s3label | based tool for rapidly labeling images | Data Labeling library

by stonethree Python Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(3)Vulnerabilities Install Support

kandi X-RAY | s3label Summary

s3label is a Python library typically used in Artificial Intelligence, Data Labeling, Deep Learning applications. s3label has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. However s3label build file is not available. You can download it from GitHub.

S3Label is an open-source browser-based image labeling tool developed by Stone Three, a company in South Africa. The goal of S3Label is to speed up the labeling of images for use in machine learning. It is particularly focused on instance segmentation, semantic segmentation and keypoints, although could easily be extended to classification and other types of labeling tasks too.

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Quality

Security

License

Reuse

Support

s3label has a low active ecosystem.

It has 8 star(s) with 3 fork(s). There are 6 watchers for this library.

It had no major release in the last 6 months.

There are 29 open issues and 23 have been closed. On average issues are closed in 45 days. There are 21 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of s3label is current.

Quality

s3label has no bugs reported.

Security

s3label has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

s3label is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

s3label releases are not available. You will need to build from source code and install.

s3label has no build file. You will be need to create the build yourself to build the component from source.

Top functions reviewed by kandi - BETA

kandi has reviewed s3label and discovered the below as its top functions. This is intended to give you an instant insight into s3label implemented functionality, and help decide if they suit your requirements.

Creates a new label for the given user
Get the label of a given label
Get the last user input data
Get all data for all user input data
Create a Flask application
Configure logging
Get the next input data item from the database
Get all user input data
Deploy the frontend
Install npm modules
Deploy the S3 backend
Update the virtualenv
Get the first user input data
Return a data item for a given user and label task
Retrieve all the data in the given user data item
Retrieve the next input data item from the database

Get all kandi verified functions for this library.

s3label Key Features

No Key Features are available at this moment for s3label.

s3label Examples and Code Snippets

No Code Snippets are available at this moment for s3label.

Community Discussions

Trending Discussions on Data Labeling

How can I do this split process in Python?

Replacing a character with a space and dividing the string into two words in R

Azure ML FileDataset registers, but cannot be accessed for Data Labeling project

QUESTION

How can I do this split process in Python?

Asked 2021-Dec-30 at 14:06

I'm trying to make a data labeling in a table, and I need to do it in such a way that, in each row, the index is repeated, however, that in each column there is another Enum class.

What I've done so far is make this representation with the same enumerator class.

A solution using the column separately as a list would also be possible. But what would be the best way to resolve this?

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ANSWER

Answered 2021-Dec-30 at 13:57

Instead of using Enum you can use a dict mapping. You can avoid loops if you flatten your dataframe:

Source https://stackoverflow.com/questions/70532286

QUESTION

Replacing a character with a space and dividing the string into two words in R

Asked 2020-Nov-18 at 07:32

I have a dataframe that contains a column that includes strings separeted with semi-colons and it is followed by a space. But unfortunately in some of the strings there is a semi-colon that is not followed by a space.

In this case, This is what i'd like to do: If there is a space after the semi-colon we do not need a change. However if there are letters before and after the semi-colon, we should change semi-colon with space

i have this:

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ANSWER

Answered 2020-Nov-16 at 07:24

Try something like:

Source https://stackoverflow.com/questions/64853962

QUESTION

Azure ML FileDataset registers, but cannot be accessed for Data Labeling project

Asked 2020-Oct-28 at 20:31

Objective: Generate a down-sampled FileDataset using random sampling from a larger FileDataset to be used in a Data Labeling project.

Details: I have a large FileDataset containing millions of images. Each filename contains details about the 'section' it was taken from. A section may contain thousands of images. I want to randomly select a specific number of sections and all the images associated with those sections. Then register the sample as a new dataset.

Please note that the code below is not a direct copy and paste as there are elements such as filepaths and variables that have been renamed for confidentiality reasons.

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ANSWER

Answered 2020-Oct-27 at 22:39

Is the data behind virtual network by any chance?

Source https://stackoverflow.com/questions/64546521

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install s3label

You can download it from GitHub.
You can use s3label like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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