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QUESTION
I'm trying to get my head around programming real mode MS-DOS in C. Using some old books on game programming as a starting point. The source code in the book is written for Microsoft C, but I'm trying to get it to compile under OpenWatcom v2. I've run into a problem early on, when trying to access a pointer to the start of VGA video memory.
...ANSWER
Answered 2022-Apr-03 at 07:23It appears your OpenWatcom C compiler is defaulting to using C89. In C89 variable declarations must be at the beginning of a block scope. In your case all your code and data is at function scope, so the variable has to be declared at the beginning of main
before the code.
Moving the variable declaration this way should be C89 compatible:
QUESTION
I am trying to use a custom allocator, using the allocator API in Rust.
It seems Rust considers Vec
and Vec
as two distinct types.
ANSWER
Answered 2022-Mar-28 at 09:53Update:
Since GitHub pull request #93755 has been merged, comparison between Vec
s with different allocators is now possible.
Original answer:
Vec
uses the std::alloc::Global
allocator by default, so Vec
is in fact Vec
. Since Vec
and Vec
are indeed distinct types, they cannot directly be compared because the PartialEq
implementation is not generic for the allocator type. As @PitaJ commented, you can compare the slices instead using assert_eq!(&a[..], &b[..])
(which is also what the author of the allocator API recommends).
QUESTION
When i install a new create-react-app
and add babel-plugin-styled-components
and add displayName option to babel-plugin-macros.config.js
it isn't adding readable classNames as in the documentation -> https://styled-components.com/docs/tooling#babel-macro.
Here is a repo with the configurations https://github.com/Futekov3216/CRA.git
P.S i dont want to eject
...ANSWER
Answered 2021-Dec-16 at 06:49Today I myself faced such a problem. The problem lies in styled-components
itself. Macro in styled does not work since version 5.2.2, and it is not known when it will be fixed. Simplest solution:
QUESTION
Simple code as below or godbolt has different results from gcc, clang and Visual Studio.
...ANSWER
Answered 2022-Feb-21 at 14:38From [expr.prim.lambda.capture]/3:
A lambda-expression shall not have a capture-default or simple-capture in its lambda-introducer unless its innermost enclosing scope is a block scope ([basic.scope.block]) or it appears within a default member initializer and its innermost enclosing scope is the corresponding class scope ([basic.scope.class]).
Which means that captures such as [n]
, [&n]
or [&]
are not allowed in trailing return types or noexcept
specifiers, but initialized captures such as [i = 1]
are.
So GCC is right to reject the first two function definitions and GCC and Clang are right to reject the last one.
QUESTION
I have been using the #[tokio::main]
macro in one of my programs. After importing main
and using it unqualified, I encountered an unexpected error.
ANSWER
Answered 2022-Feb-15 at 23:57#[main]
is an old, unstable attribute that was mostly removed from the language in 1.53.0. However, the removal missed one line, with the result you see: the attribute had no effect, but it could be used on stable Rust without an error, and conflicted with imported attributes named main
. This was a bug, not intended behaviour. It has been fixed as of nightly-2022-02-10
and 1.59.0-beta.8
. Your example with use tokio::main;
and #[main]
can now run without error.
Before it was removed, the unstable #[main]
was used to specify the entry point of a program. Alex Crichton described the behaviour of it and related attributes in a 2016 comment on GitHub:
Ah yes, we've got three entry points. I.. think this is how they work:
- First,
#[start]
, the receiver ofint argc
andchar **argv
. This is literally the symbolmain
(or what is called by that symbol generated in the compiler).- Next, there's
#[lang = "start"]
. If no#[start]
exists in the crate graph then the compiler generates amain
function that calls this. This functions receives argc/argv along with a third argument that is a function pointer to the#[main]
function (defined below). Importantly,#[lang = "start"]
can be located in a library. For example it's located in the standard library (libstd).- Finally,
#[main]
, the main function for an executable. This is passed no arguments and is called by#[lang = "start"]
(if it decides to). The standard library uses this to initialize itself and then call the Rust program. This, if not specified, defaults tofn main
at the top.So to answer your question, this isn't the same as
#[start]
. To answer your other (possibly not yet asked) question, yes we have too many entry points.
QUESTION
I want to run an example via Cargo but I am facing an error:
...ANSWER
Answered 2021-Dec-14 at 14:09Update the Rust to satisfy the new edition 2021.
rustup default nightly && rustup update
Thanks to @ken.
Yes, you can use the stable
channel too!
But I love nightly
personally.
QUESTION
The following macro is from an MCAL source of a microcontroller and it converts timer ticks to milliseconds.
...ANSWER
Answered 2022-Jan-20 at 13:16The multiplication and addition are in fact pointless, as is the outer cast.
Both operators perform the usual arithmetic conversions on both operands.
For the multiplication, the left operand has type uint64
(as a result of the cast) and the right operand has type int
. Since uint64
is the larger type it will be the type of the result. The operand 1
does not change value as a result of the conversion, so in multiplying by 1
the result has the same type and value as (uint64)(x)
.
Similarly for the addition, the operands are of type uint64
and int
respectively, meaning the resulting type is uint64
, and 0
does not change value after the conversion. So by adding 0 the result has the same type and value as (uint64)(x) * 1
which has the same type and value as (uint64)(x)
.
The cast at the end is also superfluous, as the casted expression already has type uint64
. As above, the division operator performs the usual arithmetic conversions on its operands so dividing a uint64
by an int
results in a uint64
.
So the above macro is equivalent to:
QUESTION
In the documentation for Ord
, it says
Implementations must be consistent with the PartialOrd implementation [...]
That of course makes sense and can easily be archived as in the example further down:
...ANSWER
Answered 2021-Dec-26 at 00:40Apparently, there is a reference to that, in a github issue - rust-lang/rust#63104:
This conflicts with the existing blanket impl in core.
QUESTION
In the vec!
macro implementation there is this rule:
ANSWER
Answered 2021-Dec-18 at 21:03Let's go step by step to see how <[_]>::into_vec(box [$($x),+])
produces a Vec
:
[$($x),+]
expands to an array of input elements:[1, 2, 3]
box ...
puts that into aBox
.box
expressions are nightly-only syntax sugar forBox::new
:box 5
is syntax sugar forBox::new(5)
(actually it's the other way around: internallyBox::new
usesbox
, which is implemented in the compiler)<[_]>::into_vec(...)
calls theto_vec
method on a slice containing elements that have an inferred type ([_]
). Wrapping the[_]
in angled brackets is needed for syntactic reasons to call an method on a slice type. Andinto_vec
is a function that takes a boxed slice and produces aVec
:
QUESTION
I was looking at the vec![]
macro implementation in Rust and noticed it uses the __rust_force_expr!
macro. This is the implementation of the latter:
ANSWER
Answered 2021-Dec-18 at 13:05It doesn't have any result on how the macro is used, it only serves to improve the quality of error messages when the macro is used incorrectly by telling the compiler that the output of the macro is always a single expression, not an item or multiple expressions.
The specific error that this was added to improve was for using vec![]
in a pattern match, which is invalid (you can't structually match on a Vec
):
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