ifconfig | Yet Another ifconfig inspired by ifconfig.me | Frontend Framework library

 by   missdeer Go Version: 1.0 License: GPL-3.0

kandi X-RAY | ifconfig Summary

kandi X-RAY | ifconfig Summary

ifconfig is a Go library typically used in User Interface, Frontend Framework, React applications. ifconfig has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

Yet Another ifconfig inspired by the online demo is [
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            kandi-support Support

              ifconfig has a low active ecosystem.
              It has 26 star(s) with 12 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 0 open issues and 1 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of ifconfig is 1.0

            kandi-Quality Quality

              ifconfig has no bugs reported.

            kandi-Security Security

              ifconfig has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              ifconfig is licensed under the GPL-3.0 License. This license is Strong Copyleft.
              Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

            kandi-Reuse Reuse

              ifconfig releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed ifconfig and discovered the below as its top functions. This is intended to give you an instant insight into ifconfig implemented functionality, and help decide if they suit your requirements.
            • Get the page data
            • Initialize the main controller
            • Run the process
            Get all kandi verified functions for this library.

            ifconfig Key Features

            No Key Features are available at this moment for ifconfig.

            ifconfig Examples and Code Snippets

            No Code Snippets are available at this moment for ifconfig.

            Community Discussions

            QUESTION

            How to configure Ubuntu as router in Vagrant
            Asked 2021-Jun-05 at 20:59

            I'm trying to configure a simple network structure using Vagrant as depicted in the following figure:

            As you can see I aim to simulate a hacker attack which goes from attacker through router and reaches victim, but that's not important for the problem I'm struggling with.

            This is my Vagrantfile so far (VritualBox is used as provider):

            ...

            ANSWER

            Answered 2021-Jun-03 at 22:55

            You've got a redundant default gateway on victim and attacker called _gateway. You should delete it and leave only the one going to the router via eth1 interface.

            Source https://stackoverflow.com/questions/67828135

            QUESTION

            Python requests_html: Socks5h proxy does not work when calling "render()"
            Asked 2021-May-31 at 01:45

            I'm using "python requests_html" because I want to get the rendered html source code. In addition, I want to do that via socks5h(Tor) proxy.

            So, I tried to write the following code. However, once render() function was called, raw ip address is displayed. This seems that render() function doesn't use proxy settings.

            Actually, I tried to connect to tor bbc news (onion domain) using the following code, it failed, because that's not tor network.

            Is there any good idea to render using socks5h proxy?

            ...

            ANSWER

            Answered 2021-May-31 at 01:45

            Sorry for the self answer. requests_html uses pyppetter internally, and this proxy issue depends on pyppeteer. Current requests_html seems that it doesn't pass proxy information, so pyppeteer doesn't use proxy. According to the following github pages, it seems that this issue would be solved in the future.

            Source https://stackoverflow.com/questions/67743945

            QUESTION

            Can I ping with Tun/Tap interface
            Asked 2021-May-27 at 10:32

            I am learning routing with tuntap interfaces... and I had created a tun0 interface and configured Ip address with ifconfig command on different subnet and adding the gateway with ip route command and I have also used masquerading rule ... my doubt is can i ping with tuntap interface or they are only used to route the traffic or something I don't know about these interface or may be misconfiguration..

            May be this question sounds me new bie and I am but give please give me correct direction..

            Ok Gerhardh,

            Edit: I had created tun dev like this:

            ...

            ANSWER

            Answered 2021-May-27 at 10:32

            Standard network interfaces have a piece of hardware behind them (a network card).

            Tuntap don't:

            https://www.kernel.org/doc/Documentation/networking/tuntap.txt

            tl;dr: packets sent to a tuntap interface are handed over to a user-space program for processing. This program takes on the role of the network card in some way (example: openvpn). Unless there is a program taking packets out of the device and doing something meaningful with them, they will vanish into the void (like a network card with a disconnected cable).

            Source https://stackoverflow.com/questions/67716753

            QUESTION

            VirtualBox: Host can not SSH to Guest
            Asked 2021-May-25 at 14:56

            i'm having some issue with m VirtualBox installation, 6.1.22. I have a VM with SUSE (SL12P1) for 64bit as a guest operative system, I have already installed the extension package and I'm trying to reach the guest from the host-system (Windows10) using ssh. I have set the network adapter as "Bridge", in this way the guest has a 192.168.120.x IP, which i verified with ifconfig while the host has an IP of 192.168.120.y. I can ping the guest from the host, but I cannot ssh the guest from the host system. Notice that:

            1. The firewall has been disabled
            2. I have enabled Hyper-V virtualization.
            3. I have tried setting the network adapter as NAT, and use port forwarding, but the ssh does not work either
            ...

            ANSWER

            Answered 2021-May-25 at 14:56

            The firewall for SuSE was active by default, after disabling it everything worked.

            Source https://stackoverflow.com/questions/67604325

            QUESTION

            Cannot determine ethernet address for proxy ARP (PPTP VPN)
            Asked 2021-May-23 at 05:29

            I've installed pptpd on ubuntu 18.04 and I can connect to vpn with android and windows client but I have no internet access while the server has full internet access. In pptpd log I noticed the error "Cannot determine ethernet address for proxy ARP".

            I've changed the dns in /etc/ppp/options.pptpd as below:

            ...

            ANSWER

            Answered 2021-May-23 at 05:29

            After trying many solutions finally I found the answer. My ethernet interface called ens160 so for IP masquerading I should use this:

            Source https://stackoverflow.com/questions/67655856

            QUESTION

            How to replicate bash's escaping on commands passed as arguments to other commands
            Asked 2021-May-18 at 09:10

            I'm passing the result of the execution of a command to python as input, like so:

            ...

            ANSWER

            Answered 2021-May-18 at 09:10

            I am struggling to find a way to replicate the escaping bash does behind the scenes

            Typically use printf "%q" to escape stuff.

            Source https://stackoverflow.com/questions/67569259

            QUESTION

            Where does Android actually invoke "ip link" or "ifconfig" to bring an interface up?
            Asked 2021-May-17 at 18:38

            I've spent a few hours reading the AOSP source to try to find how and where "ip link" or "ifconfig" is invoked when eth0 needs to be brought up.

            Does Android 10 use "ip link" or "ifconfig" to set the address and bring up eth0?

            Or does it manipulate the network interfaces in some other way?

            ...

            ANSWER

            Answered 2021-May-14 at 20:10

            Since you mentioned eth0, I'll assume you're interested in Ethernet interfaces. Each transport type has its own way for managing IP provisioning. For ethernet interfaces, you can find the owning class at EthernetNetworkFactory link. The method you are interested in seeing how this works is EthernetNetworkFactory#provisionIpClient link.

            Ultimately if you follow the code, you'll see this eventually arrive at netd here in NetdNativeService#interfaceAddAddress link. At this point we're in the native layer.

            This then ultimately arrives at ifc_utils#ifc_act_on_address link. This is where the ip address will ultimately be added to the ethernet interface. After all of this detective work, we see in this function that a socket is opened to send a NETLINK_ROUTE message link to set the ip address.

            Source https://stackoverflow.com/questions/67533929

            QUESTION

            Docker compose ignoring ipv4_address in container
            Asked 2021-May-14 at 16:18

            I have following docker-compose.yaml file

            ...

            ANSWER

            Answered 2021-May-14 at 14:29

            I had a similar problem when using docker compose up on macOS. Using docker-compose up (note the - sign) resolved it.

            Source https://stackoverflow.com/questions/67318361

            QUESTION

            Exit out of a console connection in Python
            Asked 2021-May-12 at 18:20

            I am working on some python code to log into a whitebox device that houses a virtual application (VTA). There will be two different VTAs installed and the code will log into the physical device, then log into the VTA using a virsh console (Name of VTA).

            The issue I am running into is exiting one VTA and then virsh console into another. The exit command simply brings me to a login prompt again but will not exit out of the console connection.

            In order to do so, I must send a "control + ]" in order to break out of the console. I have been searching online to try and find a solution but the only option I have found is to send and "exit" followed by "\x1b". However, This does not actually break out of the console window. Rather, it ends the session which is not what I am looking for.

            Is there a way to send a "Control + ]" in python?

            Here is some of the code showing the steps:

            ...

            ANSWER

            Answered 2021-May-12 at 18:20

            The hex character you're using to send the ctrl+] is wrong. Update your exit console commands to this: exit_console = [ 'exit\n', '\x01D' ]

            ASCII Reference: http://www.physics.udel.edu/~watson/scen103/ascii.html

            It also looks like you're using the invoke_shell() method, you can use the close() method to exit out of that particular shell and establish a new one as needed.

            Paramiko reference: http://docs.paramiko.org/en/stable/api/channel.html

            Source https://stackoverflow.com/questions/67207216

            QUESTION

            My ZSH completions won't work on start but they do when I source .zshrc (Mac)
            Asked 2021-May-11 at 10:39

            a simple summary is in the title but to further explain:

            Whenever i open my terminal (iterm2) i load into zsh but completions don't seem to work, then when i manually run source .zshrc it does fully load. I've tried moving stuff around in my .zshrc file to see if the order of loading was incorrect but it didn't fix anything.

            My .zshrc file:

            ...

            ANSWER

            Answered 2021-May-11 at 10:39

            You're making two mistakes in your .zshrc file:

            1. If you do source $ZSH/oh-my-zsh.sh, then you shouldn't also do autoload -U compinit && compinit, because the former includes the latter.
            2. plugins=( ... ) should be done before doing source $ZSH/oh-my-zsh.sh. The former does not do anything by itself.

            So, change the top of your .zshrc file to this:

            Source https://stackoverflow.com/questions/67484598

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install ifconfig

            You can download it from GitHub.

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            gh repo clone missdeer/ifconfig

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