dayz | Bullet journal , mood tracker ️

 by   karenying JavaScript Version: Current License: MIT

kandi X-RAY | dayz Summary

kandi X-RAY | dayz Summary

dayz is a JavaScript library. dayz has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Track your days, weeks, months, and years with dayz -- a minimalistic, aesthetic, and colorful online bullet journal.
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            kandi-support Support

              dayz has a low active ecosystem.
              It has 15 star(s) with 1 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              dayz has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of dayz is current.

            kandi-Quality Quality

              dayz has no bugs reported.

            kandi-Security Security

              dayz has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              dayz is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              dayz releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of dayz
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            dayz Key Features

            No Key Features are available at this moment for dayz.

            dayz Examples and Code Snippets

            No Code Snippets are available at this moment for dayz.

            Community Discussions

            QUESTION

            Unwanted space between menu and content
            Asked 2020-Jun-05 at 07:43

            I am developing a website with the help of HTML and CSS. Here, I have two parts of the page, first one - the menu and second part - rest of content. I am seeing an unwanted space between both parts. I checked the code many times but I could not find any reason for this. I used the developer tools to see what could I do. The margin was 0px. When I reduced the margin to -18 or -19px, then I could see both parts joined.

            Also, another problem is there. The paragraph text is going outside the container(as shown in the image). The code is as below -

            ...

            ANSWER

            Answered 2020-Jun-05 at 07:36

            The unwanted space you mentioned is coming because of h1 tag you used for about us.

            Source https://stackoverflow.com/questions/62210246

            QUESTION

            Transform rows in columns MSSQL
            Asked 2020-May-19 at 10:32

            I have this table

            ...

            ANSWER

            Answered 2020-May-19 at 09:48

            You weren't far off, but you're grouping by the wrong thing. The Row Number is what you want in each row, but you've defined it as your columns

            Source https://stackoverflow.com/questions/61887937

            QUESTION

            Event on label is not updating the clicked label
            Asked 2019-Jun-06 at 09:17

            I want to add a event for label when a specific label is pressed, but my event handler is not reacting to the clicked label.

            I created a calender so when I click a date I want to highlight that date, that's the requirement.

            ...

            ANSWER

            Answered 2019-Jun-06 at 09:01

            Your current implementation is trying to change the properties of lblDayz, which might be a single label somewhere. But the way you're creating labels you have a number of labels generated in code. One for each day

            That means you need your handler to react to the label that was clicked. The label that was clicked is the sender in your event handler. Crudely then you could handle it like this

            Source https://stackoverflow.com/questions/56473840

            QUESTION

            Python -While loop doesn't work with Time
            Asked 2019-Apr-17 at 11:06

            I have a code which starts a main function. In this function have a while loop which should starts program when certain time comes. I have set this time in morning (start time), evening(end time) variables. It is in while loop and it works, but only if I start the program the day I want to use it. For example: When I start it Monday evening (20:00) and start time(morning variable) is from 8:00 (next day), it will continue loop

            print("Waiting for the right time") <=(doing this)

            even if that time the next day comes. But It works when I start it the next day at 6:00 or so...

            Can someone explain me, why this happens? Here is the code

            ...

            ANSWER

            Answered 2019-Apr-17 at 01:31

            When you call .replace() to set the morning and evening times, it keeps the current date as part of the datetime object. So if you were to call it a day before, the dates would be set to the previous day's date, and thus .now() will never be in between the previous day's time range.

            E.g. if on January 1st you make the calls to set morning and evening, the stored datetimes will be "January 1st 8am" and "January 1st 4pm". The next time when your loop is checking, it asks "Is January 2nd 10am between January 1st 8am and January 1st 4pm" and of course the answer is no, because January 1st was the day before.

            You probably want to use the datetime.time class instead of the datetime.datetime class, if you're only wanting to check for time. Alternatively, you could set the date portion of your evening and morning datetimes to the specific date you want to match (but that wouldn't help for repeating weekly).

            Source https://stackoverflow.com/questions/55718641

            QUESTION

            Wait until specific time
            Asked 2019-Apr-09 at 01:28

            I'm writing a program that will do something if now == specific time and day and wait till that time if is not equal.

            I have a morning, evening, days values, which shows start time, end time and today's day. I would like to make a program that check if today is a weekday and specific time (between morning and evening) if True to do something and if even one of these is False, gonna wait till that time and after that do something.

            I did it with while loop but when it starts with False value(not in right time) it continue printing False even if that time came and value should change to True but it shows True when I start it in right time.

            Here is the code:

            ...

            ANSWER

            Answered 2019-Apr-09 at 00:42

            You only initialize your now variable once and never update its value to the current now. You should update the value inside the while loop, for example:

            Source https://stackoverflow.com/questions/55583380

            QUESTION

            Flexbox not working properly with Firefox
            Asked 2019-Mar-17 at 00:21

            On Chrome, the flexbox keeps the body of the page vertically centered on the page. However, on firefox, the page is not vertically centered and all of the content is moved as far to the top of the page as possible which can be seen in the picture and codepen below.

            Firefox: not working https://imgur.com/a/is880mp

            Chrome working https://imgur.com/a/2N6bXSF

            Example of problem: https://codepen.io/robbyjm/pen/PLeQVY?

            ...

            ANSWER

            Answered 2019-Mar-17 at 00:21

            You need height: 100vh on the body element. Then, to prevent a vertical scrollbar, override the default margins with margin: 0.

            Source https://stackoverflow.com/questions/55202540

            QUESTION

            Adjacent Jsx elements must be wrapped in an e
            Asked 2018-Oct-27 at 19:37

            i have a very annoying error when trying to display stuff in react table , i would like to make a table and display all values in rows , but for some reason i am getting this error saying Adjacent jsx elemetns must be wrapped in an enclosing element next to the line where im trying to map over results. Any help is greatly appreciated !! thanks!!!

            ...

            ANSWER

            Answered 2018-Oct-27 at 19:36

            the problem is that the closing tbody and table atgs should be outside map function as follows

            Source https://stackoverflow.com/questions/53025560

            QUESTION

            Sending music file from one application to another
            Asked 2018-Aug-14 at 11:10

            I'm trying to send a music files from my app to other ones using this code. I already have WRITE_EXTERNAL_STORAGE permission enabled. But whenever I choose the app I want to share my file with it doesn't appear or I get Toast saying format not recognized.

            ...

            ANSWER

            Answered 2018-Aug-14 at 10:02

            The problem with my code was due to change in how files are sent after Android N. Now apps should use content:// instead of file:// so the platform can extend temporary permission for the receing app. Only thing missing is File Provider that will change file:// into content:// in uri.

            The whole solution for my problem is here: https://stackoverflow.com/a/38858040/8430049

            So code should look like this:

            Source https://stackoverflow.com/questions/51837927

            QUESTION

            PHP login system won't header, and at relog must refresh to fully logout.
            Asked 2018-Mar-18 at 01:18

            I know that there are many, many questions about my problem, I read much of them, but I can't find a solution of my problem, that's why I'm asking too.

            I will write why do I think that I have the issues, and how to fix them, and I ask you to correct me if I'm wrong and help me with the solution, thank you. I've read a lot of information and topics from yesterday and still didn't found solutions.

            I have 3 errors.

            If I login with username "John" and then logout, and connect with username "Bob" it shows "John's" statistics.

            When pressed login, page refreshes, it logs the user, but it won't redirect him via header on profile.php page.

            Errors:

            ...

            ANSWER

            Answered 2018-Mar-18 at 01:18

            If I login with username "John" and then logout, and connect with username "Bob" it shows "John's" statistics.

            That's a session fixation issue. Clearly session_destroy() in logout.php is not working. While you should always change the session id whenever there is a change to authentication (login and logout) that's not going to fix the problem here. Presumably logout.php is emitting the "headers already sent" error. (see below).

            Cannot send session cache limiter

            DO NOT TRY TO MAKE YOUR SESSION PAGES CACHEABLE

            This is really difficult to get right and should not be attempted until you are an expert with PHP programming (and even then it is very dubious).

            This is not caused by the META headers you've shown us. It's in your PHP config.

            Source https://stackoverflow.com/questions/49342519

            QUESTION

            My index in my code doesn't work
            Asked 2018-Jan-23 at 08:10
            #TASK ONE
            #       LISTS      #
            import sys
            import time
            cows = []
            val = []
            num4 = 0
            literd = []
            test1 = []
            val1 = []
            day = []
            end = []
            num2 = []
            days = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"]
            daya = ["1234567"]
            # COW ID VALIDATION #
            h = int(input("How many cows do you have? "))
            for x in range(h):
                Id = int(input("Enter the 3 digit code of your cows: "))
                if len(str(Id)) != 3:
                    print("Sorry, the code ID can only be 3 digit numbers!")
                    sys.exit()
                elif Id in cows:
                    print("The cow ID is already in!")
                    sys.exit()
                else:
                    cows.append(Id)
            ###################
            # NUMBER OF COW LITERS #
            print(" ")
            dayz = list(days)
            cowz = list(cows)
            print(" ")
            print("In reality a cow can get milked 25 liters a day, beware!")
            for day in days:
                print("Day: ", dayz[0])
                cowz = list(cows)
                dayz.pop(0)
                for cow in cows:
                    print("Cow: ", cow)
                    test1.append(float(input("How many liters did you milk the cow at AM? ")))
                    test1.append(float(input("How many liters did you milk the cow at PM? ")))
            val = list(test1)
            ########################
            #ROUNDING NUMBERS AND ADDING THE LITTERS OF COW MILKED#
            val = [ round(elem, 1) for elem in test1 ]
            kek = list()
            total = sum(map(len, daya)) * h
            for x in range(total):
                num1 = val[0] + val[1]
                num2.append(num1)
                kek.append(num1)
                for x in range(2):
                    val.pop(0)
            num3 = list(num2)
            ########################################################
            #               PRINTS OUT THE RESULTS                #
            print(" ")
            print("A table will print out in just a second showing the results.")
            cowz = list(cows)
            print(" ")
            for day in days:
                print("Day: ", day)
                for cow in cows:
                    print("Cow: ", cow, end = " ")
                    print("liters: ", num2[0])
                    num2.pop(0)
            ########################################################
            cow1 = list()
            #TASK TWO
            # PRINTING OUT THE TOTAL LITERS OF MILK THIS WEEK#
            weekly = list()
            num5 = len(num3)
            for x in range(num5):
                num4 += num3[0]
                num3.pop(0)
            print("Total liters of milk this week", num4)
            #################################################
            # ADDING ALL THE LITERS FOR EACH COW #
            for day in days:
                cowz = list(cows)
                for cow in cows:
                    cow1.append(cowz[0])
                    cow1.append(kek[0])
                    cowz.pop(0)
                    kek.pop(0)
            ##################################################
            cow2 = list(cow1)
            cow3 = list(cows)
            cow_val = []
            cow_val1 = []
            print(cows, cow3)
            for x in range(h):
                current = cow3[0]
                while current in cow3:
                   cow_val.append(cow1[cow1.index(current)])
                   cow1.pop(cow1.index(current))
                   cow1.pop(cow1.index(current)+1)
                cow_val1.append(sum(cow_val))
                cow3.pop(0)
            
            ...

            ANSWER

            Answered 2018-Jan-23 at 08:10
            # ADDING TOTAL LITERS FOR EACH COW #
            cow2 = list(cow1)
            cow3 = list(cows)
            cowval = []
            cow_val1 = []
            for cow in cows:
                cow2 = list(cow1)
                i = 0
                total1 = 0
                while cow3[0] in cow2:
                    if cow3[0] == cow2[0]:
                        i += 1
                        cowval.append(cow2[i])
                        cow2.pop(0)
                        cow2.pop(0)
                        i = 0
                    elif cow3[0] != cow2[0]:
                        cow2.pop(0)
                        cow2.pop(0)
                        i = 0
                cow3.pop(0)
                cow_val1.append(sum(cowval))
                cowval.clear()
            

            Source https://stackoverflow.com/questions/48315369

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

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            You can download it from GitHub.

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