alice | Painless middleware chaining for Go | Runtime Evironment library

Because your $i is only visible to bash, not awk. You need to pass it into your awk script as:

If you were using BigQuery, then the logic would look like:

1. The names of constants look like the names of local variables, except that they begin with a capital letter.

2. All the built-in classes, along with the classes you define, have a corresponding global constant with the same name as the class called class name.

So in your case, when you define User class, there's a constant class name: User, but not user, that why the error NameError (wrong constant name user) is raised.

try text_post = TextPost.create(title: 'foo', content: 'lorem ipsum', author_id: 1, author_type: 'User')

The error message explicitly tells you that the key that fails doesn't describe itself as suitable for encrypted storage or communications.

Per the signature subpacket specification, we know that this information lives in a subpacket of type 27.

Per the detailed specification on that subpacket, we know that the desired flags are 0x04 and 0x08, respectively.

To compare these keys, you can use gpg --list-packets --verbose.

For the first, non-working key, we get:

The reason here is that you're constructing a public/private key pair in both applications.

Essentially you're trying to encrypt something with Bob's public key, and trying to decrypt that with Alice's private key. This won't work.

You need to construct 1 pair, and then use the public key from that pair for the encryption, and the private key from the same pair for the decryption.

This works:

The comparator of std::lower_bound is supposed to take the object dereferenced from the iterator, i.e. the element as the 1st parameter, the value to be compared as the 2nd parameter.

The type Type1 must be such that an object of type ForwardIt can be dereferenced and then implicitly converted to Type1. The type Type2 must be such that an object of type T can be implicitly converted to Type2.​

You need to change the order of the parameters, e.g.

You already have your JSON data in a string, so you need to parse it into a JavaScript object (an array in your case):

The reason for the difference has two parts, both of them defined in GroupAggFunction, which is the process function used to process this query.

The first is this part of the code:

If you only have two pieces of information (name and total), I would suggest changing your schema a bit. Instead of a list of dictionaries, use a single dictionary where the keys are names and the values are totals: