tempy | Get a random temporary file or directory path | Runtime Evironment library
kandi X-RAY | tempy Summary
kandi X-RAY | tempy Summary
Get a random temporary file or directory path.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of tempy
tempy Key Features
tempy Examples and Code Snippets
Community Discussions
Trending Discussions on tempy
QUESTION
When I run my code it throws a segmentation fault and I have tried rewriting the code several times. Still to no avail, it won't even run. The segmentation fault happens as soon as my program is launched. What it's supposed to do is print a path on screen using the ncurses library in Linux, from the given coordinates. Here is the problematic snippet with the lines where gdb said the segmentation fault was, also it (snippet) reproduces the problem.
EDIT: This will help explain what I'm trying to do, but using dynamic arrays. Breadth First Search
EDIT 2: The variable frontier is supposed to keep track of the X and Y values at a specific index. The add_neighbors function is there to add all four neighbors (providing they aren't already added) to the frontier and came_from arrays.
frontier[index][0] is X value.
frontier[index][1] is Y value.
The before the first while loop I set the start position x1 and y1. During the first while loop, it increments getting the new coordinates from the frontier, then processing and adding to came_from array.
For example:
(x1,y1) (x1+1,y1)
(x1,y1+1) (x1+1,y1+1)
(x1,y2) (x2,y2)
I'm trying to get from (x1,y1) to (x2,y2). Sure hope that explains it better. What I'm trying to implement is a Breadth First Search (BFS) algorithm. Using two arrays, one is frontier (keeps track of visited positions) and came_from (keeps track of X and Y the path from x1,y1 to x2,y2). Updated the code to reflect the first answer. Plus added a comment to explain where the error might be, not really sure but I've been debugging it. It looks like the came_from array never gets set with x and y.
The Code:
...ANSWER
Answered 2021-May-23 at 17:26Some of the allocation sizes are incorrect:
frontier = malloc(sizeof(frontier) * MAXHEIGHT * MAXWIDTH);
should be
QUESTION
i'll try my best to describe what i'm trying to achieve, please correct me if there's a better way for doing so! :)
I just started practicing classes in javascript, and im trying to call an interval from a class function like this:
...ANSWER
Answered 2021-May-23 at 05:42UPDATE: Created a sandbox if anyone wanted to play around a bit more.
I would like to suggest a more manageable architecture.
Your bubble creation shouldn't be the part of a Bubble's
functionality.
Also, since your need multiple Bubble
s, you need an owner to maintain all those bubbles, so you should create an array first.
Then you can have one function that keeps running on an interval and that function should be responsible for 2 things.
- Clearing the canvas at the start of animation,
- Asking all of your
Bubble
s to play themselves.
Each Bubble
must be the owner of their process, i.e., they should have a play
function which has 2 responsibilities,
- Update the bubble's position (in your case this is random),
- Draw the bubble at the updated location.
This kind of architecture let's you easily handle complex logic by dividing responsibilities.
Run the snippet and check it out.
Ask me any doubt you have with this. I understand it can be hard to wrap around at first, but once you get it, you will never go back.
QUESTION
When I was writing the code I saw that the code would not reset the canvas to (400, 400)
after being changed to (600, 600)
. It would disorientate the canvas and stretch all the shapes with it in evaporation()
. When going through all the screens and trying to go back to reset back.
ANSWER
Answered 2021-May-19 at 19:46From the documentation for createCanvas:
Creates a canvas element in the document, and sets the dimensions of it in pixels. This method should be called only once at the start of setup. Calling createCanvas more than once in a sketch will result in very unpredictable behavior.
Instead of calling createCanvas repeatedly in your drawing functions, you should use resizeCanvas once when transitioning from one screen to another.
I couldn't actually reproduce whatever issue you were describing (partly because I could not make sense of your description). However I did also notice an issue with the variable ripple
not being declared anywhere, so I fixed that, and now the sketch appears to be working correctly.
QUESTION
I want to cover my whole website despite a small circle that follows the cursor. So I made a svg with a circle-mask that updates it's position via jquery. But now all my elements below are not clickable, because the svg lays in front of them. Is there a solution how to solve this?
...ANSWER
Answered 2021-May-10 at 13:45You can take a look at pointer-events
.
ex
QUESTION
I have a struct for a polynomial with variables x, y, and z
...ANSWER
Answered 2021-Apr-29 at 16:46Compile with full warnings (in gcc would be -Wall -Wextra
).
In this case you will see that you are not including , C allows an implicit declaration (
int (*)()
), but the behaviour is not what you want.
add the following to your code,
QUESTION
i have a dataframe with count for each year,month, and week for a type(a hue column):
...ANSWER
Answered 2021-Feb-21 at 09:41After reading your data into a pandas dataframe, first filter out only the rows required during the preferred timeframe:
QUESTION
This is my first question and I apologize if it's not posed as it should be in advance.
So, I'm trying to make the fruits (I also call them apples in code) spawn on a position that is different from the snake body just like the title says. The problem is that I don't know how to check if the coordinates of the new fruit is not equal to each of the body parts of the snake.
...ANSWER
Answered 2021-Feb-19 at 11:55I think you should have an array of all the location of body parts of snakes as any body part could do collision (As if the snake collide then it's game over).
You can use the same Array for fruit respawn just ensuring that it is not in the array.
QUESTION
I have a MIP model in CPlex.
In each iteration I use different .dat files and solve the problem.
I hold the decision variable solution values in a multi dimensional array like "Array[iteration][i]", "i" is the decision variable's index and iteration represent the different instances(different .dat files).
I want to reach "Array[1][i]" when "iteration = 2", it says "Array[1][i]= [a IloNumVar]".
...
ANSWER
Answered 2021-Jan-25 at 09:21Instead of
QUESTION
class Edge
{
public:
int v1;
int v2;
int weight;
};
class Subset
{
public:
int rank;
int parent;
};
int find(Subset* subsets,int V)
{
if(subsets[V].parent!=V)
subsets[V].parent= find(subsets,subsets[V].parent);
return subsets[V].parent;
}
void union_rank(Subset* subsets,int x,int y)
{
if(subsets[x].rank>subsets[y].rank)
subsets[y].parent=x;
else if(subsets[x].rank 1)
{
for (int v = 0; v < V; v++)
{
cheapest[v] = -1;
}
for (int i=0; i list[i].weight)
cheapest[x] = i;
if (cheapest[y] == -1 ||list[cheapest[y]].weight > list[i].weight)
cheapest[y] = i;
}
}
for (int i=0; i>V>>E;
Edge* list=new Edge[E];
for(int i=0;i>tempX>>tempY>>wt;
list[i].v1=tempX;
list[i].v2=tempY;
list[i].weight=wt;
}
//sort(list,list+E,comp);
boruvka(list,V,E);
return 0;
}
...ANSWER
Answered 2020-Dec-04 at 19:32The problem lies in this for loop
QUESTION
Can someone explain me the logic part? I kinda know it should work but I cant trace the code step by step, It doesnt make sense. Exchange among temp, pre, and Tail part is so confusing.
How does it run with the framerate? Is TailX[0] and TailY[0] always ahead? WHY? How do new tail parts get assigned in correct position? HELP ME.
...ANSWER
Answered 2020-Nov-27 at 17:05Ok so let's run through the Logic
function with different values of i
.
i
represents the number of loops to do in the Logic
function up to the length of the snake which is given by nTail
, however, it starts from 1, not 0 so it skips the first tail segment which is always set to where the head was last frame.
When the snake is just a head nTail = 0
Before you eat food, nTail
is 0 and therefore the only part of the logic that runs is:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install tempy
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page