kay | Experimental high-performance actor system framework
kandi X-RAY | kay Summary
kandi X-RAY | kay Summary
kay can be transparently and trivially scaled onto... kay is inspired by Data-Oriented Game Development, Erlang and the original ideas behind Object-Orientedness. It is thus named after Alan Kay.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of kay
kay Key Features
kay Examples and Code Snippets
Lines of Code : 57
License : No License
Copy
def decorator_apply(dec, func):
"""
Decorate a function by preserving the signature even if dec
is not a signature-preserving decorator.
"""
return FunctionMaker.create(
func, 'return decfunc(%(shortsignature)s)',
Community Discussions
Trending Discussions on kay
QUESTION
I'm hoping someone can help me out. I have created a table and have multiple Tabs. Each Tab has different data inside the table. Each table row has a column with a number of votes and I want to sort the rows automatically with the columns that have more votes at the top.
This is my HTML code:
...ANSWER
Answered 2021-Jun-03 at 03:04Having separate arrays for each tab(comedy and horror) worked for me, so you just create a second array and duplicate the javascript functions, using more specific JS selectors.
QUESTION
I'm trying to create a directed graph with my Javascript code which I created. By clicking on a node, the list of publications assigned to a keyword should be called up. The currently selected node should be highlighted in the visualisation. The details should be shown on a separate grey area which i created:
...ANSWER
Answered 2021-May-30 at 16:05The error means that persona[keyName] is undefined. We are not given declaration of persona array to make better research.
QUESTION
I would like to create a graph. To do this, I have created a JSON file. The Skills (java, python, HTML, json) should be the links and the index (KayO, BenBeck) should be the nodes. Also the node must not fall below a certain minimum size and must not become too large.
After that, I would like to be able to call up the list of publications on the right-hand side by clicking on the node. The currently selected node in the visualisation should be highlighted.
I have already implemented from this example (https://bl.ocks.org/heybignick/3faf257bbbbc7743bb72310d03b86ee8). But unfortunately I can't get any further.
The error message I always get is:
Uncaught TypeError: Cannot read property 'json' of undefined
This is what my issue currently looks like:
The JSON file:
...ANSWER
Answered 2021-May-15 at 14:59Your JSON file should be of format:
QUESTION
Recently I started using a flat file manager called Cardbox to maintain lists of my film and music collections. Cardbox outputs records in both CSV and XML formats and I use the latter to create web pages so that I can easily proofread my work. I would like to convert it to a form of XML that uses the field names as elements rather than as attributes of a common element and eliminates the ... tags. The software will accept an XSLT transform to do this.
Here is an example of what I would like to do.
...ANSWER
Answered 2021-May-10 at 01:23What am I missing
You are missing the fact that your XML puts its elements in a namespace. As a result, your templates do not match anything, and the entire output is produced by the built-in template rules. See https://stackoverflow.com/a/34762628/3016153 how to handle this.
The other thing is that there is no need to list each field and its name explicitly in the stylesheet. You can construct a more dynamic stylesheet that can handle any number of fields, with any names (as long as the names are also valid element names):
XSLT 1.0
QUESTION
Had this commit yesterday where the process would go straight to Heroku's memory limit giving me an R15 error - It worked really well in my testing and also on heroku until it gets to a random number of checked items, at which it throws the error. The interesting part is that right after the error, i get another R15 one, which says i am using only 22.2% of available memory.
Here is the code giving me the error:
...ANSWER
Answered 2021-Apr-23 at 10:27Apparently, denying javascript requests was the solution to this - even though it's not perfect and some sites may require javascript to run, this one was the exception. Just update the config function (which I forgot to include) that blocked images and css, to block js as well.
Here is how that function looks now
QUESTION
Given the string below,
...ANSWER
Answered 2021-Apr-17 at 19:41(?:foo|\G(?!^))(\d+).*?(?=(\w+))\w+(?=\1\b)
It could be some size or performance optimization.
@Niko Gambt, say if any optimization is important for you.
QUESTION
Want to obtain the xpath for the elements from a drop-down menu (refer the image),
Tried with the following,
.//div[@class='styles__dropDownList___1PunQ styles__dropDownList___2fbeV'] with this only the drop down is getting selected
No luck with,
.//div[@class='styles__dropDownList___1PunQ styles__dropDownList___2fbeV' and data-test-id='option_0']//div[@class='styles__dropDownList___1PunQ styles__dropDownList___2fbeV' and text()='Hyg']//div[@class='styles__dropDownList___1PunQ styles__dropDownList___2fbeV' and contains(@text,'Hyg')]
Element Section:
...ANSWER
Answered 2021-Apr-08 at 11:41To click the desired element you should first open the dropdown box by clicking on it and after that to click on the element.
Since you can select it uniquely only according to the text the element contains you should use //div[contains(text(),'Hyg')] or //div[text()='Hyg']
QUESTION
Hello so I am making a password manager and I want to encrypt the password file, so I generate and create the first password and when I read it and decrypt it reads it. And then when making another password it creates it but then when decrypting it throws an error. From what I can see I am using the same key. Here is the code:
...ANSWER
Answered 2021-Mar-26 at 08:12The problem is that you take input of user for chosen account password then you append splitter and random generated password then '/n'. After that you encrypt this var using fernet. This method will work to view your first password since with first password you read and decrypt whole file but not with multiple encrypted passwords since each var encryption is unique (having different IV) which means that to decrypt all the passwords you will need a way to signal the end of an encrypted password and beginning of another encrypted password so that you pass to ferent the correct ciphertext with correct margins. This can be done by simply adding --END OF PASSWORD-- after each encryption write to password file. Then during reading of passwords you can just split pass file on these margins and pass result to fernet.
NOTE: dont use this code as your password manager since although you encrypt your passwords you are leaving your master password in mykey.key unencrypted which makes this totally useless.
QUESTION
I need to compare xml files from two folders and collect those xml elements that only show up in one of the xml file.
The xml files in two folder has same file name. Below is the sample of what I want to do:
old/booklist1.xml
...ANSWER
Answered 2021-Mar-26 at 04:17The below xsl code works well for my problem:
QUESTION
I have 1000 points of county name data. (ok_field) Also, there are weather data for 1 to 10 days. (m) This data is a datalist.
(The size of the data is so large that if you use the data below as an example, I am grateful!)
...ANSWER
Answered 2021-Mar-11 at 06:50This uses a loop to populate the data frame that you desire.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install kay
Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
