# NLog | NLog - Advanced and Structured Logging for Various NET Platforms

## kandi X-RAY | NLog Summary

## kandi X-RAY | NLog Summary

NLog consists of multiple packages. Most of the functionality is inside the NLog (core) package. What's inside the packages? See targets and layout renderers overview!.

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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of NLog

## NLog Key Features

## NLog Examples and Code Snippets

## Community Discussions

Trending Discussions on NLog

QUESTION

Am not experienced in `C`

stacks, but am trying to build this DICOM project, it seems it's depending on a 'no-longer' existing project, so I tried to compile mdcm instead to generate the DLLs.

the generated dlls produce `DICOM`

and `Nlog`

, NLog didn't seem to work with the target project, missing classes etc ... when I installed `Nlog version 1.0`

using `Nuget package manager`

the missing classes issues got solved but now I get the below error message.

what are possible solution to this ?

...ANSWER

Answered 2022-Feb-25 at 14:13It means a dependency references a version of a package that is greater than the one you have installed into your app but your app reference will "win" since it is a direct reference, hence the error.

To fix it, you should install/upgrade to version 2 of NLog directly into your app although there might be build/runtime issues with that depending on the changes made in v2.

QUESTION

When I include `NLog.LogManager.GetCurrentClassLogger()`

at the top of my F# modules, the name of the logger looks something like `.$Program`

. I would have hoped for something like `NLogTest.TestModule`

.

**How can I get a better logger name for my F# modules?**

Here is a complete example:

`Program.fs`

ANSWER

Answered 2022-Feb-09 at 00:40Here are several options:

**Create the logger inside every module function**

QUESTION

```
# find all possible sorted substrings of s
substr = ["".join(sorted(s[i: j]))
for i in range(len(s))
for j in range(i + 1, len(s) + 1)]
```

...ANSWER

Answered 2021-Dec-29 at 17:59In this expression:

QUESTION

I installed Nlog from NuGet and tried to make some changes at NLog config. Unfortunately, that file is marked by a padlock. Also it is placed out of the project catalogue (C:\Users\username\.nuget\packages\nlog.config\4.7.13\contentFiles\any\any\NLog.config) and read-only. How should I correctly add that file to the project? Should I copy that and add it manually to the project?

...ANSWER

Answered 2021-Dec-13 at 22:27The nlog config file should be carefully located so your resulting build project files load it correctly. In the documentation about the File Location info you see where the programs looks for the Nlog config file.

You can indeed include it in your project and set the property `Copy to Output directory`

to `Copy if newer`

QUESTION

I have been looking at logging options and settled on NLog and logging to a database

I am fairly new to functional programming and have come from a background in C# OOP.

How would I implement logging in a functional way in F#?

Do I

- Create the logger at the top level and just pass it in to every function as I go
- Access the logger through a static method as needed ( obviously there would be some overhead to instantiating a logger each time - but maybe that's not a big deal )
- Something else?

I want to avoid using a commercial logging option just because my projects are quite small.

Thanks for your time.

...ANSWER

Answered 2021-Nov-20 at 00:43As logging is inherently impure there isn't a particularly clean way to do logging that I'm aware of. You have basically identified the two solutions in your question. Which one you use depends on what the logs are being used for.

For logging to external services I would consider creating an `AppContext`

type which is home to app and user settings as well as providing functions or methods for logging to e.g. a database. This type should be added an extra parameter in your functions or an additional field in your types depending on what makes the most sense.

For your lowest-level functions rather than changing them all to accept an additional parameter you should consider altering the return type to include the information you want to log and leaving the act of logging to higher level parts of your program.

For logging to a console, rolling buffer, or other temporary location I think it is fine to create a `module`

which is equivalent to a C# static class and just provide globally accessible logging functions.

QUESTION

Given an array of size n and k, how do you find the mode for every contiguous subarray of size k?

For example

...ANSWER

Answered 2021-Nov-15 at 18:30I was intrigued by this problem in part because, as I indicated in the comments, I felt certain that it could be done in `O(n)`

time. I had some time over this past weekend, so I wrote up my solution to this problem.

This means that whenever you add a number to the collection, if the number added was not already one of the mode-values then the frequency of the mode would not change. So with the collection `(8 9 9)`

the mode-values are `{9}`

and the mode-frequency is `2`

. If you add say a `5`

to this collection (`(8 9 9 5)`

) neither the mode-frequency nor the mode-values change. If instead you add an `8`

to the collection (`(8 9 9 8)`

) then the mode-values change to `{9, 8}`

but the mode-frequency is still unchanged at `2`

. Finally, if you instead added a `9`

to the collection (`(8 9 9 9)`

), now the mode-frequency goes up by one.

Thus in all cases when you *add* a single number to the collection, the mode-frequency is either unchanged or goes up by only one. Likewise, when you *remove* a single number from the collection, the mode-frequency is either unchanged or goes down by at most one. So all incremental changes to the collection result in only two possible new mode-frequencies. This means that if we had all of the distinct numbers of the collection indexed by their frequencies, then we could always find the new Mode in a constant amount of time (i.e., `O(1)`

).

To accomplish this I use a custom data structure ("ModeTracker") that has a multiset ("numFreqs") to store the distinct numbers of the collection along with their current frequency in the collection. This is implemented with a Dictionary (I think that this is a Map in Java). Thus given a number, we can use this to find its current frequency within the collection in O(1).

This data structure also has an array of sets ("freqNums") that given a specific frequency will return all of the numbers that have that frequency in the current collection.

I have included the code for this data structure class below. Not that this is implemented in C# as I do not know Java well enough to implement it there, but I believe that a Java programmer should have no trouble translating it.

(pseudo)Code: class ModeTracker { HashSet[] freqNums; //numbers at each frequency Dictionary numFreqs; //frequencies for each number int modeFreq_ = 0; //frequency of the current modeQUESTION

Imagine there's have an array of integers but you aren't allowed to access any of the values (so no `Arr[i] > Arr[i+1]`

or whatever). The only way to discern the integers from one another is by using a **query()** function: this function takes a subset of elements as inputs and returns the number of unique integers in this subset. The goal is to partition the integers into groups based on their values — integers in the same group should have the same value, while integers in different groups have different values.
The catch - the code has to be O(nlog(n)), or in other words the query() function can only be called O(nlog(n)) times.

I've spent hours optimizing different algorithms in Python, but all of them have been O(n^2). For reference, here's the code I start out with:

...ANSWER

Answered 2021-Nov-04 at 14:49Let's say you have an element `x`

and an array of distinct elements, `A = [x0, x1, ..., x_{k-1}]`

and want to know if the `x`

is equivalent to some element in the array and if yes, to which element.

What you can do is a simple recursion (let's call it `check-eq`

):

- Check if
`query([x, A]) == k + 1`

. If yes, then you know that`x`

is distinct from every element in`A`

. - Otherwise, you know that
`x`

is equivalent to some element of`A`

. Let`A1 = A[:k/2], A2 = A[k/2+1:]`

. If`query([x, A1]) == len(A1)`

, then you know that`x`

is equivalent to some element in`A1`

, so recurse in`A1`

. Otherwise recurse in`A2`

.

This recursion takes at most `O(logk)`

steps. Now, let our initial array be `T = [x0, x1, ..., x_{n-1}]`

. `A`

will be an array of "representative" of the groups of elements. What you do is first take `A = [x0]`

and `x = x1`

. Now use `check-eq`

to see if `x1`

is in the same group as `x0`

. If no, then let `A = [x0, x1]`

. Otherwise do nothing. Proceed with `x = x2`

. You can see how it goes.

Complexity is of course `O(nlogn)`

, because `check-eq`

is called exactly `n-1`

times and each call take `O(logn)`

time.

QUESTION

given an array `nums`

of integers with length `n`

, for each index `i`

, I am trying to find the rightmost index `j`

such that `i < j`

and `nums[j] >= nums[i]`

. Is there an O(N) solution for this problem? I am aware of **monotonic stack** which could be used for this kind of problems, but unable to derive an algorithm.

For example, given an array A:
` A = [9,8,1,0,1,9,4,0,4,1]`

, the solution should output
` [5,5,9,9,9,-1,8,9,-1,-1]`

. Here `-1`

indicates no indices satisfy the constraint.

This link asked the same question, and the accepted answer is only for O(NlogN). I'd like to know whether an O(N) solution is possible.

Thank you.

**Update**

Based on @Aivean's answer, here is an **O(Nlog(N))** solution in python.

ANSWER

Answered 2021-Oct-28 at 20:03There is not going to be an O(N) algorithm for the problem as written. Given a function that solves this problem, you could use it to partition N/2 arbitrary numbers into N/2 arbitrary adjacent ranges.

For example [2532,1463,3264,200,4000,3000,2000,1000] produces [5,6,4,7,-1,-1,-1,-1], identifying the ranges of the first N/2 numbers.

If you can only relate the numbers by comparison, then this will take you N/2 * log(N/2) comparisons, so O(N log N) time.

Without a limit on the size of the numbers, which would let you cheat like a radix sort, there isn't going to be way that is asymptotically faster than all comparison-based methods.

QUESTION

```
arr.sort((a, b) => a - b).map(num => num ** 2);
```

...ANSWER

Answered 2021-Oct-28 at 17:16The complexity of your function `f`

, for `arr`

of size `n`

. We'll assume:

QUESTION

Hello I am working on a problem that seems to be out of my league so any tips, pointers to reading materials etc. are really appreciated. That being said here is the problem:

given 3 subsets of numbers a, b, c ⊆ {0, ..., n}. In nlog(n) check if there exists numbers n1, n2 in a, b and n3 in c where n1 + n2 = n3.

I am given the hint to convert a and b to polynomial coefficients and to use polynomial multiplication using ftt to multiply the coefficients of a and b.

Now where I am stuck is after getting the result of the polynomial multiplication, what do I do next?

Thank you in advanced.

...ANSWER

Answered 2021-Oct-17 at 04:03Thanks to all who helped. I figured it out and hopefully this can help anyone who runs into a similar problem. The issue I had was I incorrectly assigned the coefficients for `a_coeffs`

and `b_coeffs`

.

Here is the solution which passed the tests for those interested.

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

## Vulnerabilities

No vulnerabilities reported

## Install NLog

.NET Framework

ASP.NET Core

.NET Core Console

Use Visual Studio 2019 and open the solution 'NLog.sln'.

AppVeyor for Windows builds, including Silverlight and Xamarin.

SonarQube for code coverage

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