segment-trees | Automatically exported from code.google.com/p/segment-trees

 by   mikemccand Java Version: Current License: No License

kandi X-RAY | segment-trees Summary

kandi X-RAY | segment-trees Summary

segment-trees is a Java library. segment-trees has no bugs, it has no vulnerabilities and it has low support. However segment-trees build file is not available. You can download it from GitHub.

Automatically exported from code.google.com/p/segment-trees
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            kandi-support Support

              segment-trees has a low active ecosystem.
              It has 11 star(s) with 3 fork(s). There are no watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              segment-trees has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of segment-trees is current.

            kandi-Quality Quality

              segment-trees has 0 bugs and 0 code smells.

            kandi-Security Security

              segment-trees has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              segment-trees code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              segment-trees does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              segment-trees releases are not available. You will need to build from source code and install.
              segment-trees has no build file. You will be need to create the build yourself to build the component from source.
              segment-trees saves you 737 person hours of effort in developing the same functionality from scratch.
              It has 1700 lines of code, 91 functions and 17 files.
              It has high code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed segment-trees and discovered the below as its top functions. This is intended to give you an instant insight into segment-trees implemented functionality, and help decide if they suit your requirements.
            • Build a JavaCounter1 from the ranges
            • Recursively splits the tree into a tree
            • Recursively builds the counter
            • Make a binary split
            • Computes the number of ranges
            • Recursively iterates over the specified node
            • Recursively builds the simple counter counts from the given node
            • Build a range - set implementation
            • Builds a generator for the given node
            • Recursively parse the given node
            • Searches for a certain range
            • Returns true if the given value is within the range inclusive
            • Returns counts for the forest
            • Determine the counts for a given node
            • Record the given value
            • Get the counts
            Get all kandi verified functions for this library.

            segment-trees Key Features

            No Key Features are available at this moment for segment-trees.

            segment-trees Examples and Code Snippets

            No Code Snippets are available at this moment for segment-trees.

            Community Discussions

            QUESTION

            Compute sum of (min*max) across all subarrays of the array
            Asked 2020-May-18 at 01:29

            given N elements of an array compute the sum (min*max) across all the subarrays of the array.

            e.g. N = 5

            Array: 5 7 2 3 9

            output: 346 (5*5 + 7*7 + 2*2 + 3*3 + 9*9 + 5*7 + 2*7 + 2*3 + 3*9 + 2*7+2*7 + 2*9 + 2*7 + 2*9 + 2*9)

            here is the complete question

            i cannot think of anything better than O(n^2). The editorial solution uses segment trees which i couldnt understand.

            ...

            ANSWER

            Answered 2020-May-18 at 01:29

            Hint regarding the editorial (the details of which I am uncertain about): if we can solve the problem for all the intervals that include both A[i] and A[i+1], where i divides A in half, in O(n) time, then we can solve the whole problem in O(n log n) time using divide and conquer, solving left and right separately, and adding to that the intervals that overlap both left and right.

            Source https://stackoverflow.com/questions/61707201

            QUESTION

            How is it possible to apply the lazy approach to update a segment tree if the update is more complex than simple addition or multiplication?
            Asked 2018-Apr-13 at 20:39

            Consider this question. In this segment tree solution, we are updating all nodes of the tree in the given range. Is it possible to apply lazy propagation to this problem?

            Edit: Consider that in every update operation arr[i] = (1-(1-arr[i])*a), where L<=i<=R and a is a constant.

            ...

            ANSWER

            Answered 2018-Apr-13 at 20:26

            Yes, it is indeed possible, at least in some cases.

            Basically, you need a way to efficiently store the lazy operation, and a way to efficiently combine two stored lazy operations into one.

            For instance, say the update operation is segment assignment, that is, a[l] = x, a[l+1] = x, ..., a[r-1] = x, a[r] = x. This operation on the whole subtree can be stored as just the value x, which will mean that the operation was to assign x to every vertex of this subtree. For lazy propagation in vertex v, we just apply it to immediate children of vertex v, and store the same lazy operation x there. Note that any old lazy operation in children is just erased by the assignment. Such is the nature of assignment.

            As for your added example, operation arr[i] = (1 - (1 - arr[i]) * a), let us see how the value changes after two such operations with constants a and b.

            Before operations, let the value be v.

            After the first one, it becomes w = 1 - (1 - v) * a, which is a*v + (1-a)*1.

            After the second operation, the value becomes 1 - (1 - w) * b, which is b*w + (1-b)*1, which in turn is b*a*v + b*(1-a)*1 + (1-b)*1, and finally becomes (b*a)*v + (1-b*a)*1. (I may have mixed up +s and -s, but that hopefully does not change the whole picture.)

            We can now see that the value is a linear function of the original value, so we can store the coefficients b*a and 1-b*a of the linear and constant terms, respectively.

            The problem now is that the coefficients may grow too quickly, and will soon exceed the capacity of the storage type (int, double or whatever). Now, if the problem deals with integer residues modulo some integer instead of just integers or reals, that's not an issue; otherwise, storing the coefficients soon becomes problematic.

            Source https://stackoverflow.com/questions/49824372

            QUESTION

            Improve the complexity of Update method in Range Minimum Query Using Square Root Decomposition Technique
            Asked 2017-Sep-11 at 09:45

            https://www.hackerearth.com/practice/data-structures/advanced-data-structures/segment-trees/practice-problems/algorithm/range-minimum-query/description/

            I am trying to solve this question. I am making the vector size of Math.ceil(Math.sqrt(arrSize)). I have used the following methods - For constructing sqrt vector

            I am taking square root chunks and finding the smallest index in the block and storing them in the vect array.

            How can I improve my update query complexity from Sqrt(n).

            ...

            ANSWER

            Answered 2017-Sep-11 at 09:45

            If you have to improve complexity you have to use Segment Trees. In this case you cannot directly update the index of the vect array like in case of range sum query. You have to find again the minimum of the block.

            Source https://stackoverflow.com/questions/46142953

            QUESTION

            Wrong Answer - Unable To Find Bug - Range Minimum Query Using Segment Trees
            Asked 2017-Sep-10 at 17:21

            I am trying to learn segment tree through https://www.topcoder.com/community/data-science/data-science-tutorials/range-minimum-query-and-lowest-common-ancestor/ After Understanding the basics of segment trees I tried to solve this question. But only one test case is passed and on the second one, I am getting tle. On further inspection comparing the two answers using filediff I found out there are wrong answers. I am unable to find any errors. Please help.

            this code is for creating and updating segment tree.

            Variables - node = starting index in segment tree which is 1. b = lower limit, e = upper limit

            ...

            ANSWER

            Answered 2017-Sep-10 at 17:21

            You are updating the segment tree in case of querying the minimum index. Remove it and the code is working fine. In case of query the segTree should not be changed.

            Source https://stackoverflow.com/questions/46129639

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install segment-trees

            You can download it from GitHub.
            You can use segment-trees like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the segment-trees component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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