M3 | JavaScript Modules for Building Web Applications | Runtime Evironment library

 by   mockee JavaScript Version: Current License: No License

kandi X-RAY | M3 Summary

kandi X-RAY | M3 Summary

M3 is a JavaScript library typically used in Server, Runtime Evironment, Nodejs applications. M3 has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

JavaScript Modules for Building Web Applications.
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            kandi-support Support

              M3 has a low active ecosystem.
              It has 4 star(s) with 2 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              M3 has no issues reported. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of M3 is current.

            kandi-Quality Quality

              M3 has no bugs reported.

            kandi-Security Security

              M3 has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              M3 does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              M3 releases are not available. You will need to build from source code and install.

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            M3 Key Features

            No Key Features are available at this moment for M3.

            M3 Examples and Code Snippets

            No Code Snippets are available at this moment for M3.

            Community Discussions

            QUESTION

            SQL conditional aggregation?
            Asked 2021-Jun-16 at 03:49

            Let's say I have the following table:

            ...

            ANSWER

            Answered 2021-Jun-16 at 00:51

            Standard SQL offers listagg() to aggregate strings. So this looks something like:

            Source https://stackoverflow.com/questions/67995022

            QUESTION

            Convert interface with nullable string property to string property
            Asked 2021-Jun-15 at 18:49

            I have the following two interfaces, one which allows a nullable vin, the other that doesn't:

            ...

            ANSWER

            Answered 2021-Jun-15 at 18:49

            You can use a type predicate to define a user-defined type guard like this:

            Source https://stackoverflow.com/questions/67989014

            QUESTION

            How to disable scrolling in the main body (background) when menu is open?
            Asked 2021-Jun-13 at 17:45

            I'm basically trying to disable the main body from scrolling when I have the main menu open. I'm hoping there's a solution without JS as I'm not too familiar with it, but don't mind with some help.

            Here is my codepen, only using CSS. As you can see, the body in the background is still able to scroll when the menu is open. I need to disable that scrolling, but still be able to scroll within the menu itself. Thanks in advance!

            Codepen

            ...

            ANSWER

            Answered 2021-Jun-13 at 17:32

            Here's a hack kind of way to do it without js. What I did was I made a container div for your entire content and gave it a class .contentWrap I then added this code to your CSS:

            Source https://stackoverflow.com/questions/67960602

            QUESTION

            JS checking object/array for ALL highest values
            Asked 2021-Jun-13 at 15:12

            I know there is Math.max(), reduce(), and even for loop:

            ...

            ANSWER

            Answered 2021-Jun-13 at 13:24

            To get the highest and the objects whose value is highest, you can match it with the value. If it is greater then you can replace the value.

            You also need to maintain the dictionary i.e. dict that contains the objects.

            When inserting the value in the dict be sure to first check if the key is already present in dict or not. If it exist then just push the value else create a new array with the value.

            Source https://stackoverflow.com/questions/67958635

            QUESTION

            Spring Cassandra time out query 'SELECT * FROM system_schema.tables' timed out after PT2S
            Asked 2021-Jun-10 at 14:20

            I am using Spring Boot 2.4.4 and Spring Data Cassandra dependency to connect to the Cassandra database. During the application startup, I am getting a DriverTimeout error (I am using VPN).

            I have gone through all the Stack Overflow questions similar to this and none of them worked for me. I have cross-posted the same question on the Spring Boot official page here.

            I used below configuration properties below -

            ...

            ANSWER

            Answered 2021-Apr-23 at 08:35

            The DriverTimeoutException gets thrown when the driver doesn't get a reply from the coordinator node. It uses the basic request timeout default of 2 seconds:

            Source https://stackoverflow.com/questions/67217692

            QUESTION

            password validation regex java
            Asked 2021-Jun-05 at 16:33
            public String checkStrength(String password) {
                    String result = "";
                    //int strength = 0;
                    
                    
                  //If password contains both lower and uppercase characters, increase strength value.
                    Pattern ps = Pattern.compile("(?=.*[a-z])");
                    Pattern pl = Pattern.compile("(?=.*[A-Z])");
                    Matcher ms = ps.matcher(password);
                    Matcher ml = pl.matcher(password);
                    
                    //System.out.println(ms.matches());
                    
                    if(!ms.matches()) {
                        //strength += 1;
                        result += "lowercase letter not found\n";
                    }
                    
                    if(!ml.matches()) {
                        //strength += 1;
                        result += "uppercase letter not found\n";
                    }
                    
                    
                  //If it has numbers and characters, increase strength value.
                    Pattern p1 = Pattern.compile("(?=.*[a-z])(?=.*[A-Z])");
                    Pattern p2 = Pattern.compile("(?=.*[0-9])");
                    
                    Matcher m1 = p1.matcher(password);
                    Matcher m2 = p2.matcher(password);
                    
                    if(m1.matches() == false || m2.matches() == false) {
                        //strength += 1;
                        result += "number and character combo not found\n";
                    }
                    
                    
                  //If it has one special character, increase strength value.
                    Pattern p3 = Pattern.compile("^(?=.*[@#$%^&+=])");
                    Matcher m3 = p3.matcher(password);
                    
                    if(!m3.matches()) {
                        //strength += 1;
                        result += "special character not found\n";
                    }
                    
                    
                  //check length of password
                    if (password.length() < 8) {
                        //strength += 1;
                        result += "length must be minimum 8.\n";
                    }
                    
                    
                  //now check strength
            //        if(strength < 2) {
            //          //return "Weak";
            //        }
                    
            
                    return result;
                    
                }
            
            ...

            ANSWER

            Answered 2021-Jun-05 at 16:33

            Your pattern are incomplete. Add .+ at the end of each pattern.

            Example: change

            Source https://stackoverflow.com/questions/67851332

            QUESTION

            Logo center and menu icon on right by using flex
            Asked 2021-Jun-05 at 08:37

            How to achieve logo on center of screen and menu icon and text on right. I have searched it and shown some flex tutorials, but not getting a single way to achieve it.

            Please see this image to know how it should look like.

            ...

            ANSWER

            Answered 2021-Jun-04 at 18:50

            Reproducing the image, it would be like this.

            Source https://stackoverflow.com/questions/67842492

            QUESTION

            Importing .txt data into R
            Asked 2021-Jun-04 at 15:32

            I'm trying to import a text file into R which has several columns separated by |. Here is the first line:

            C00088591|N|M3|P|15970306895|15|IND|BURCH, MARY K.|FALLS CHURCH|VA|220424511|NORTHROP GRUMMAN|VP PROGRAM MANAGEMENT|02132015|500||2A8EE0688413416FA735|998834|||4032020151240885624

            I used read.table to read the data:

            pc <- read.table(file = source(file.choose()), header = FALSE, sep = "|")

            However I get this error message when I execute the code above:

            Error in source(file.choose()) : /Users/na/Desktop/Thesis/04_Data/Campaign contributions/indiv16/by_date/itcont_2016_10151005_20150726.txt:1:42: unexpected ',' 1: C00088591|N|M3|P|15970306895|15|IND|BURCH, ^

            I went ahead and erased the commas in the dataset but it didn't work either:

            Error in source(file.choose()) : /Users/na/Desktop/itcont_2016_10151005_20150726 copy.txt:1:43: unexpected symbol 1: C00088591|N|M3|P|15970306895|15|IND|BURCH MARY ^

            Is it because there are multiple words in a column? How could I fix this?

            ...

            ANSWER

            Answered 2021-Jun-04 at 15:31

            Remove the source function call, it doesn’t fit here (the function does something completely different).

            Source https://stackoverflow.com/questions/67839955

            QUESTION

            How to delete rows in VBA using targeted range
            Asked 2021-Jun-04 at 09:21

            I have a sheet and I need to delete rows starting from A3:M3. All rows below him should also be deleted. I'm using the code below and the entire rows now are empty.

            Any tips and tricks how to do it?

            ...

            ANSWER

            Answered 2021-Jun-04 at 09:21

            Please, try the next code:

            Source https://stackoverflow.com/questions/67834460

            QUESTION

            Why this SVG not working in the EPUB file
            Asked 2021-Jun-03 at 15:06

            I have the bellow pandoc generated xhtml in my EBUP file:

            ...

            ANSWER

            Answered 2021-Jun-03 at 01:48

            Most epub viewers that I'm familiar with use a web engine for rendering. So to get your SVG to be visible in an epub, it probably needs to be visible in a web browser.

            Trying your second SVG, I don't see anything in Chrome or Firefox. Or in a generic image viewer.

            If I add a stroke= value to your path, I see "something" in the browser, but it's a tiny little thing. As if the viewbox and/or the use settings are confusing the browser.

            Source https://stackoverflow.com/questions/67813530

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install M3

            You can download it from GitHub.

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            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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