chorus | The first editor for Spigot configurations | Plugin library
kandi X-RAY | chorus Summary
kandi X-RAY | chorus Summary
Chorus is an easy-to-use and lightweight YAML editor, created for anyone who works on Spigot-based Minecraft servers. Thanks to its features, Chorus is perfect to edit configurations quickly and easily.
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Trending Discussions on chorus
QUESTION
Suppose I have lots of audio effects into an enum:
...ANSWER
Answered 2021-May-21 at 00:11You can do that with a bit of trickery but I am not sure how useful it really is.
The main problem you will have to face it that generally you can't iterate easily through all values of an enum
. As the underlying data type for a normal enum
is integer starting you might use a simple loop for a plain enum
but this fails for any enum
where values are set manually such as
QUESTION
I am attempting to implement an answer to a slightly different question from here: How to stream video to browser with Kodi
stackoverflow user @YRabl unvoted answer, entitled "I've modified the Chorus webinterface to allow streaming with a nodejs process in the background." gives the full script as well as the required mods to the existing interface.
However I have n o clue how i would insert the .js script into the process of opening the local URL and when I attempt to simply run the script itself, it throws the following errors:
...ANSWER
Answered 2021-Apr-30 at 19:27The error you are getting is because you didn't replace the placeholder with the actual port on the last three lines of the code.
QUESTION
I have a list of files that a date has been added to the end. ex: Chorus Left Octave (consolidated) (2020_10_14 20_27_18 UTC). The files will end with .wav or .mp3
I want to leave the (consolidated)
but take out the date. I have come up with the regex and tested with regexr.com. It does format the text correctly there.
The regex is: /(\([0-9]+(.*)(?=.wav|.mp3))+/g
Now, I am trying to actually rename the files. In my terminal I have cd'ed into the folder with the files. Based on other answers here I have tried:
rename -n '/(\([0-9]+(.*)(?=.wav|.mp3))+/g' *.wav|*.mp3
- usingrename
installed with homebrewsed '/(\([0-9]+(.*))+/g' *.wav|*.mp3
for f in *.wav|*.mp3; do mv "$f" "${f/(\([0-9]+(.*)(?=.wav|.mp3))+/g}” done
The first two do not throw any errors, but do not do any renames (I know that the -n after rename
just prints out the files that will be changed, it doesn't actually change the files)
The last one starts a bash session.
I'd rather use the rename or sed, seems simpler to me. But, what am I doing wrong?.
...ANSWER
Answered 2021-Feb-24 at 01:36In plain bash
:
QUESTION
We have been given an assignment to do some basic HTML stuff. That I have completed, but I want wo go a little further. We were given a christmas song and should show it in various ways, i.e. different colors for chorus and verse, a link to the Youtube video and so on. One verse looks like this:
...ANSWER
Answered 2020-Dec-18 at 15:53Here is a "solution".
It replaces the necessary spans to identify each row.
Example:
QUESTION
I am trying to match keywords listed in one file from text in another file. The keywords file is new line separated.
grep
returns different results based on the order of the keywords (not the input file).
Here is an example.
With this input
...ANSWER
Answered 2020-Oct-13 at 19:12I found this issue in grep (BSD grep) 2.5.1-FreeBSD
(this is the default version that ships on Mac High Sierra).
Fixed by using Gnu Grep ggrep (GNU grep) 3.4.
instead.
Installed via brew install grep
.
Note that this version of grep is now called ggrep
.
QUESTION
I'm using Lucene 8.6.2 (currently the latest available) with AdoptOpenJDK 11 on Windows 10, and I'm having odd problems with the Portuguese and Brazilian Portuguese analyzers mangling the tokenization.
Let's take a simple example: the first line of the chorus from Jorge Aragão's famous samba song, "Já É", first using a org.apache.lucene.analysis.standard.StandardAnalyzer
for reference.
...Pra onde você for
ANSWER
Answered 2020-Sep-20 at 22:56Looking at the code for the PortugueseAnalyzer
and the BrazilianAnalyzer
, it looks like these analyzers are performing stemming. (I'm a little new to coding Lucene, so it's not something I expected.) So for indexing, maybe this is what the authors intended. Perhaps "você" is a stem for "você" and "vocês". And I guess "volt" is the stem of the verb (infinitive form) "voltar". (But "saudad" is not what I would expect for the stem of "saudade", but again, this aspect of text analysis is a bit new to me.)
For my particular use case, I just want to tokenize the words and skip stop words. I can't find a way to turn off stemming for the PortugueseAnalyzer
and the BrazilianAnalyzer
, so I guess I'll just use a StandardAnalyzer
but use the stop words from the language-specific analyzer, like this:
QUESTION
I am slowly working on a project which where it would be very useful if the computer could find where in an mp3 file a certain sample occurs. I would restrict this problem to meaning a fairly exact snippet of the audio, not just for example the chorus in a song on a different recording by the same band where it would become more some kind of machine learning problem. Am thinking if it has no noise added and comes from the same file, it should somehow be possible to locate the time at which it occurs without machine learning, just like grep can find the lines in a textfile where a word occurs.
In case you don't have an mp3 lying around, can set up the problem with some music available on the net which is in the public domain, so nobody complains:
...ANSWER
Answered 2020-Jun-25 at 15:55MP3 is an interesting format. The underlying data is stored in 'Frames', each 0.026 seconds long. Each frame is a Fast Fourier transform of the sound wave, encoded with varying degrees of quality depending on the size and bitrate, etc.. In your case, are you certain that the mp3s have matching bitrates? If they do, a relatively straightforward grep-style approach should be possible, given that you select on Frame boundaries. However, it is entirely likely and possible that this is not the case.
For a true solution, you need to process the mp3 file to some degree, to abstract away the encoding. However, there is no guarantee that the resulting wave match even for matching sounds, as bitrates and possibly frame alignment may differ. This small degree of chance makes it much harder.
I will give you my approach to this problem, but it is worth noting that this is not the perfect way to do things, just my best swing. Even though its the same file, there's no guarantee that frame boundaries are aligned, so I think you need to take a very wave-oriented approach, rather than a data-oriented one.
First, convert the mp3s to waves. I know that it'd be great to leave it compressed, but again I think wave-oriented is our only hope. Then, use a high-pass filter to try to remove any artifacts of audio compression that would differ between samples. Once you have two waveforms, it should be relatively straight forward to find the wavelet in the wave. You can iterate through possible starting positions and subtract the waves. When you get close to zero, you know you're close.
QUESTION
I'm using FFMPEG to produce a video consisting of a single monchrome JPG image:
...ANSWER
Answered 2020-May-30 at 11:14Your input image has only one component channel - luminance. Most players deal with H.264 streams containing three component channels - luminance or 'brightness' (Y) and two for chroma or 'color' (U & V). When the H.264 encoder encodes a luma-only stream, it stores it using a syntax which many players don't handle well. So, we tell ffmpeg to add chroma components which will have neutral values (since there's no color valence in the source) before sending it to the encoder. We'll add the most common form of YUV encoding - yuv420p.
So,
QUESTION
I have a song, as such:
...ANSWER
Answered 2020-May-18 at 05:10You can do a regex match on the entire header bracket, start with the open square bracket, and match any character other than the closing bracket. Then match for anything after the closing bracket that isn't an opening bracket to get all the text after the header.
QUESTION
Below is my text:
...ANSWER
Answered 2020-May-03 at 17:26Can use str.replace(), this will substitute all characters with the wanted one. in your case
dat.replace(',', '}')
or in case it is a list
[x.replace(',', '}') for x in dat]
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