fizzbuzz | fizzbuzz -

 by   futoase Python Version: Current License: MIT

kandi X-RAY | fizzbuzz Summary

kandi X-RAY | fizzbuzz Summary

fizzbuzz is a Python library. fizzbuzz has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can install using 'pip install fizzbuzz' or download it from GitHub, PyPI.

fizzbuzz
Support
    Quality
      Security
        License
          Reuse

            kandi-support Support

              fizzbuzz has a low active ecosystem.
              It has 7 star(s) with 0 fork(s). There are no watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              fizzbuzz has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of fizzbuzz is current.

            kandi-Quality Quality

              fizzbuzz has 0 bugs and 0 code smells.

            kandi-Security Security

              fizzbuzz has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              fizzbuzz code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              fizzbuzz is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              fizzbuzz releases are not available. You will need to build from source code and install.
              Deployable package is available in PyPI.
              Build file is available. You can build the component from source.
              Installation instructions are not available. Examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed fizzbuzz and discovered the below as its top functions. This is intended to give you an instant insight into fizzbuzz implemented functionality, and help decide if they suit your requirements.
            • Find scripts in scripts_path
            • Generator function .
            Get all kandi verified functions for this library.

            fizzbuzz Key Features

            No Key Features are available at this moment for fizzbuzz.

            fizzbuzz Examples and Code Snippets

            Print Fizzbuzz .
            javadot img1Lines of Code : 13dot img1no licencesLicense : No License
            copy iconCopy
            public static void fizzbuzz(int n) {
            		for (int i = 1; i <= n; i++) {
            			if (i % 3 == 0 && i % 5 == 0) {
            				System.out.println("FizzBuzz");
            			} else if (i % 3 == 0) {
            				System.out.println("Fizz");
            			} else if (i % 5 == 0) {
            				System  
            Creates a FizzBuzz thread .
            javadot img2Lines of Code : 10dot img2no licencesLicense : No License
            copy iconCopy
            public static void main(String[] args) {
            		int n = 100;
            		Thread[] threads = {new FizzBuzzThread(true, true, n, "FizzBuzz"), 
            							new FizzBuzzThread(true, false, n, "Fizz"), 
            							new FizzBuzzThread(false, true, n, "Buzz"),
            							new NumberThre  

            Community Discussions

            QUESTION

            Unexpected behaviours with Raku lambdas that are supposed to be equal (I guess)
            Asked 2022-Apr-04 at 18:53

            I'm learning Raku as a passion project and I wanted to implement a simple fizzbuzz, why is join only retaining buzz if I write lambdas with pointy blocks?

            ...

            ANSWER

            Answered 2022-Mar-27 at 22:27

            Because lots of things in Raku are blocks, even things that don't look like it. In particular, this includes the "argument" to control flow like if.

            Source https://stackoverflow.com/questions/71640655

            QUESTION

            How can I return a new instance of a class as a string and use it as a parameter of a generic method?
            Asked 2022-Mar-10 at 09:29

            I have this generic method to solve the fizzbuzz quiz but when I use the class instance as a parameter to the method. I get an empty output. Can anyone help out with this.

            if input is divisible by 3 output Fizz
            divisible by 5 output = Buzz
            3 & 5 = FizzBuz<

            ...

            ANSWER

            Answered 2022-Mar-10 at 09:29

            The key is ToString() in int itemLength = item.ToString().Length;

            Let's restructure your program a little bit to see what's happening.

            Source https://stackoverflow.com/questions/71421373

            QUESTION

            MySQL idempotent version of add column failing
            Asked 2022-Feb-14 at 18:45

            MySQL here. Trying to add a column to a table in idempotent fashion. In reality it will be a SQL script that gets ran as part of an application data migration, so it will be ran over and over and I want to make sure that we only run it if the column does not already exist.

            My best attempt so far:

            ...

            ANSWER

            Answered 2022-Feb-14 at 18:45

            QUESTION

            Two Walrus Operators in one If Statement
            Asked 2022-Jan-14 at 15:44

            Is there a correct way to have two walrus operators in 1 if statement?

            ...

            ANSWER

            Answered 2022-Jan-14 at 15:44

            The issue you are having is that five is only assigned if three is True in this statement because of short circuiting:

            Source https://stackoverflow.com/questions/70698738

            QUESTION

            Apply two different colors as a gradient to different words in
          • element
          • Asked 2022-Jan-05 at 23:07

            I'm trying to render the fizz buzz function in an unordered list, with each word corresponding to a different color ('fizz'-- green, 'buzz'--blue) like so:

            I'm successfully rendering "fizz" and "buzz" in their colors on their own, but when it comes to rendering the "fizzbuzz" line, the entire background of the

          • is split between green and blue instead of only the individual words.

            Here's the css selector responsible for "fizzbuzz":

            ...
          • ANSWER

            Answered 2022-Jan-05 at 23:07

            add width:fit-content;

            Source https://stackoverflow.com/questions/70600618

            QUESTION

            Return string variable in map without cloning
            Asked 2021-Dec-30 at 23:33

            I'm writing a simple fizzbuzz in Rust:

            ...

            ANSWER

            Answered 2021-Dec-30 at 21:48

            QUESTION

            Is there a way to force non-lazy evaluation of && and || in Ruby?
            Asked 2021-Dec-28 at 21:10

            I was playing with the FizzBuzz programming exercise this evening, trying out different ways of writing solutions.

            One line which I wrote was:

            nf = !((ff = i % 3 == 0) || (bf = i % 5 == 0))

            nf is "No flag"

            ff is "Fizz flag"

            bf is "Buzz flag"

            Now I know this is horrible style - I have far better solutions to the original problem - but this one also doesn't work because Ruby's lazy evaluation of || expressions means that if i is a multiple of 3, ff is set to true and bf is left as nil (although it is defined because that happens before the evaluation).

            What I've been hunting for without success is a way to make Ruby evaluate both sides of the || (or another operator) so that all three flags get their correct values.

            Is there a way of doing it in Ruby?

            ...

            ANSWER

            Answered 2021-Dec-28 at 21:10

            Perhaps you're looking for the | and & operators which do not short-circuit.

            E.g.:

            Source https://stackoverflow.com/questions/70512459

            QUESTION

            How do I redirect input and output in VSC python code?
            Asked 2021-Dec-27 at 08:12

            I have tried the "<" and ">" commands but vsc still uses the terminal.

            My launch.json:

            ...

            ANSWER

            Answered 2021-Dec-27 at 08:12

            As you have discovered the < is nicely put inside quotes by the ms-python extension and thus the shell will not see it as a redirect.

            It can be done but requires a bit of configuration.

            You have to setup the debug client and server yourself.

            The debug server is setup as a task. The client is an attach launch configuration.

            First you need to find the location of the debugpy module that is part of the ms-python extension (you can install as a separate module in your environment but why if you already have it).

            I use the following 2 files:

            redir_input.py

            Source https://stackoverflow.com/questions/70485256

            QUESTION

            Is there anyway to clear a textarea without using an onclick function?
            Asked 2021-Dec-16 at 06:29

            I want to achieve an automatic clear and display another value corresponds to new inputted data

            This is my html code for input data and text area

            ...

            ANSWER

            Answered 2021-Dec-16 at 05:39

            As far as I can see here, there isn't a way to clear a textarea without using an onclick function.

            Source https://stackoverflow.com/questions/70374263

            QUESTION

            Conditionally modifying collections inline using Java Streams
            Asked 2021-Dec-08 at 22:52

            Java 11 here. I have a 2 List instances, latest and current. The "latest" list is the list of latest Fizzbuzzes, hot off the press. The "current" list is the list of Fizbuzzes that I have in my database. I am comparing these lists.

            I need to compare these lists and create a 3rd list, additions, which contains any Fizzbuzzes from the latest list that are not found inside the current list. Its a list of "new" Fizzbuzzes that the database does not have on record.

            Furthermore, I need to set each addition's processedAt field (Instant) to the same current date/time. I'd like to try and accomplish this all inline using the Java Stream API. I can accomplish this the "old fashioned" way:

            ...

            ANSWER

            Answered 2021-Dec-08 at 17:41

            You may use Stream.peek, it allows to apply an operation on each element and doesn't keep the result (if there is any) and resume the stream

            Source https://stackoverflow.com/questions/70279380

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install fizzbuzz

            You can install using 'pip install fizzbuzz' or download it from GitHub, PyPI.
            You can use fizzbuzz like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

            Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items

            Find more libraries
            CLONE
          • HTTPS

            https://github.com/futoase/fizzbuzz.git

          • CLI

            gh repo clone futoase/fizzbuzz

          • sshUrl

            git@github.com:futoase/fizzbuzz.git

          • Stay Updated

            Subscribe to our newsletter for trending solutions and developer bootcamps

            Agree to Sign up and Terms & Conditions

            Share this Page

            share link