ServerProxy | Android library for creating proxy servers | Runtime Evironment library
kandi X-RAY | ServerProxy Summary
kandi X-RAY | ServerProxy Summary
serverproxy is a android library to provide easy to use classes to create a local server proxies. the following classes exist:. serverproxy: abstract class which creates a socket and has methods to get a url to reference it. - start: start the proxy listening for requests - stop: stop the proxy listening for requests - getprivateaddress: get a local url good for being passed internally to another application on the same device - getpublicaddress: get a url good for being passed to another device on the same lan. fileproxy: streams whichever file is referenced in the url. can handle partial requests. bufferproxy: streams a file which is being concurrently downloaded. takes a bufferprogress object to determine when the file is finished downloading. this is useful for serving a song to a mediaplayer which
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Top functions reviewed by kandi - BETA
- Returns the private address for the given request
- Returns the address for the given host and request parameters
- Returns the public address for the given request
- Process the incoming request
- Starts the proxy
- Stops this service
ServerProxy Key Features
ServerProxy Examples and Code Snippets
Community Discussions
Trending Discussions on ServerProxy
QUESTION
I am trying to run an XMLRPC server and an XMLRPC client on Mininet hosts, using the script below.
...ANSWER
Answered 2021-May-13 at 11:24Replace print(net.hosts[0].cmd('python3 xmlrpc_server.py'))
with print(net.hosts[0].sendCmd('python3 xmlrpc_server.py'))
. Connection is sometimes refused, but that issue can be resolved with exception handling on the client script.
QUESTION
Hello i'm trying the External API of Odoo so i'm trying something but i have an error when i try to launch my main.py.
...ANSWER
Answered 2021-Apr-02 at 09:13OK I'll answer myself...
The problem was my Python default version.
I had Python2.7 et Python3.8, but the priority was set to :
Python2.7 as "2" (hight priority)
AND
Python3.8 as "1" (low priority)
so i had to change the priority of both by this command :
QUESTION
I'm trying to take the first download 'str' zip link. I don't need more than one file of information. When I tried a not famous movie such as Shame 2011 My code worked but when I tried Avatar doesn't work. I think the code trying to take a lot of 'str' files information, API after that blocks this request.
**How I can reach the first English str file download link? **
...ANSWER
Answered 2021-Apr-01 at 17:27Check out opensubtitle's new API - here's the documentation. It's way easier to use than the older API.
Grabbing subtitles is as easy as
QUESTION
I'm trying to set up one RaspberryPi as server and another as client using Python3 xmlrpc. There are plenty of examples online, mostly along the same lines. The relevant server code snippet is:
...ANSWER
Answered 2020-Dec-14 at 18:08OK, I found the answer. For anyone arriving here with the same problem this is what I've learned.
The 'localhost' in the server code means only listen for connections from this machine. Changing this to '0.0.0.0' means listen on "all IPv4 addresses on the local machine" - Wikipedia. So I made the change and it worked.
But I also did some tests. As shown, my server Pi is at 192.168.1.19, but changing the client code call to 192.168.1.100 connected just the same. Perhaps '0.0.0.0' means just all IPv4 addresses, but I don't want the server code to spark up in response to every network call. Changing the server code from '0.0.0.0' to its actual address of '192.168.1.19' made it ignore all other addresses. In my world I'm unlikely to have a machine with more than one IP address.
QUESTION
I'm trying to use the xmlrpc api of odoo 14.
I have made a small script to do some tests. In the test I do a read operation but I get an xmlrpc.client.Fault
exception, where odoo compains that I try to modify 'res.users'
although my query is a read on 'res.partner'
Here is my test script. (Please note that the error is the same if I try to do a search_read instead of a search then read)
...ANSWER
Answered 2020-Nov-28 at 09:40Please check with this, what's giving in it.
QUESTION
I'm trying to register a payment for an invoice that I created earlier via the API.
I posted the invoice as follows
...ANSWER
Answered 2020-Oct-24 at 01:13The action_register_payment method will check if active_ids
is in context and if not it will return an empty string.
To pass the context you need to pass a dict just after the args list like they passed the fields
argument to the read method in the official XML-RPC documentation:
QUESTION
I am writing a python script to backup and restore an Odoo database (copy, really).
My code to make the backup is as follows:
...ANSWER
Answered 2020-Oct-23 at 06:37QUESTION
I'm trying to change the state of a created invoice from 'draft' to 'posted' using the Web APIs (Python) by referring to this documentation : https://www.odoo.com/documentation/13.0/webservices/odoo.html
I'm updating the invoice as follows :
...ANSWER
Answered 2020-Oct-19 at 09:21I recommend to use Odoo's workflow and business logic here by calling post
instead of directly writing the state.
QUESTION
url = "ip"
db = "dbname"
username = "user"
password = "admin"
common = xmlrpc.client.ServerProxy('{}/xmlrpc/2/common'.format(url))
uid = common.authenticate(db, username, password, {})
actions = models.execute_kw(db, uid, password, 'ir.cron', 'search', [[['name', '=', 'Mail: Email Queue Manager']]])
print(actions)
Returns [2]
...ANSWER
Answered 2020-Aug-24 at 22:18You can run the action manually by calling the method_direct_trigger
method.
Example:
QUESTION
I want to use the xmlrpc for the model "product.category".
How to write the field "categ_id" with "read and search"in PYTHON ? I have always an error. I need to do that because i have to transfer this informations into another database Odoo.
...ANSWER
Answered 2020-Aug-05 at 14:44The method name should be search_read
Example:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install ServerProxy
You can use ServerProxy like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the ServerProxy component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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