pyston | A faster and highly-compatible implementation of the Python programming language

by pyston Python Version: pyston_2.3.5 License: Non-SPDX

X-Ray Key Features Code Snippets(1)Community Discussions(2)Vulnerabilities Install Support

kandi X-RAY | pyston Summary

pyston is a Python library typically used in Debian applications. pyston has no bugs, it has no vulnerabilities, it has build file available and it has medium support. However pyston has a Non-SPDX License. You can download it from GitHub.

Pyston is a fork of CPython 3.8.8 with additional optimizations for performance. It is targeted at large real-world applications such as web serving, delivering up to a 30% speedup with no development work required.

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Quality

Security

License

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Support

pyston has a medium active ecosystem.

It has 2399 star(s) with 88 fork(s). There are 36 watchers for this library.

It had no major release in the last 12 months.

There are 33 open issues and 55 have been closed. On average issues are closed in 65 days. There are 13 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of pyston is pyston_2.3.5

Quality

pyston has 0 bugs and 0 code smells.

Security

pyston has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

pyston code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

pyston has a Non-SPDX License.

Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

Reuse

pyston releases are available to install and integrate.

Build file is available. You can build the component from source.

Installation instructions, examples and code snippets are available.

It has 589420 lines of code, 54905 functions and 2022 files.

It has medium code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed pyston and discovered the below as its top functions. This is intended to give you an instant insight into pyston implemented functionality, and help decide if they suit your requirements.

Get the output templates for a function
processes a module
Setup UI .
Create the general page .
Checks if a given BerkeleyDB version is available .
loading the classes
Returns the MD5 diff between lines .
Build the universal python python library .
Create the page highlight .
Parse the message .

Get all kandi verified functions for this library.

pyston Key Features

No Key Features are available at this moment for pyston.

pyston Examples and Code Snippets

EmbeddedPyston,Overview

Lines of Code : 11

License : Strong Copyleft (GPL-3.0)

Copy

// Pyston
#include "Libraries/Pyston/Python.h"

// Initialises the Pyston interpreter.
Py_Initialize();

meow = 'Meow!' 
print(meow)

PyRun_SimpleString("meow = 'Meow!' \n print(meow)");

PyRun_SimpleString("meow = 'Meow!'");

PyRun_SimpleString("pri

Community Discussions

Trending Discussions on pyston

Exuberant ctags ignores python-kinds option

In Python how do I test if the interpreter is running Pyston, Jython, CPython?

QUESTION

Exuberant ctags ignores python-kinds option

Asked 2017-Sep-23 at 04:01

I'm trying to generate a ctags file for the Python standard library, so that I can add it to my Python projects to get correct tagging/highlighting for standard library functions. I don't want to generate tags for variables, since that would make the tags file huge and I really only care about function and class names. However, Exuberant Ctags seems to be ignoring all my requests to disable variable tagging, and still produces a tags file containing lots of entries of kind:v.

This is how I run Exuberant Ctags:

...

ANSWER

Answered 2017-Sep-23 at 04:01

This is a bug of Exuberant Ctag and you can use universal-ctags instead.

This bug has already been fixed in universal-ctags.

Source https://stackoverflow.com/questions/46203565

QUESTION

In Python how do I test if the interpreter is running Pyston, Jython, CPython?

Asked 2017-Aug-15 at 14:59

I would like to test from inside a running Python program if the interpreter is running pyston, jython, ironpython, pypy and so on.

The things that come to mind are pattern matching on system.version and checking the magic number from imp.get_magic() But both of these seem a little frail and hacky. Any other suggestions?

Edit: user2357112 comes through again.

I tried running the following code on every Python version I had installed, and this differentiates Jython, Pyston, and various CPythons. Where it falls down is in Python before 2.6, and the anaconda variant of CPython. For anaconda, that may be the right thing though.

Here is the program and the results. Feel free note which other kinds of Python this does or does not work on.

...

ANSWER

Answered 2017-Aug-15 at 02:25

As user2357112 mentioned, you can check platform.python_implementation() == "Pyston", as you can see in the source.

Source https://stackoverflow.com/questions/45685549

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install pyston

Pyston has the following build dependencies:.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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