buzz | linguistics tool for parsing and then exploring plain | Natural Language Processing library
kandi X-RAY | buzz Summary
kandi X-RAY | buzz Summary
buzz is a linguistics tool for parsing and then exploring plain or metadata-rich text. This README provides an overview of functionality. Visit the full documentation for a more complete user guide.
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Top functions reviewed by kandi - BETA
- Run the search
- Return tqdm progress bar
- Perform depgrep on the corpus
- Perform a depgrep query
- Create a content table from the content table
- Make a match column from a dataframe
- Convert a series to a wordlist
- Joins the entity_info
- Compute the cosine similarity between two datasets
- Read a list of files
- Toggles the header row
- Convert Python objects to unicode
- Create a DashSite instance
- Convert a pandas DataFrame to a figure
- Toggle column width mode
- Read files
- Generate a WordCloud object from the query
- Move the page left
- Move the page right
- Search for valid characters
- Start search
- Return a pandas DataFrame with the given deprep_query
- Get the entity for the given entity
- Display information about the window
- Define keys
- Show a cell
- Parse command line arguments
buzz Key Features
buzz Examples and Code Snippets
Community Discussions
Trending Discussions on buzz
QUESTION
while (scanFile.hasNext() == true)
{
word = scanFile.next();
int length = word.length();
for (i=0; iANSWER
Answered 2021-Jun-14 at 00:11Your nested loop used the same loop variable. Change
QUESTION
So I have a hackerRank different type of fizzBuzz function that is as follows:
The only constraints:
0 < n < 2 x 10^5.
But for simplicity, I am not using the constraints here so the answer won't be so big. Here it is:
if n is multiple by both 5 and 3 print('FizzBuzz')
if n is multiple by 3(but not 5) print('Fizz')
if n is multiple by 5(but not 3) print('Buzz')
if n is neither print(n)
The prints should be one value per line
So far ok, here is the code I wrote in Python 3
...ANSWER
Answered 2021-Jun-13 at 15:20As you can see this is the same evaluation as your code but with optimized approach, FizzBuzz questions are to test on how to write an efficient algorithm. Just because the code is working it doesn't mean it shouldn't be optimized.
In here you can see I'm checking every interval and appending the string by words. If you use modulo(%) operator, then it uses more cpu clocks, I know it is nothing for current generation computers, but it's good practice with problems like this
QUESTION
I'm new to Combine and I'm trying to understand it by solving the "old" problems
My goal is to make the process cancelable, but even I called the .cancel() method right after (or with sort delay) the printFizzbuzz() method, the code still keeping running(around 3 secs) until finishing
I've tried the code below in the new Xcode project, still the same
...ANSWER
Answered 2021-Jun-06 at 21:57The problem is that your publisher is too artificially crude: it is not asynchronous. An array publisher just publishes all its values at once, so you are canceling too late; and you are blocking the main thread. Use something like a timer publisher instead, or use a flatmap with a delay and backpressure.
QUESTION
I have the following code in Elixir:
...ANSWER
Answered 2021-Jun-12 at 14:14One cannot pipe to an anonymouse function. Also, you want to pipe values, one by one, not the whole range, so you need an iterator there.
Use function capture &/1:
QUESTION
I am somewhat new to Javascript so I'll try my best to explain this properly. I'm using vanilla JS on the fizz buzz loop, but I'm trying to do it slightly differently, I think.
I've put both sets of numbers in 2 separate arrays, and successfully did it with a for loop by counting up to 20, but I didn't use the arrays to do it. However, I want to use the variables passed as arguments to check if the values are true so the appropriate response can be printed, either fizz, buzz, or fizzbuzz.
My code for the for loop is:
ANSWER
Answered 2021-Jun-07 at 21:14You can test if the number you're iterating is inside of any of the arrays with the function some. For example,
QUESTION
library(dplyr)
library(data.table)
library(readxl)
macro <-
list()
macro$filepath <-
'C:\\Users\\TMC\\Documents'
macro$file <-
list.files(
macro$filepath,
pattern = 'EventData.xlsx',
full.names = TRUE)
macro$sheet <-
'FY21'
macro$first_dt <-
'2021-02-01' %>% as.Date
dat <-
macro$file[regexpr('~', macro$file) < 0] %>%
read_xlsx(., sheet = macro$sheet) %>%
data.table
dat <-
dat[!(DESCRIPTION %in% 'AEG')]
macro$keep <-
c(
'Product vs. buzz',
'CATEGORY',
'JUN',
'JUL',
'AUG',
'SEP',
'OCT',
'NOV',
'DEC',
'JAN',
'FEB',
'MAR',
'APR',
'MAY')
dat <-
dat[
,
intersect(macro$keep, dat %>% names),
with = FALSE]
setnames(
dat,
c('Product vs. buzz', 'CATEGORY'),
c('evt_type', 'raw'))
dat[, raw := (raw %>% tolower)]
##ISSUE IS HERE
macro$category <-
list.files(
macro$filepath,
pattern = 'BrandEventCategoryMapping',
full.names = TRUE) %>%
read_xlsx %>%
data.table
ANSWER
Answered 2021-Jun-09 at 02:58list.files returns multiple filenames. You cannot read all of them in one single read_xlsx. You may need to use lapply/map to read the files.
QUESTION
I'm writing a function that takes three optional arguments from the console.
...ANSWER
Answered 2021-May-31 at 15:31Check out the argparse module:
QUESTION
I write program to solve several problems with numbers. My program should:
Welcome users;
Display the instructions;
Ask for a request;
Terminate the program if a user enters zero;
List item
If a number is not natural, print an error message;
Print the properties of the natural number;
Continue execution from step 3, after the request has been processed.
I got an error:
The program should continue to work till the user enter 0.
Here is my code:
...ANSWER
Answered 2021-May-27 at 10:09You are just a loop away from getting the desired output, below is the code with comments to understand properly. Also, I have commented the code which you wrote but I removed from there.
QUESTION
I have a large dataframe. Column A has website names, and Column B has all the IDs that visit that website. So - if a website has 100,000 visitors, there will be 100,000 rows for Website A, etc.
I want to get the overlap between all pairs of these websites - so, to understand how many people visit A&B, A&C, C&B, etc.
Sample data
...ANSWER
Answered 2021-May-20 at 15:00To get the total number of visitors to each website you can use GroupBy.size:
QUESTION
In the code below I am using a v-autocomplete component
and a variable select where the selected value is stored.
The watch logs the value and type of select.
The problem I'm facing is that when the text typed in the v-autocomplete is cleared, select defaults to null instead of an empty string.
Is there any way to revert select to an empty string instead of a null object?
ANSWER
Answered 2021-May-24 at 14:25v-model='select' is a shorthand for :value="select" and @input="select = $event". Thus, if you want to customize the behaviour of emitted @input event, you can write it in expanded form.
In below snippet, when the input value changes, you assign it to select if it is not null, or assign an empty string otherwise.
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