deduplicate | Remove duplicate urls from input | REST library
kandi X-RAY | deduplicate Summary
kandi X-RAY | deduplicate Summary
Parsing through long lists of endpoints, full of params, became a hassle? You want to get out? Say no more, Deduplicate is the solution. With less than 200 lines of code, written in Go, it will remove any duplicates from your lists and make visual parsing a bliss. I made this so that I can go faster through wayback urls output.
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Top functions reviewed by kandi - BETA
- main is the main entrypoint
- extIsVideo returns true if ext is a video .
- extIsImage returns true if the given extension is an image .
- DEPRECATED
- extIsFont returns true if ext is a font .
deduplicate Key Features
deduplicate Examples and Code Snippets
Community Discussions
Trending Discussions on deduplicate
QUESTION
I don't want to delete duplicate files, but I only want to see one instance of each.
Prioritization among duplicates doesn't matter in this case.
///
The actual scenario:
I want to create a VLC playlist containing every video I have ever downloaded from a particular domain. The files are not well-organized and many exist in more than one location on my computer. Consequently, a Finder search for "Where from" --> [the domain] returns many duplicate files. Which means I can't just drag and drop the search results into VLC without there being many duplicates.
I don't want to deduplicate the files themselves.
How can I make this happen?
...ANSWER
Answered 2021-Jun-09 at 07:20It is not possible to hide duplicates in the Finder search because there is no option for filtering duplicates in the Finder search.
But your job is to search, then create a playlist. This can be done by dragging and dropping your selection onto the next droplet, which you can call "VLC Playlist Creator". (Or turn it into a "Make VLC Playlist" service using Automator). It will filter for you the duplicates and open Save Playlist Dialog of VLC.app.
QUESTION
i have a command like this :
...ANSWER
Answered 2021-May-27 at 09:15You haven't specified much about your usecase. In you oversimplified example the "filter" matches always the same line, and never a different one. If that's the case, maybe piping the result into uniq could be enough:
QUESTION
SELECT
CASE
TO_CHAR(last_day(SYSDATE),'DAY')
WHEN '1' THEN last_day(SYSDATE) - 1
WHEN '7' THEN last_day(SYSDATE) - 2
ELSE last_day(SYSDATE)
END
AS "Last legal business day"
FROM
dual;
ANSWER
Answered 2021-May-20 at 09:18Your query is not going to work as TO_CHAR(value, 'DAY') will output, for example, "MONDAY " rather than a numeric value.
It will also not give consistent results in different countries as, depending on the NLS_TERRITORY parameter being used, different countries start their week on different days (day 1 is Sunday in America but in Great Britain day 1 is Monday).
You can do it without sub-queries, without TO_CHAR and without a CASE statement using TRUNC to find the start of the ISO week (which is always a Monday):
QUESTION
I have a dataset of companies. Each company has tax payer number, address, phone and some other fields. Here is a Pandas code I take from Roméo Després:
...ANSWER
Answered 2021-May-18 at 17:19You could solve this using the graph analysis library networkx.
QUESTION
I have quite some stateless React components and all of them contain the same (duplicated) code.
Example:
...ANSWER
Answered 2021-May-17 at 18:48One great way to extract a lot of duplicated code is through HOCs (Higher Order Components). For example in order to extract the state you can do like this:
QUESTION
Given an array of unknown length of objects that looks like:
...ANSWER
Answered 2021-May-17 at 18:11If you want to "filter" by id, I think this will fits to you.
QUESTION
I am trying to deduplicate the records using input topic as KTable and sinking them to output topic. But the KTable is still sinking the duplicate records to the output topic. Not sure where am I going wrong.
Here is my application.yml
...ANSWER
Answered 2021-May-07 at 19:46I think the problem that you are trying to solve, will be well solved by compacted topic here. Once you deliver data with the same key to a compacted topic and compaction is enabled on broker level (which is enabled by default), each broker will start a compaction manager thread and a number of compaction threads. These are responsible for performing the compaction tasks. Compaction does nothing but keeps the latest values of each key and cleans up the older (dirty) entries.
Refer this Kafka Documentation for more details.
QUESTION
I am back again with my ctrlpanel application.
I have it 100% working in development and went through the process to get it loaded up to Heroku and got the app up, gems installed. DB is there (mostly) but I have an issue even before the DB. I am getting an error dealing with devise_invitable that I DO NOT get in Development. To my surprise I do get the same error when I launch production on my laptop which was shocking to me to say the least as everything works perfect in development. So I know it isn't a Heroku issue which I am happy about at least I can reproduce it. The full error is below here but the line that specifically deals with the error is:
...ANSWER
Answered 2021-May-06 at 05:40The recommendation to move invitations_controller.rb into an app/controllers/users folder is the correct one. That's the path that matches your route:
QUESTION
I perform a geodataframe modification on the items during the for loop with itertools.combinations(). I check that there are no duplicate geometries, LineString in my case. If yes I delete one of them.
The pandas drop_duplicates() method does not work here because we are dealing with spatial geometries with point coordinates that may be distributed differently and yet represented by the same LineString.
...ANSWER
Answered 2021-Apr-29 at 12:49import numpy as np
def deduplicate(geo_data: np.ndarray # shape == (N, 4)
) -> np.ndarray: # deduplicated data with origin order
data = geo_data.reshape(-1, 2, 2)
dt = f'f{data.itemsize}' # f4 or f8
data = data.view([('x', dt), ('y', dt)])
# eliminate differences
ixs = np.argsort(data, -2, order=('x', 'y'))
data_no_df = np.take_along_axis(data, ixs, axis=-2) # sorted by 'x' then by 'y'
# get unique
unique_sorted_data, uni_ixs = np.unique(data_no_df, True, axis=0)
uni_ixs.sort() # inplace sort 1d-array
data_deduplicated = geo_data[uni_ixs] # unique, originally ordered and shaped
return data_deduplicated
def _test():
geo_data = np.array([[42.70275, 9.94481, 42.7003 , 9.94783],
[42.7003 , 9.94783, 42.70275, 9.94481],
[42.70275, 9.94481, 42.697 , 9.97133],
[42.697 , 9.97133, 42.70275, 9.94481],
[42.60179, 10.34216, 42.7003 , 9.94783]])
data_deduplicated = deduplicate(geo_data)
print(data_deduplicated)
>>> _test()
[[42.70275 9.94481 42.7003 9.94783]
[42.70275 9.94481 42.697 9.97133]
[42.60179 10.34216 42.7003 9.94783]]
large_data = np.random.randint(0, 10, size=(1000, 4)).astype('d')
%timeit deduplicate(large_data)
1.98 ms ± 9.37 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)
QUESTION
Thanks to another SO answer, I successfully wrote a function that deduplicates a Vec. However, it does two clones of each item. I want to be able to do this with a single clone.
Here is the gist of what I am doing.
- The incoming Vec is not mutable.
- The output list must preserve order of retained items.
- The type of item is Clone, not Copy.
ANSWER
Answered 2021-Apr-13 at 13:58You don't need the items in the hashset: references would be enough.
Note also that you should prefer passing &[T] instead of &Vec as argument as it covers more cases. So I'd change your code to
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