8x8 | Direct drive LED 8x8 matrix for Arduino
kandi X-RAY | 8x8 Summary
kandi X-RAY | 8x8 Summary
Direct drive LED 8x8 matrix for Arduino
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of 8x8
8x8 Key Features
8x8 Examples and Code Snippets
Community Discussions
Trending Discussions on 8x8
QUESTION
I would like to use the following heatmap generated with Python:
...ANSWER
Answered 2022-Mar-04 at 13:30You can set font size (and rotation) of the tick labels on the axes -- for particular subplots.
The general way to do that is:
QUESTION
I posted a similar question to this one a few weeks ago where I had trouble finding the data race in my N-queens program using pthreads in C. Why is my multithreaded C program not working on macOS, but completely fine on Linux?
I got a few suggestions in the comments sections of the post and I really tried my best to make corrections based on them. I sat with the suggestions a few days, changed some parts but the data race persisted and I just cannot understand why. There are counters inside critical sections for the number of productions and consumptions. I feel completely blind when looking through the code and analyzing it, I'm aware that consumptions are too many but the synchronization around that code fragment should with my knowledge be correct, but obviously something's not right. External input would be greatly appreciated.
This is the code I'm using and I'm not sure how to reduce its size to still reproduce the issue. I compile it with gcc (clang-1205.0.22.11) on macOS Monterey (12.1) using a MacBook Pro 2020 x86_64 architecture.
compile: gcc -o 8q 8q.c*
run: ./8q
, NxN chess board, N queens to place
parameters: ./8q 2 4
Enough to highlight the problem (should yield 2 solutions, but every other run yields 3+ solutions, i.e duplicate solutions exist
note: running the program with ./8q 2 4
should give 2 solutions, 1820 productions and 1820 consumptions.
ANSWER
Answered 2022-Feb-16 at 03:21You're not initializing your mutexes and condition variables. The result is UB when used in pthread APIs. Two ways to do this, the simplest is just use the proper initializer:
QUESTION
I converted an avi file to a mp4 file with the following command, but the converted mp4 file produced no audio when played with QuickTime (no such problem with other players). I was able to convert mkv to mp4 with the same command without the audio problem.
...ANSWER
Answered 2022-Feb-06 at 19:04From your log I can see that your input audio is MP3.
QUESTION
I am using a for loop to populate an 8x8 grid with two different buttons randomly. I have an array of instances of the buttons and for some reason, it is only giving me one of each button and not populating the rest of the grid with anything. Any advice? I included only the buildPanel block of the code but I do have separate classes for the buttons and the Game class. I also have the rest of the code somewhat done. It doesn't fully do what I need yet and needs to be cleaned up but if it might be helpful in solving this issue, I can post it. I'm unable to post more code than this in the question without writing more details but it's pretty straightforward of a question I think.
...ANSWER
Answered 2021-Dec-04 at 15:57it is only giving me one of each button
Because you only have a single instance of each button:
QUESTION
I'm trying to initialize an "empty" array with each elements containing t_list
a 8x8 np.zeros array :
t_list = np.zeros((8,8), dtype=np.float32)
I would now want to have a np.array
with multiple t_list at each indexes:
result = np.array((t_list, t_list, ...., tlist))
I would like to be able to control the number of time t_list
is in result
.
I know that I could use list instead of arrays. The problem is, I put this in a numba njit function so I need to precise everything.
The aim is then to change each values in a double for
loop.
ANSWER
Answered 2021-Dec-04 at 06:54The shape
param of numpy.zeros
can be a tuple of ints of any length, so you can create an ndarray
with multiple dimensions.
e.g.:
QUESTION
I am trying to figure out the layout for this(the rest of the code is in the early stages) but for this block, I am trying to figure out the best(and doable) way to format it. I want it to be an 8x8 grid that I will eventually populate with the treasure/empty buttons but I also need a title up top as well as some labels and text on the left. I am unsure if I am able to do multiple grids but what I did below is try to create a 1x2 grid and then place two other grids inside, one with the info on the left(3x2), and another with the 8x8 grid for the buttons. I know it's not close to what it needs to be but none of the grids are showing up at all(it's just putting the title and then one column with 8 rows) and I wanna know if I'm even on any sort of right track, or if I'm just making things up at this point. Any tips would be appreciated, or resources about possibly nesting the grids? I can't find anything in my book about That specifically.
...ANSWER
Answered 2021-Dec-03 at 10:30You can't use multiple grids within the same JPanel
- one panel, one layout manager.
But you can nest layout managers (and thereby grids) by using nested panels.
For example you could use a BorderLayout
for the first panel (containing the title at the top, the info panel on the left and the button panel in the center.
The code to construct those panel then might look like this:
QUESTION
I use this reverse-bit method of iteration for rendering tasks in one dimension, the goal being to iterate through an array with the bits of the iterator reversed so that instead of computing an array slowly from left to right the order is spread out. I use this for instance when rendering the graph of a 1D function, because this reversed bit iteration first computes values at well-spaced intervals a representative image appears only after a very small fraction of all the values are computed.
So after only a partial rendering we already have a good idea of how the final graph will look. Now I want to apply the same principle to 2D rendering, think raytracing and such, the idea is having a good overall view of the image being rendered even from an early stage. The problem is that making the same idea work as a 2D iteration isn't trivial.
Here's how I do it in 1D:
...ANSWER
Answered 2021-Nov-07 at 14:17Reversing the bits achieves the expected effect in 1D, you could combine this shuffling technique with another one where you get the x and y coordinates be selecting the even, resp. odd, bits of the resulting number. Combining both methods in a single shuffle is highly desirable to avoid costly bit twiddling operations.
You could also use Gray Codes to shuffle values with n significant bits into a pseudo random order. Here is a trivial function to produce gray codes:
QUESTION
Here is an 8x8 table of 64 cells, each containing a number
...ANSWER
Answered 2021-Oct-24 at 20:21You could calculate the index of 2x2 parts.
QUESTION
I'm hoping to speed up this matrix-vector product using AVX-1 or earlier instructions:
...ANSWER
Answered 2021-Sep-29 at 14:14I'd go with the interleaving approach suggested by chtz.
Read 32 or 64 bytes (aka a full cache line) from two rows, then interleave.
32 bytes at least, as the width of each row % 32 == 0, and preferably 64 bytes, as that is a full cache line and it would take 8 accumulators out of 16 registers.
Also I would guess that processing the input as blocks of (8, 16, or 32 rows) by (32 or 64 columns) would be better than processing all the rows; the more rows you process, the less you need to spill the accumulators to memory, with more rows processed in non-linear order the higher the probability of evicting soon to be needed lines from cache. 4 rows should be definitively on safe side.
Interleaving b
is quite naturally done by
QUESTION
I want help in maxpooling using numpy
.
I am learning Python for data science, here I have to do maxpooling and average pooling for 2x2
matrix, the input can be 8x8
or more but I have to do maxpool for every 2x2
matrix. I have created an matrix by using
ANSWER
Answered 2021-Sep-25 at 10:21You can solve the convolution part using np.lib.stride_tricks
which is actually how the numpy generates views from its methods in the background. Be careful though, this is memory level access to numpy arrays.
- Convolve over the (8,8) matrix to get (4,4) matrices of (2,2) shape.
- Reduce the (2,2) matrics with a pooling operation such as mean to get a (4,4) output.
This approach is scalable to larger matrices without any modification and can accommodate larger convolutions as well.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install 8x8
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page