should.js | BDD style assertions for node.js -- test framework | Functional Testing library
kandi X-RAY | should.js Summary
kandi X-RAY | should.js Summary
BDD style assertions for node.js -- test framework agnostic
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QUESTION
I am currently using Mocha and assertion library should.js
I am trying to run through a situation in my unit tests where it will throw an exception - but from looking at the documentation I haven't had much luck in getting it to work thus far.
The following block of code is currently what am working with:
...ANSWER
Answered 2019-Jul-03 at 12:41Its doing exactly what you set it up to do.
You told should, that your function should throw an exception "U wot m8". But it didnt, thus the should failed.
The expectation (the should) was that it should throw.
QUESTION
I am new to Should testing. Always used Assert but I'm trying new options.
This simple test is not working and I am curious to understand why.
Profile.js ...ANSWER
Answered 2018-Mar-26 at 10:56Yes. From should documentation
should.equal(actual, expected, [message])
Node.js standard assert.equal.
And from Nodejs documentation we know that assert.equal(...)
Tests shallow, coercive equality between the actual and expected parameters using the Abstract Equality Comparison ( == ).
Looks like you need to use eql(..)
or deepEqual(..)
. Something like
QUESTION
I have a function, which computes some stuff, notifying the user via callbacks about some events:
...ANSWER
Answered 2018-Feb-22 at 21:15First, be aware that done()
implies a synchronous test; Mocha's default is to run tests asynchronously. If you want to test the 'returned' value from asynchronous functions (functions that return a value in a callback function), you run them synchronously, via done()
.
Next, you can't return a value from an asynchronous function. These two behaviours are mutually exclusive:
QUESTION
Version 13.2.1 of the library should produces the following error when compiling with TypeScript 2.7.1 on Node 8.9.1:
...ANSWER
Answered 2018-Feb-09 at 12:02If a definition has already assigned the Assertion
interface to Object.should
globally (which it must have if you are told you are making a subsequent declaration)...
And if you have extended the original Assertion
interface....
Then you don't need to re-specify the interface in a global declaration.
Why?When you write multiple interface definitions within the same common root, they all contribute to a single type. That means your additions to an interface are included as if they were within the same code block.
ErrorsIf you get the error you mention, or if you can't see the type information you believe you added to the interface it will be because you haven't managed to hit the same common root, i.e. an interface exists in X.Y.Z
but you have added it to X.Y
.
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