fiscalyear | : calendar : Utilities for managing the fiscal calendar | Calendar library
kandi X-RAY | fiscalyear Summary
kandi X-RAY | fiscalyear Summary
:calendar: Utilities for managing the fiscal calendar
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Top functions reviewed by kandi - BETA
- Creates a context manager for the fiscal calendar
- Checks if the given day is in the given month
- Validate fiscal calendar parameters
- Setup the calendar
- Returns the previous fiscal quarter
- Check if quarter is out of range
- Create a new FiscalQuarter instance
- Returns the previous fiscal day
- Checks the fiscal day
- Create a new fiscal day
- Tests if this period is a leap day
- Check the year
- Create a FiscalYear instance
- Gets the next fiscal month
- Create a new FiscalMonth instance
- Return the fiscal quarter of this date
- Returns the next fiscal month
- Returns the previous fiscal month
- Returns a fiscal date time
- Returns the fiscal month
- Returns the next fiscal day
- Return the previous fiscal month
- Gets the next fiscal quarter
- Returns the fiscal year
- Returns the fiscal day of this date
- Returns the next fiscal quarter
fiscalyear Key Features
fiscalyear Examples and Code Snippets
Lines of Code : 14License : Strong Copyleft (CC BY-SA 4.0)
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ProfitAndLossBudgetOverview
2021
Accounts
Date
Account
production_year = Production.objects.filter(production_year = fiscal_year).values('seasons').annotate(total_production = Sum('production_volume'))
products = Product.objects.annotate(total_production_volume=Sum('production_product__production_volume'))
for product in products:
print(product.name, product.total_production_volume)
def get_fiscal_week(formatted_report_date):
"""
Given a date, returns the week number (from 1-53) since the last April 6th.
:param formatted_report_date: the formatted date to be converted into a
>>> import fiscalyear
>>> fiscalyear.START_MONTH = 7
>>>
>>> cur_y = fiscalyear.FiscalYear(datetime.datetime.now().year)
>>> cur_y.start.date()
datetime.date(2018, 7, 1)
>>> cur_y.end.dimport json
inp = {}
cout = {}
def flatrn_dict(inp, name, pk_name):
cop_in = inp.copy()
pkn, pkv = identify_id(cop_in)
for k, v in cop_in.items():
if type(v) == dict:
if pkv is not None:
vdef get_fiscal_year(date):
m = date.month
yy = date.year % 100
fy = None
if m > 3:
fy = f"FY{yy}-{yy+1}"
else:
fy = f"FY{yy-1}-{yy}"
return fy
df['FiscalYear'] = df['Date'].apply(lambda dt: gedf['diffval'] = df.apply(lambda x: x['diffval'] * -1 if x['GL'].str[0] in ['4', '0'] else x['diffval'], axis=1)
df['diffval'] = df.apply(lambda x: x['diffval'] * -1 if x['GL'][0] in ['4', '0'] else x['diffval'], axm=(df.pivot_table(index='PART_UNIT', columns='FiscalYear',
values='BUY_UNIT_PRICE', aggfunc='mean'))
m.pct_change(axis=1).mul(100).add(100,fill_value=0)
FiscalYear range(start, stop, step)
Community Discussions
Trending Discussions on fiscalyear
QUESTION
My fact table is following
...ANSWER
Answered 2021-May-26 at 11:16Why not join the two tables with a between condition, like Calendar.fiscalPeriod between fact.startFiscalPeriod and fact.endFiscalPeriod?
QUESTION
I wanted to change an Existing Column in SQL Server to computed and persisted without dropping the table/column.
I have an auto-incrementing ID and another column ReportID which is formatted with this computation:
ANSWER
Answered 2021-May-17 at 02:56I would think to approach this by:
- Renaming the original column
- Creating the new computed column that uses the original column and fails over to a computation if the original column has no value (is null).
Like:
QUESTION
I am trying to do a sum of a column with a distinct but seem to be getting this error:
cannot perform an aggregate function on an expression containing an aggregate or a subquery
Query that is currently working:
...ANSWER
Answered 2021-May-11 at 14:58Use conditional aggregation:
QUESTION
Here, I'm trying to get the sum of the production_volume different seasons in particular production_year: here is my models:
...ANSWER
Answered 2021-May-07 at 17:03does this help?
QUESTION
I have WTDdata table that contains ThisYearRevenue and LastYearRevenue summarized by week:
I need to create 4 more columns LastYearOnlineRevenue, LastYearStoreRevenue, ThisYearOnlineRevenue, and ThisYearStoreRevenue from another table (RevenueByDate) that looks like this:
W column in this table means Fiscal Week.
I tried using this aproach:
...ANSWER
Answered 2021-May-07 at 06:12Try this:
Since there is no way of telling the current year from the WTDdata table, I have assumed that the current year is always 2021, you can also replace that with:
VALUE ( MAX ( RevenueByDate[FiscalYear] ) )
QUESTION
I need to sum all different product's "product_volume" in one for this my model is
...ANSWER
Answered 2021-May-04 at 10:12You can use the Sum aggregation function [Django docs] to annotate the sum of the field:
QUESTION
I just installed SQL Server 2019 Express, and SSMS (18.9). I also downloaded the AdventureWorksDW2019 Database from Microsoft. I successfully set up my connection.
I've already tried doing this -> Enable IntelliSense: For all query windows, please go to Tools >> Options >> Text Editor >> Transact-SQL >> IntelliSense, and select Enable IntelliSense. For each opening query window, please go to Query >> IntelliSense Enabled. Enable statement completion: please go to Tools >> Options >> Text Editor >> Transact-SQL >> General, and check on Auto list members and Parameter information boxes. Refresh IntelliSense local cache: please go to >> Edit >> IntelliSense >>Refresh Local Cache or use the CTRL+Shift+R keyboard shortcut to refresh. Wait a minute or two for the Refresh to finish before trying again.
The Issue: I am able to select a table, right-click and 'Select Top 1000 Rows' and the query runs fine, displaying the results as expected. However, for some reason, each column is underlined red stating 'Invalid column name'.
Because of this, I am unable to use IntelliSense when writing my own queries. I have checked that the correct IntelliSense settings are checked.
See screenshots below:
...ANSWER
Answered 2021-Apr-16 at 15:13This is a known issue with SSMS 18.9, and a hotfix is currently being developed.
https://twitter.com/SysAdminDrew/status/1382869366702624774?s=20
QUESTION
I am building a Calendar Table in Biquery. How can I get Fiscal month and Year from Calendar Date in GCP BigQuery? Fiscal Year - Jul to June Below is the SQL I have so far
...ANSWER
Answered 2021-Mar-04 at 04:58SELECT
date,
extract(month from date) as calendar_month,
extract(year from date) as calendar_year,
extract(month from date_add(date, interval 6 month)) as fiscal_month,
extract(year from date_add(date, interval 6 month)) as fiscal_year,
from unnest(generate_date_array('2020-01-01', '2021-12-31', interval 1 month)) as date
order by date;
QUESTION
Good morning. I am writing a unit test to validate that my API handler is sorting the collection properly. As you can see, it's mocked data and I intentionally created the test data out of order to test the OrderBy functionality. Once the handler returns the DTO collection, I want to validate that the "act" collection is in the same order as my "expectedDTO" collection. Here's the code:
...ANSWER
Answered 2021-Mar-02 at 19:19I believe I solved the problem by using fluent assertion and adding the following line of code to test the two collections. Let me know if this is incorrect. Thanks again!
QUESTION
I have the folowing data set:
...ANSWER
Answered 2021-Feb-25 at 10:24If I understand the question correctly, you do not need grouping. You need to select only one row for each group, so using ROW_NUMBER() with the appropriate PARTITION BY and ORDER BY clauses is a possible option:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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No vulnerabilities reported
Install fiscalyear
You can use fiscalyear like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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