iota | A simple IO library for using Clojure 's reducers | Dataset library
kandi X-RAY | iota Summary
kandi X-RAY | iota Summary
Iota is a Clojure library for handling large text files in memory, and offers the following benefits;. Why write this library? I wanted to be able to use Clojure reducers against large text files to speed up data processing, and without needing more than 10% memory overhead. Due to Java's inefficient storage of Strings, I found that a 1GB TSV file consumed 10GB of RAM when loaded line by line into a Clojure vector.
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Top functions reviewed by kandi - BETA
- Returns the first part of this object
- Convert this buffer to an array
- Computes the next split in a chunk
- Compute the end of a chunk
- Returns an iterator over the elements in this sequence
- Returns the line count
- Returns an iterator over the subfile vectors
- Return the nth value
- Get the first character from this buffer
- Replaces consecutive lines with line break
- Gets data from a buffer
- Append line number
- Get line
- Get the chunk at the specified index
- Prints a mmap
- Return the size of this file
- Return the first string in this queue
- Converts the buffer to an array
- Returns next segment
- Returns the next record
- Get the first element in the buffer
- Duplicate this buffer
- Splits the buffer into two lines
- Returns the next chunk
iota Key Features
iota Examples and Code Snippets
Community Discussions
Trending Discussions on iota
QUESTION
I am solving a problem on LeetCode:
Given an unsorted array of integers
nums
, return the length of the longest consecutive elements sequence. You must write an algorithm that runs inO(n)
time. So fornums
=[100,4,200,1,3,2]
, the output is4
.
The Union Find solution to solve this is as below:
...ANSWER
Answered 2022-Mar-14 at 07:33They are right. A properly implemented Union Find with path compression and union by rank has linear run time complexity as a whole, while any individual operation has an amortized constant run time complexity. The exact complexity of m
operations of any type is O(m * alpha(n))
where alpha
is the inverse Ackerman function. For any possible n
in the physical world, the inverse Ackerman function doesn't exceed 4. Thus, we can state that individual operations are constant and algorithm as a whole linear.
The key part for path compression in your code is here:
QUESTION
I like the idea of the lazy ranges you can make with std::views::iota
but was surprised to see that iota
is currently the only thing like it in the standard; it is the only "range factory" besides views::single
and views::empty
. There is not currently, for example, the equivalent of std::generate
as a range factory.
I note however it is trivial to implement the semantics of generate
by using a transform view on iota and just ignoring the value iota passes to transform i.e.
ANSWER
Answered 2022-Feb-17 at 17:10The reason why generate2
cannot work is that it does not model the range
concept, that is, the type returned by its begin()
does not model input_iterator
, because input_iterator
requires difference_type
and value_type
to exist and i++
is a valid expression.
In addition, your iterator does not satisfy sentinel_for
, which means that it cannot serve as its own sentinel, because sentinel_for
requires semiregular
which requires default_initializable
, so you also need to add default constructors for it.
You also need to rewrite bool operator!=(...)
to bool operator==(...) const
since operator!=
does not reverse synthesize operator==
. But it's easier to just use default_sentinel_t
as sentinel in your case.
if you add them to iterator
you will find the code will be well-formed:
QUESTION
Implementing a reset()
method, which uses some of the members from this
to construct a new object and then move-assign that object to *this
.
Questions:
- Does this cause any problems? UB or otherwise? (seems fine to me?)
- Is there a more idiomatic way?
Destructor and move-assignment operator only implemented to prove what is happening/ The real class has neither. "Rule of 5" not followed, as not needed here.
...ANSWER
Answered 2022-Feb-13 at 09:53
- Does this cause any problems? UB or otherwise? (seems fine to me?)
As long as the move assignment and the constructor are implemented in such a way that it does what you want, then I don't see a problem.
- Is there a more idiomatic way?
I would invert the direction of re-use.
QUESTION
Why is the variable 'n' in 2nd usage of std::generate
and within lambda capture not preceded with it's data type in below code?
I thought it's important to specify the datatype of all identifiers we use in a c++ code.
ANSWER
Answered 2022-Jan-17 at 13:41Why is the variable 'n' in 2nd usage of std::generate and within lambda capture not preceded with it's data type in below code?
It's not preceded with a data type, because the grammar of C++ says that it doesn't need to - nor even allowed to - be preceded by a type name.
A type name isn't needed because the type is deduced from the type of the initialiser expression.
QUESTION
I am learning union-find and to understand it better, I have written a small program:
...ANSWER
Answered 2022-Jan-13 at 17:23The output you got does not signify that one node is disconnected.
The parent
data structure represents links from one node to another (or itself, when it is a root).
At the start you have this:
And at the end we have this:
The important thing here is that there is one tree. It is not required that all nodes are linked directly to the root, just that they have a path to the root, which is also true for the node with index 3.
NB: if you would call find(3)
, then also index 3 would receive value 0. It is just something that gets optimised by calling find
, but it doesn't change the meaning of result.
QUESTION
My program has an iterative algorithm with a for-loop that I had written as
...ANSWER
Answered 2022-Jan-07 at 14:25With the auto i
you never use the variable anywhere.
With the for ( unsigned i=0; i < max_iter; i++ )
you're using i
twice, once in i < max_iter
and again in i++
so the variable is used
QUESTION
To quickly create a for loop similar to python's for i in range(100)
, I could do:
ANSWER
Answered 2022-Jan-01 at 15:42Is it possible for it to create something of a totally different type (not even weakly incrementable)? And can I safely ignore the warning?
According to the synopsis of iota_view
in [range.iota.view]:
QUESTION
Some ranges adaptors such as filter_view
, take_while_view
and transform_view
use std::optional
's cousin copyable-box
to store the callable object:
ANSWER
Answered 2021-Oct-09 at 14:20All the algorithms require copy-constructible function objects, and views are basically lazy algorithms.
Historically, when these adaptors were added, views were required to be copyable
, so we required the function objects to be copy_constructible
(we couldn't require copyable
without ruling out captureful lambdas). The change to make view
only require movable
came later.
It is probably possible to relax the restriction, but it will need a paper and isn't really high priority.
QUESTION
I am fairly new to ranges, and I wanted to know if there was a way to apply a dynamic number of range adaptors. I have fiddled around with some code for a while, and I have also done some searching, but to no avail.
...ANSWER
Answered 2021-Dec-04 at 23:02For a fixed number like this, it would be possible to use metaprogramming to recursively build the range (although you might hit a template instantiation depth limit). You can do a truly dynamic number by type-erasing the ranges, such that the chain of filters is connected by virtual function calls. The result is slow and the code is painful, but it’s certainly possible.
QUESTION
I saw that there is log level in Uber Zap implementation:
...ANSWER
Answered 2021-Nov-01 at 14:42The correspondence between go-logr
and go.uber.org/zap
log levels is given by:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install iota
You can use iota like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the iota component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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