Handle | Handler-based Eventbus for Android | Frontend Utils library
kandi X-RAY | Handle Summary
kandi X-RAY | Handle Summary
Handler-based Eventbus for Android.
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Top functions reviewed by kandi - BETA
- Run the benchmark
- Start the timer
- Prints the results
- End an event
- Start the Handler
- Send all registered tickies to the event handler
- Registers the event handler
- Initialize the activity
- Called when the bundle is created
- Initializes the debug
- Handle the post
- Returns the supported annotation types
- Unregisters an event handler
- Register event handler
- Unregister an object
- Cancel all pending events
- Registers the given object into the event bus
- Post an event to the event bus
- Checks if the handler is registered
- Cancel sticky event
- Returns a string representation of this buffer
- Handle a message
- Clears all registered listeners
- Initialize this class
- Process the inner classes
- Unregisters handler
Handle Key Features
Handle Examples and Code Snippets
Community Discussions
Trending Discussions on Handle
QUESTION
ANSWER
Answered 2022-Mar-21 at 14:44Does this work for you?
QUESTION
Apparently throwError(error)
is now deprecated. The IntelliSense of VS Code suggests throwError(() => new Error('error')
. new Error(...)
accepts only strings. What's the correct way to replace it without breaking my HttpErrorHandlerService
?
ANSWER
Answered 2021-Aug-04 at 19:08Instead of this:
QUESTION
I need to calculate the square root of some numbers, for example √9 = 3
and √2 = 1.4142
. How can I do it in Python?
The inputs will probably be all positive integers, and relatively small (say less than a billion), but just in case they're not, is there anything that might break?
Related
- Integer square root in python
- Is there a short-hand for nth root of x in Python?
- Difference between **(1/2), math.sqrt and cmath.sqrt?
- Why is math.sqrt() incorrect for large numbers?
- Python sqrt limit for very large numbers?
- Which is faster in Python: x**.5 or math.sqrt(x)?
- Why does Python give the "wrong" answer for square root? (specific to Python 2)
- calculating n-th roots using Python 3's decimal module
- How can I take the square root of -1 using python? (focused on NumPy)
- Arbitrary precision of square roots
Note: This is an attempt at a canonical question after a discussion on Meta about an existing question with the same title.
...ANSWER
Answered 2022-Feb-04 at 19:44math.sqrt()
The math
module from the standard library has a sqrt
function to calculate the square root of a number. It takes any type that can be converted to float
(which includes int
) as an argument and returns a float
.
QUESTION
I just downloaded pytube (version 11.0.1) and started with this code snippet from here:
...ANSWER
Answered 2021-Nov-22 at 07:03Found this issue, pytube v11.0.1. It's a little late for me, but if no one has submitted a fix tomorrow I'll check it out.
in C:\Python38\lib\site-packages\pytube\parser.py
Change this line:
152: func_regex = re.compile(r"function\([^)]+\)")
to this:
152: func_regex = re.compile(r"function\([^)]?\)")
The issue is that the regex expects a function with an argument, but I guess youtube added some src that includes non-paramterized functions.
QUESTION
My problem is that I'm trying to handle the value of my inputs, which the user defines which input he wants, by an API call.
Here is where I get the values :
...ANSWER
Answered 2021-Dec-10 at 13:32It was a bit hacky so I simplified it, I think you should understand the logic behind it.
QUESTION
I'm looking for a way to have all keys / values pair of a nested object.
(For the autocomplete of MongoDB dot notation key / value type)
...ANSWER
Answered 2021-Dec-02 at 09:30In order to achieve this goal we need to create permutation of all allowed paths. For example:
QUESTION
Imagine a df in the following format:
...ANSWER
Answered 2021-Nov-09 at 20:04I think this algorithm does what you want, but it's not very efficient. It may provide others with a starting point for faster solutions.
QUESTION
The contextlib.asynccontextmanager
documentation gives this example:
ANSWER
Answered 2021-Aug-03 at 11:18You can protect the task with asyncio.shield
to guarantee graceful shutdown of the context manager, I did changes only in main()
:
QUESTION
I have a dictionary of type
...ANSWER
Answered 2021-Aug-02 at 10:02You can't deconstruct directly in an out
parameter yet unfortunately, see this proposal.
You'll have to deconstruct it yourself:
QUESTION
The std::coroutine_handle
is an important part of the new coroutines of C++20. Generators for example often (always?) use it. The handle is manually destroyed in the destructor of the coroutine in all examples that I have seen:
ANSWER
Answered 2021-Jul-12 at 19:54This is because you want to be able to have a coroutine outlive its handle, a handle should be non-owning. A handle is merely a "view" much like std::string_view -> std::string
. You wouldn't want the std::string
to destruct itself if the std::string_view
goes out of scope.
If you do want this behaviour though, creating your own wrapper around it would be trivial.
That being said, the standard specifies:
The coroutine state is destroyed when control flows off the end of the coroutine or the
destroy
member function([coroutine.handle.resumption])
of a coroutine handle([coroutine.handle])
that refers to the coroutine is invoked.
The coroutine state will clean up after itself after it has finished running and thus it won't leak unless control doesn't flow off the end.
Of course, in the generator case control typically doesn't flow off the end and thus the programmer has to destroy the coroutine manually. Coroutines have multiple uses though and the standard thus can't really unconditionally mandate the handle destructor call destroy()
.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install Handle
You can use Handle like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the Handle component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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