
I have POINT_X, POINT_Y, and a z-point column in a .csv file that I'm trying to reproject in R. Originally, it was projected in the EPSG:26777 reference system, but I'm trying to project it back to WGS 84. However, when I import the .csv file into R and try the conversion, it does not change the point values in my "geometry" column. How can I change them to latitude and longitude coordinates?
Here is the data, exported in the original projection:
...ANSWER
Answered 2022-Mar-24 at 21:37To transform the data to lat/lon, first you need to load it with the original crs value.
QUESTION
I am trying to download a BigQuery data set from Google Cloud Platform into R workspace in order to analyze it, using the following code:
...ANSWER
Answered 2022-Mar-17 at 10:12As per documentation link about rateLimitExceeded, it looks like you break the threshold of query jobs.
Please consider the following:
Check if your project
bigquery api
have setup limits and quotas that you might be breaking when performing the operation. To see your current quotas and limits please go to IAM & Admin > Quotas > Quotas for project "projectid" > bigquery.google.apis.comAs your chunks are about
55,308 rows
per chunk of58,882,407 rows
it appears you are trying to download way more data that it allows and you might be hitting the following limits:Query/script execution-time limit
,Maximum response size
,Maximum row size
.Verify if table constraints are not reached. Specially the one about
operations per day
.Check the amount of columns you row have. There is a limit of 10,000 columns.
Consider checking all the rest of quota limits specified on query jobs.
Reducing the scope of your select or reduce the size of your chunks. Million records tables of everything its truly needed?. You can perform something like this:
QUESTION
I am a bit new to R and trying to learn the basics.
I have run into a bit of a problem trying to convert one of my columns into seconds for analysis.
When I try to convert ride_length to numeric it is saying "NAs introduced by coercion" and I cannot seem to change this from character. I am sure there is a way to calculate the travel time using the started_at / ended_at but thought it would be easier to use the ride_length column instead.
...ANSWER
Answered 2022-Mar-15 at 21:51If I understand your requirement, I think this should work:
QUESTION
I want to change values in my username
variable but only when they meet a condition set from the variable chatforum
. For example, I want all instances of users called "Alex" from Canadian chatrooms to be relabeled as "AlexCA":
ANSWER
Answered 2022-Mar-13 at 00:51For using case_when
or ifelse
, you can have multiple conditions that must be met in order to the apply the change. So, if chatforum == "Canada" & username == "Alex"
, then we change the name to AlexCA
.
QUESTION
With Pandas in Python there is the describe() function that returns the summary statistics for a dataframe. The output is not in a 'tidy' format for simple manipulation with the tidyverse summarise function but it is in a nice format for presentation. My question is how to reproduce this output in R?
...ANSWER
Answered 2022-Mar-12 at 07:11You can combine do.call()
with rind()
and lapply()
to get a tidy format of summary()
. t()
transpose the output.
QUESTION
Via this post I discovered the fascinating list2env()
function in conjunction with dplyr
lists, allowing the user to move the contents of a named list out into the global environment. However I have run into some problems, best illustrated by the example below.
Say we have a list of datasets
...ANSWER
Answered 2022-Mar-01 at 22:04I think the issue is that your list of dataframes 'lost' their names after applying your renaming function; if you reassign the names your function works, e.g.
QUESTION
I am a complete beginner in R and right now I am learning to use the fundamentals. I was wondering what the function of double quotes ("") is in R: when do you have to use it and when not? For example: when use library() you need them, however when using a function such as glimpse() to quickly explore a dataset, the double qoutes ("") actually interfere with the function of glimpse(); you do not see the dataset when include double qoutes.
TLDR: I do not know what double qoutes ("") actually do in R and I cannot find a beginner level explanation for it other than "it creates a string".
Thanks in advance!
...ANSWER
Answered 2022-Feb-21 at 12:09Well, its a bit complicated, but the simplest answer is that it is typically used to denote a character (letters, etc.) versus numeric values. For example, I would code this object without quotes:
QUESTION
I saw an interesting navigation list example as below (css omitted),
...ANSWER
Answered 2022-Jan-26 at 04:57There is no reason for it and can be removed as they are normally just basic HTML comments. They provide no usefulness to the code
as for the formatting difference, you will need to better style them, that's all.
QUESTION
This question was asked in an company coding round which unfortunately I was unable to solve, I am getting the glimpse that this question is based on greedy but cannot proceed further, anyone who has solution or algorithm please share it with me.
Problem Statement:
Mustafa wants to cross a dungeon. The dungeon has N cells, and in every cell, there are M monsters. To cross each cell he has to kill one monster, on killing the monster, he loses the strength equal to that of the monster and gains some confidence which adds up to his strength and he proceeds to the next cell. Mustafa can only kill a monster if his strength is greater than or equal to the strength of the monster. Help him find the minimum strength he must have in the beginning so that he can cross N cells.
Input format:
- First two integers are
N
andM
. N X M
matrix that represents energy required to kill monster in each cell.N X M
matrix that represents confidence gain by killing respective monsters.
Testcase:
Input:
...ANSWER
Answered 2022-Jan-06 at 14:46Let us call Energy[N][M])
the energy needed to kill each monster, and Conf[N][M]
the associated confidence.
Let us call Stren[N]
the minimum energy that you will need to pass each cell.
We need to select the good monster at each step. The issue is that at first cell for example, you cannot make the good decision without considering all the next cells. A DP solution or a DFS one will certainly work. However, the complexity would be quite high.
The hint to use a greedy solution is correct, at the condition to start from the end.
At the last cell, the needed strength is easily calculated:
Strength[n-1] = min_i Energy[n-1][i]
The next strengths are then iteratively calculated, from back to the top:
Strength[j] = min_i (Energy[j][i], Energy[j][i] - Conf[j][i] + Strength[j+1])
For all j
Final result: Strength[0]
Complexity: linear O(NM). Impossible to do better as you have to consider each monster.
Some further explanations
Performing an iteration in reverse order is a classical trick, when you know the starting value, here Strength[N-1]
.
The key point is the recursive formula:
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