xtract | deserialize XML to user types
kandi X-RAY | xtract Summary
kandi X-RAY | xtract Summary
Xtract is a scala library for deserializing XML. It is heavily inspired by the combinators in the Play JSON library, in particular the Reads[T] class. See the introductory blog post.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of xtract
xtract Key Features
xtract Examples and Code Snippets
"com.lucidchart" %% "xtract" % "2.2.1"
"com.lucidchart" %% "xtract-testing" % "2.2.1" % "test"
Community Discussions
Trending Discussions on xtract
QUESTION
I've been trying to use Puppeteer to scrape a website, but when I try to obtain the screenshot it never loads it either goes to a TimeoutError or just never finishes.
...ANSWER
Answered 2021-Feb-12 at 21:27There appears to be an unnecessary waitForNavigation
call here. Since you already waited until page load, waiting for another navigation that never occurs is going to cause a timeout. Re-add the commented-out line below to reproduce your problem.
QUESTION
I have the following problem: I'm using [xtract][1], a Scala library for parsing XMLs. The latest version, 2.0.0 I'm trying to parse an XML file like this
...ANSWER
Answered 2020-Nov-22 at 22:40There are several issues with your code. The path object/name
is indeed ambiguous, as you cannot know whether you meant the first, or the second.
First, you need to define a class that contains the desired sequence, and its reader:
QUESTION
I have data like the input data data_df2 sample below. I have the code below that creates the label column by comparing the Cleaned column value to the value in the record before it and then either giving it the same letter, if the values match, or a new value. The problem I have is that I would like the letters that are chosen for the label column to start over with every new label_set_id. So the label value for first label_set_id=2 would be A. Every 20 records the label_set_id goes up by 1. Can anyone suggest how I can modify the code below to accomplish this? Or is there a slicker way with pandas, say using the apply function. This code does run kind of slow.
code:
...ANSWER
Answered 2020-Mar-27 at 17:35IIUC, you can use groupby
on label_set_id and check where two following rows are different with shift
, and use cumsum
to get an incremental value per group. Add 64 for map
the chr
function.
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