fifolock | flexible low-level tool | Reactive Programming library
kandi X-RAY | fifolock Summary
kandi X-RAY | fifolock Summary
A flexible low-level tool to make synchronisation primitives in asyncio Python. As the name suggests, locks are granted strictly in the order requested: first-in-first-out; and are not reentrant.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Wait for all waiters .
- A context manager .
- Initialize the lock .
- Get the long description of the README . md file .
- Acquire the lock mode .
- Returns a _FifoLockContext manager .
fifolock Key Features
fifolock Examples and Code Snippets
Lines of Code : 24License : Permissive (MIT)
Copyimport asyncio
from fifolock import FifoLock
class Read(asyncio.Future):
@staticmethod
def is_compatible(holds):
return not holds[Write]
class Write(asyncio.Future):
@staticmethod
def is_compatible(holds):
return no import asyncio
from fifolock import FifoLock
class SemaphoreBase(asyncio.Future):
@classmethod
def is_compatible(cls, holds):
return holds[cls] < cls.size
lock = FifoLock()
Semaphore = type('Semaphore', (SemaphoreBase, ), {'siz import asyncio
from fifolock import FifoLock
class Mutex(asyncio.Future):
@staticmethod
def is_compatible(holds):
return not holds[Mutex]
lock = FifoLock()
async def access():
async with lock(Mutex):
# access resource Community Discussions
Trending Discussions on fifolock
QUESTION
For school I am working on a project that has 2 reading threads running and 1 writing thread that work around a shared buffer. This shared buffer is some sort of pointer based list that we programmed ourselves. To make it thread-safe I used to pthread_rw_locks and also some pthread_barriers. When i tried to run my code it crashed almost instantly and it gave me a segmentation fault. When using the gdb debugger it gave me the following message:
program received signal SIGSEGV, Segmentation fault.
__pthread_barrier_init (barrier=0x0, attr=0x0, count=2) at pthread_barrier_init.c:47
47 pthread_barrier_init.c: No such file or directory.
When compiling I included the -lpthread flag and I also made sure to include the pthread.h in every file where it was used. Any idea why my program can't find this c file?
EDIT
This is a snippet of the code that I use. (This is barely all code but it goes wrong in this part)
This is my code for the main loop
...ANSWER
Answered 2022-Jan-04 at 16:19The error is not an error, just a warning, and it’s not issued by your program, but by the debugger. The debugger tried to help you by displaying the source file where the crash happened. Alas, that source file is not a part of your program, but a part of pthreads library. Since it’s not available, the debugger informs you of this fact, since otherwise you’d expect to see the source line where the problem manifested. gdb has a “show source line” function that gets invoked after a signal/exception is raised, and that function will always print something: either the source line, or an warning message.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install fifolock
You can use fifolock like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
