oslo | A simple Visual Studio Code Theme creator
kandi X-RAY | oslo Summary
kandi X-RAY | oslo Summary
Currently, it's under GPL 3.0 license, but I'm not sure if a BDL license is better.
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QUESTION
I have a dataframe that looks like that :
...ANSWER
Answered 2022-Apr-12 at 07:26IUUC, you could reshape the data, then compute the percent per group, finally reshape again:
QUESTION
I am having trouble with something i thought it will be simple.
I have an array of nested arrays with strings.
...ANSWER
Answered 2022-Apr-11 at 10:20Object should contain key: value pair
If you want to convert each string element into an object element. Then you can do something like this :
QUESTION
I encountered this problem while trying to arrange for total_number of boys and girls, but there was top places for boys that were not in the top 20 for girls. The visualization did not show an even representation of the sample because the top places of the girls are not the top places of the boys and vice versa (though they do visit similar places, just not in vast numbers).
place Category2 total_number Andorra la Vella boy 66394 Yerevan boy 33539 Vienna boy 29757 Baku girl 24615 Minsk girl 23847 Brussels girl 23691 Sarajevo boy 23285 Sofia boy 21309 Oslo girl 20982 Zagreb boy 19885I have arranged by the total_number descending, used head(20) and attempted to plot it. This did not look good because of empty spaces and out of order with respect to the boys and girls (category 2). I want to arrange for the top 20 of the data set, but I want the arrangement of total_number to alternate between girls and boys of Category2 to show an equal representation and no blanks in the top 20 of the visualization. How do I do this?
...ANSWER
Answered 2022-Apr-03 at 21:21If I understood you correctly one way to go about this is setting the scales argument inside the facet_wrap to "free" and order places according to the total_number (I used the - to invert increasing order):
QUESTION
Basically I have a table called cities
which looks like this:
ANSWER
Answered 2022-Mar-25 at 13:59You need to UNION ALL the total sum.
WITH ROLLUP works by summing up the total for every group separate and can't be used here.
QUESTION
I have a 2 tables and one view which I want to find which pairs are duplicate:
...ANSWER
Answered 2022-Mar-09 at 21:11Use INNER JOIN
, it will return the matching records :
QUESTION
I would like to add a suffix to strings in one column when a condition is met in another column. If a value is present in "Market" column, "Symbol" column corresponding value is updated to include current ticker but I would like to add a suffix to it representing its market place. I guess I could create multiple masks and change multiple values with multiple lines of codes for each value but I was wondering if there exist a more elegant way of doing this in one operation.
This is what I tried :
conditions = [ (df['Market'].str.contains("Oslo")), (df['Market'].str.contains("Paris")), (df['Market'].str.contains("Amsterdam")), (df['Market'].str.contains("Brussels")), (df['Market'].str.contains("Dublin")) ] values = [str+'.OL', str+'.PA', str+'.AS', str+'.BR', str+'.IR'] df['Symbol'] = np.select(conditions, values) print(df)
I get an error :
unsupported operand type(s) for +: 'type' and 'str'
any help welcome
added after KingOtto's answer...
the data frame :
ANSWER
Answered 2022-Feb-16 at 12:25You need to proceed in 3 steps
You need to define an exhaustive suffix_list - a dictionary that holds information only once for each market
suffix_list = pd.DataFrame({'Market': ['Oslo', 'Paris'], 'suffix':['OL','PA']})
You want to merge the
suffix_list
into your existing dataframe as a new column - one command for all markets (for each market that has a suffix in the list, you add that suffix):pd.merge(df, suffix_list, how='left', on='Market')
Now that you have the 2 columns
'value'
and'suffix'
next to each other for all rows, you can apply 1 single operation for all rowsstr('value')+'suffix'
QUESTION
I have these 2 tables which I would like to query:
...ANSWER
Answered 2022-Feb-23 at 10:35Use array_agg() for adding multiple exchange_id with unique pair. Use distinct keyword inside array_agg() for removing duplicate exchange_id. When passing specific input then enable WHERE clause otherwise disable it. If single exchange_id then comment exchange_id column in select clause.
QUESTION
I would like to get results from the fields (path) in table URL where the last directory in the path field from URL table contains at least two matching words from the same row in the Locations table.
Table URL
...ANSWER
Answered 2022-Feb-22 at 17:17What is wrong here?
QUESTION
I would like to create a func that gets several pandas columns and make extra string manipulation to create another column. The string maipulatioins has to be dependent on some other string constants that are sent to the function.
...ANSWER
Answered 2022-Feb-14 at 22:41IIUC:
QUESTION
I'm modifying a CSS template based on bootstrap, in order to obtain a responsive simple website.
The page provides a list of events. Since show_date
and show_shop
have fixed width, when the website is opened on a smartphone (smaller screen) the class flex-row
allows the show_name
and show_location
to be disposed in column to save space.
The problem is that when the text in show_name
and show_location
is too long, the text wrap out of the box in vertical.
How can I force the text in show_name
and show_location
to use only a single line (one for each one), truncating the text with ...
?
I tried overflow: hidden
with text-overflow: ellipsis
but it doesn't work (I think due to the flex width of the div).
Thanks for help.
...ANSWER
Answered 2022-Jan-28 at 21:12You could simply use the text-nowrap
class on those divs and use spans inside. I've also removed some redundant div elements and combined classes.
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