Replay | Das Replay-System nimmt die Aktionen von Spielern und | Addon library
kandi X-RAY | Replay Summary
kandi X-RAY | Replay Summary
Das Replay-System nimmt die Aktionen von Spielern und Entities auf einem Server auf. Es kann als Schnittstelle genutzt werden und bietet eine simple Benutzung. Fertige Replays können nicht nur als Datei, sondern auch als Bytearray verwendet werden, was das Abspeichern in Datenbanken ermöglicht. Neben der Möglichkeit des Aufzeichnens kann man mit dem selben Plugin auch Replays abspielen. Eine benutzerfreundliche GUI ist bereitgestellt, welche erlaubt zu beschleunigen, rückwärts abszuspielen, zu pausieren und sich zu Spielern zu teleportieren.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Replay
Replay Key Features
Replay Examples and Code Snippets
Community Discussions
Trending Discussions on Replay
QUESTION
I have a project with hundreds of commits. It is a fork of another open-source project. At the time the fork was created, the git history was wiped. Now I want to reattach the history.
The original project has thousands of commits, call them: A <- B <- C <- D
Meanwhile, our fork has: E <- F <- G <- H
The branches do not share any common ancestors, but commit D and E have exactly the same filesystem. When E was created, the git history was wiped.
How can I reattach them without solving merge conflicts?
Solutions I've tried:
git cherry-pick fork/initial..fork/develop- I tried cherry-picking changes from the fork onto the original repo, but this resulted in merge conflicts. This solution tries to replay the commits linearly, but with all of the branching and merges that happened, there are merge conflicts all along the way.git rebase -i fork/initial fork/develop~0 --onto new-branch- Rebasing instead of cherry-picking unfortunately has the same problem as above. It tries to replay the commits in order, leading to merge conflicts. I also tried with--rebase-mergesto no avail.git merge fork/develop --allow-unrelated-histories-- This is the closest to what I want. It still resulted in a ton of merge conflicts (for reasons I don't understand?) but I resolved them all at once withgit checkout fork/develop -- .andgit commit. The problem with this solution is the "initial commit" of the fork branch is still the oldest commit to touch every file, so I am not getting any of the benefits of consolidating these branches.
All the solutions I’ve encountered so far require me to resolve conflicts. This should not be required, since I am trying to attach histories at a point where the filesystems are identical.
I just want to reattach the history to where it came from. Any ideas?
...ANSWER
Answered 2022-Apr-09 at 17:37You can try this
QUESTION
MutableSharedFlow takes 3 parameters: replay, extraBufferCapacity and onBufferOverflow. What is the difference between replay and extraBufferCapacity?
The documentation mentions the following:
replay - the number of values replayed to new subscribers (cannot be negative, defaults to zero).
extraBufferCapacity - the number of values buffered in addition to replay. emit does not suspend while there is a buffer space remaining (optional, cannot be negative, defaults to zero).
I don't understand exactly the difference between the 2 and when we would need extraBufferCapacity > 0. Is extraBufferCapacity just an additional replay capacity for emitters?
...ANSWER
Answered 2022-Apr-05 at 09:31Is extraBufferCapacity just an additional replay capacity for emitters?
The "replay" terminology only really makes sense for subscribers, not emitters. The replay parameter defines how many past values new subscribers will receive upon subscribing. It obviously implies that those values need to be stored, so the overall buffer needs to be at least this big.
However, the buffer size (as a whole) impacts emitters. The exact consequence of a full buffer depends on onBufferOverflow, but this buffer size can be used to control backpressure on emitters (slowing them down) or how we drop messages. With a larger buffer, you can allow emitters to have bursts of emissions without slowing them down, like any regular buffer.
Now, choosing to have a larger buffer shouldn't force you to replay those buffered values to new subscribers, hence the extraBufferCapacity. With extraBufferCapacity > 0, you can define a buffer of any desired size without also forcing you to replay as many values, simply by using the formula:
QUESTION
How can we divide work of consumers over a limited set of resources in RXJS?
I have a Pool class here (simplified):
ANSWER
Answered 2022-Mar-31 at 12:55So the main thing is you need to share the actual part that does the work, not only the resources.
Here's a solution from me:
https://stackblitz.com/edit/rxjs-yyxjh2?devToolsHeight=100&file=index.ts
QUESTION
To back-test a trading strategy, I use the replay feature in trading view and mark my trades by adding a "long position" or "short position" from the left panel. Like this:
I need to save the data (chart data including the positions, or any other drawing I have in that layout) as an Excel or a CSV file on my PC.
I know TradinView has export chart data features but does it include all the positions and the drawings or is it just chart data and the indicators?
If that doesn't work, is there any way to get that data? (from tradingview api for example)
...ANSWER
Answered 2022-Feb-20 at 10:59I'm not sure that is what you are looking for but recently I found this GitHub:
That repo is written in JS, but the author provides some examples and the first sentence is:
"Get real-time market prices and indicator values from Tradingview !"
I hope that you found this useful.
QUESTION
I need to automate the upload of some files from client PCs to a central server. We're building central statistics for an online gaming community, processing game replay files.
- target is my own small VPS server running ubuntu
- upload file size 2-3MB
- 20-40 different clients running windows spread around the globe
- I expect ~6GB of wanted data to be uploaded over the course of 7 weeks (a season in our game) and 5-10x that amount of "unwanted" data.
The files are processed on the server, and then they're not required anymore, and ought to be deleted to not run out of disk space eventually. I also only need some of the files, but due to the files requiring very complex processing including decryption, so i can only determine that after the server processed it.
My initial idea was to use a scriptable client such as WinSCP, and use some Windows scheduler entry to automate it. WinSCP documentation looks very nice. I am a bit hesitant because I see the following problems:
- after deletion on the server, how to prevent re-upload ?
- ease of setup to technical novices
- reliability of the solution
I was thinking maybe someone has done the same before and can give some advice.
...ANSWER
Answered 2022-Jan-27 at 06:32There's article on WinSCP site that deals with all this:
How do I transfer new/modified files only?
For advanced logic, like yours, it uses PowerShell script with use of WinSCP .NET assembly.
Particularly, there is a section that you will be interested in: Remembering the last timestamp – It shows how to remember the timestamp of the last uploaded file, so that the next time you will transfer only newer files, even if the previously uploaded files are not on the server anymore.
The example is for downloads with
Session.GetFiles, but it will with small changes work for uploads withSession.PutFilestoo.It also points to another article: Remember already downloaded files so they are not downloaded again, which shows another method – To store names of already transferrer file to a file and use it the next time to decide, which files are new.
QUESTION
First of all, I want to animate the steps of Quick Sort, to learn its behavior.
The Quick Sort algorithm is fine (of course) from a reference book.
But I can only view only the start and end of the Quick Sort movement. Let me know how to view every single step in Quick Sort by d3.js. (I'm a JS beginner.)
My temporary codes are as below. Thnx in advance.
index.html:
...ANSWER
Answered 2022-Jan-16 at 07:28The problem is that you're calling redraw() without waiting for the transition to complete (it takes 1s i.e. durationTime, while the subsequent redraw calls must be taking a few milliseconds).
The solution is to save all the steps in an array. And then later re-use it to redraw with a time interval between each redraw() call. Use setInterval for that.
I have created a working codepen with the mentioned changes.
- replace all calls to
redraw()with asteps.push(ref: Array push method) - After the sorting is complete. Call redraw
steps.lengthtimes with a time interval of something greater thandurationTime(ref: setInterval) - Once you've finished redrawing,
clearIntervalto cleanup thesetInterval(ref: clearInterval)
QUESTION
My target is to play a given sound or music for a given second, but the music file is actually longer than the given seconds. i.e. the file is 2 min 32 seconds long but only required to play 16 seconds. My design of player part is:
...ANSWER
Answered 2021-Dec-24 at 22:02Theoretically, if I understand the question right, you can just call stop() after x seconds when you call play()
QUESTION
I've installed Windows 10 21H2 on both my desktop (AMD 5950X system with RTX3080) and my laptop (Dell XPS 9560 with i7-7700HQ and GTX1050) following the instructions on https://docs.nvidia.com/cuda/wsl-user-guide/index.html:
- Install CUDA-capable driver in Windows
- Update WSL2 kernel in PowerShell:
wsl --update - Install CUDA toolkit in Ubuntu 20.04 in WSL2 (Note that you don't install a CUDA driver in WSL2, the instructions explicitly tell that the CUDA driver should not be installed.):
ANSWER
Answered 2021-Nov-18 at 19:20Turns out that Windows 10 Update Assistant incorrectly reported it upgraded my OS to 21H2 on my laptop.
Checking Windows version by running winver reports that my OS is still 21H1.
Of course CUDA in WSL2 will not work in Windows 10 without 21H2.
After successfully installing 21H2 I can confirm CUDA works with WSL2 even for laptops with Optimus NVIDIA cards.
QUESTION
I tough that induction n, m would create induction hypothesis for n and m but after some tries this seems not be the case. BTW I'm assuming forall (n m : nat).
So what is the difference of induction n, m induction n. induction m and induction n; induction m?
Here is my currently understanding:
I know that ; is a combinator so that a; b replays b on every subgoal generated by a, so induction n; induction m will generate an induction hypotesis for m for each subgoal of induction n is this right?
And in the same sense induction n. induction m would generate induction hypotesis only for the current goal so that this seems not particularly useful
I expected induction n, m to be like induct on this two variables this generate four goals for natural numbers as I expected, but I expected IHm to be on context on the 4th goal but it isn't! What I'm missing?
--
Still researching on this, it seems that the IHm is merged in IHn at the 4th goal, is this correct?
-- edit 2
Here is some example based on addition commutativity
So first the induction n, m version:
ANSWER
Answered 2021-Nov-09 at 14:56induction n, m is the same as induction n; destruct m. The reason for this is that it's quite rare that you actually want two induction hypotheses, and in cases where you do, you probably don't want induction n; induction m because the induction hypothesis for m will not be appropriately general over n.
The reference manual for 8.15 will be much more complete than the reference manual for 8.14, and you can find this documented in the current documentation for the master branch:
If no induction_principle clause is provided, this is equivalent to doing induction on the first induction_clause followed by destruct on any subsequent clauses.
QUESTION
I have developing an application that records the events and replays them. For that I need to identify what kind of event is being generated because mouse, keyboard and form events behave differently from each other.
Right now i am trying to use:
e instanceof KeyboardEvent but this doesn't seems to be working. What is the better way of identifying to which event family it belongs to?
ANSWER
Answered 2021-Nov-05 at 14:34Using the event.detail allow you to determine if the event was a keypress or mouse event
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install Replay
You can use Replay like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the Replay component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
