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kandi X-RAY | chef Summary
kandi X-RAY | chef Summary
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Top functions reviewed by kandi - BETA
- Create a new listener for listening sockets .
- Parse the command line options
- Runs the repo
- Verify that the command should be executed
- Creates a new instance .
- Compute a measure
- Stop the server .
- Read a string from the UTF - 8 bytes
- Returns the current node .
- Executes the given argument with the given arguments .
chef Key Features
chef Examples and Code Snippets
Community Discussions
Trending Discussions on chef
QUESTION
I have this Js function with hard coded filter parameters. It filter all the buckets sub objects when key start with a string from a given list. For now i havent found a way to put this list as an array...
...ANSWER
Answered 2022-Jan-25 at 16:55Use array.every()
to check all the elements of the array.
QUESTION
I need to parse a string to get desired number and position form a string, for example:
...ANSWER
Answered 2022-Jan-17 at 15:05Together with re.MULTILINE
you can do everything in one regex, that will also split everything correctly:
QUESTION
I use node-template to practise the tutorials.
I have finished the start a private network and Permissioned Network. At the end, I can see Charlie joined the network as a full node. I want to go further, I try to make Charlie to be an authority node, I want to make Charlie's role the same as Alice's and Bob's.
I want to let a node automatically joined and became an validator to generate blocks and finalize blocks.
Previously, Charlie runs as :
...ANSWER
Answered 2022-Jan-03 at 15:22I got an answer substrate-validator-set. If you want to dynamically add validator on a PoA network, you need to add a session pallet, and let session to manage the auro key and grandpa key.
QUESTION
So lets say, I have the following dataframe.
...ANSWER
Answered 2021-Dec-29 at 23:29rachefs = df[~(df["Name"] == "RACHEL") | ~(df["Job"] == "CHEF")]
QUESTION
I have a node with the following json in chef nodes:
...ANSWER
Answered 2021-Dec-04 at 03:01Like with other Chef artifacts, nodes can also be updated from file using the from file
argument.
Instead of knife node edit
, you need to run:
QUESTION
Take a class hierarchy Chef extends Person extends GraphNode
, where each parent class is generic in an interface T
that extends the interface of its parent class. The uppermost (abstract) class defines a method accepting as its argument a subset of the keys of T
.
I'm seeing an error (highlighted below) when keys are a subset derived from T
. When the derived keys are exactly keyof T
, the code works as expected. As far as I can tell both should work – and it's notable that it does work in the final class Chef
, which is not generic.
Inheritance extensions are not behaving as I'd expect, have I missed something there?
...ANSWER
Answered 2021-Dec-02 at 16:32The generic type LiteralKeys
defined like
QUESTION
I'm need to do the producer consumer problem in c++, solve for 1 consumer and 6 producer, and for 1 producer and 6 consumer, below is the statement of the question.
Question 1: Imagine that you are waiting for some friends in a very busy restaurant and you are watching the staff, who wait on tables, bring food from the kitchen to their tables. This is an example of the classic "Producer-Consumer'' problem. There is a limit on servers and meals are constantly produced by the kitchen. Consider then that there is a limit on servers (consumers) and an "unlimited" supply of meals being produced by chefs (producers).
One approach to facilitate identification and thus reduce to a "producer-consumer" problem is to limit the number of consumers and thus limit the infinite number of meals. produced in the kitchen. Thus, the existence of a traffic light is suggested to control the production order of the meals that will be taken by the attendants.
The procedure would be something like:
- Create a semaphore;
- Create the server and chef threads;
- Produce as many meals as you can and keep a record of how many meals are in the queue;
- The server thread will run until it manages to deliver all the meals produced in the tables; and
- Threads must be "joined" with the main thread.
Also consider that there are 6 chefs and 1 attendant. If you want, you can consider that a chef takes 50 microseconds to produce a meal and the server takes 10 microseconds to deliver the meal on the table. Set a maximum number of customers to serve. Print on the screen, at the end of the execution, which chef is most and least idle and how many meals each chef has produced.
Question 2: Considering the restaurant described above. Now consider that there are 1 chef and 6 attendants. Assume that a chef takes 50 microseconds to produce a meal and the server takes 15 microseconds to deliver the meal to the table. Set a maximum number of customers to serve. Print which server is the most and least idle and how many meals each server has delivered.
I managed to solve for 6 producers and 1 consumer, but for 6 consumers and 1 producer it's not working, it seems that the program gets stuck in some DeadLock. I'm grateful if anyone knows how to help.
...ANSWER
Answered 2021-Nov-15 at 15:44The same exact bug exists in both the consumer and the producer function. I'll explain one of them, and the same bug must also be fixed in the other one.
QUESTION
Lets say we have an array of objects and we loop through it and create a div in every iteration.
How could we take the property ol
(which is also an array of objects) in every iteration and create an
- inside the div for every object in it, with as many
's as the number in the property
li
. Also, text inside theli
should be the text of the propertytitle
so it should look like this:I'm hitting my head to solve it but my noobness doesn't let me. I tried another loop of the
...ol
object inside the outer loop, but I cant get it right.
ANSWER
Answered 2021-Oct-05 at 08:54To do what you require you can use map()
to loop through the ol
array of each object and create a HTML string which can be appended to the div you create.
Note the use of fill()
in the example below to create the required number of li
elements with the same content.
Also note that the same approach can be used to both tidy the code and improve performance as it means you only append to the DOM once when the loop completes, instead of within each loop iteration.
Try this:
QUESTION
Hello everyone I'm having a hard time trying to understand how to make this work.
I have 8 different divs, each one with an img used as button and same class (tm-img) and hidden divs with additional info. What I want is to have displayed only the img at the beginnig and when the user clicks one of the 8 images depending on the one they clicked the hidden divs from that image show. (Whats happening now is tha if I click on one image all hidden divs from all images show not just the one I clicked)
...ANSWER
Answered 2021-Oct-01 at 22:17You can do something like in below snippet . Use the this
keyword so that the clicked element is triggered not all .
You can also
for
loop to run through all tags and trigger(toggle) clicked event
QUESTION
I want to create symbolic link only if its not present
I have written below recipe
...ANSWER
Answered 2021-Sep-04 at 04:02The link resource is idempotent in nature, and shouldn't change if the link is already present.
However, for some reason if you want to skip the step, we can use symlink?
method from Ruby's File class. This method returns true/false
based on whether the target path is a link or not.
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