codex | mathematical knowledge written in the MathLingua language

 by   DominicKramer Shell Version: Current License: No License

kandi X-RAY | codex Summary

kandi X-RAY | codex Summary

codex is a Shell library. codex has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

A repository of mathematical knowledge written in the MathLingua language.
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              codex has a low active ecosystem.
              It has 0 star(s) with 0 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              codex has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of codex is current.

            kandi-Quality Quality

              codex has 0 bugs and 0 code smells.

            kandi-Security Security

              codex has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              codex code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              codex does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
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              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              codex releases are not available. You will need to build from source code and install.

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            codex Key Features

            No Key Features are available at this moment for codex.

            codex Examples and Code Snippets

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            Community Discussions

            QUESTION

            How would you fix an 'ERR_REQUIRE_ESM' error?
            Asked 2022-Apr-09 at 03:58

            I am trying to use the chalk npm. My code is:

            ...

            ANSWER

            Answered 2022-Apr-09 at 03:22

            The latest version of Chalk is only compatible with ESM modules and thus wants you to load it with import, not require().

            From the doc:

            IMPORTANT: Chalk 5 is ESM. If you want to use Chalk with TypeScript or a build tool, you will probably want to use Chalk 4 for now. Read more.

            So, your choices are:

            1. Switch your project to an ESM module and load the latest version of Chalk with import instead of require().

            2. Install version 4 of Chalk which can be used with require().

            3. With a fairly recent version of nodejs, you can use dynamic import to load the ESM module into your CommonJS module: const chalk = await import('chalk);

            Source https://stackoverflow.com/questions/71804844

            QUESTION

            How to bind function fish shell plugin
            Asked 2022-Mar-29 at 06:24

            I'm trying to write a plugin for the fish shell but can't get it to work. I have the following in a file called functions/codex.fish:

            ...

            ANSWER

            Answered 2022-Mar-28 at 18:52

            You don't need plugins to set up key bindings. Here is one way to do it:

            1. Create your function:

            Source https://stackoverflow.com/questions/71646083

            QUESTION

            why default layout information still appeared after deleted the default Layout in ASP.NET MVC?
            Asked 2022-Mar-03 at 12:22

            I just created new project in ASP.NET MVC and created new layout and deleted the default layout but when I run the project its show the new layout and down it shows the default layout information's ASP.NET and its information please see the image .

            enter image description here

            why its show the default layout text I deleted already and how to remove it

            This is the new layout footer code :

            ...

            ANSWER

            Answered 2022-Mar-03 at 12:22

            Go to Views > Home > Index.cshtml then Remove code.

            Source https://stackoverflow.com/questions/71334885

            QUESTION

            Have plans for Python 4 been resurrected?
            Asked 2022-Jan-03 at 03:45

            I just started noticing deprecation notices like the following in the official Python documentation:

            Deprecated since version 3.3, will be removed in version 4.0.

            I had been led to believe based on a number of public statements (such as this article with excerpts interview with Guido) that there would never be a Python 4, but now I'm starting to wonder if he (or the Python maintainers) may have recently had a change of mind. Or are these deprecation notices just a humorous way of saying "this feature will never be removed"? You never know with someone who names his language after a comedy team. 😂

            ...

            ANSWER

            Answered 2022-Jan-02 at 23:16

            People like to repeat that one sound bite, but Guido had more to say on the subject, like:

            Van Rossum didn't rule out the possibility of Python 4.0 entirely, though suggested this would likely only happen in the event of major changes to compatibility with C. "I could imagine that at some point we are forced to abandon certain binary or API compatibility for C extensions… If there was a significant incompatibility with C extensions without changing the language itself and if we were to be able to get rid of the GIL [global interpreter lock]; if one or both of those events were to happen, we probably would be forced to call it 4.0 because of the compatibility issues at the C extension level," he said.

            (source: https://www.techrepublic.com/article/programming-languages-why-python-4-0-will-probably-never-arrive-according-to-its-creator/ - which contains a link to a video with more, if you have the time)

            So the upshot of it seems to be that there will never be a Python 4, unless the advantages of making backwards compatibility breaking changes are so great, they simply dwarf the massive downsides that have become so apparent from the 2-to-3 change.

            Programmers and programming language designers are pragmatic people, generally speaking. If the benefit outweighs the cost, it will happen eventually. Nobody has anything to gain from religious zeal about design choices.

            Source https://stackoverflow.com/questions/70557069

            QUESTION

            How to keep the image previews of images that I have already uploaded upon re-render of Uppy instance in a React app
            Asked 2021-Dec-27 at 15:21

            I am able to upload images using Uppy on my react app:

            Upon selection and upload of an image, I see a preview of the image, along with options to remove it, add more, etc.:

            After clicking the "Continue" button, the state of reporting (from const [reporting, setReporting] = useState(false);) is set to true, which I think triggers a re-render of the DOM, including the disappearance of the UploadManager component, which contains the Uppy dashboard pictured above. Now, instead, a component is rendered:

            ...

            ANSWER

            Answered 2021-Nov-09 at 19:46

            I am unable to run the repro you provided because it appears to require private API keys.

            However, inspecting the code, here's what appears to be happening:

            1. The component renders for the first time with reporting state as false. This causes the component to render, and a new instance of Uppy to be created by the effect within that component and stored in this instance of the 's state.
            2. The user uploads a file, and hits the "continue" button, which sets reporting state to true. This causes the component to re-render, and show the component instead. The original component is unmounted, and the things that were present in its state, notably, the instance of Uppy that had the user's uploaded file, are lost.
            3. The user hits the "Back To Photos" button, which sets reporting state back to false. A this causes a new instance of to render, and the effect that creates an instance of Uppy re-runs. The instance that is created is new as well, and thus won't show what it contained the last time it was rendered.

            One way to solve this would be to lift up state that needs to remain the same as the is mounted and unmounted into the parent component. So the component would be responsible for creating the Uppy instance, and pass that as a prop to the .

            See also this part of the Uppy docs:

            Functional components are re-run on every render. This could lead to accidentally recreate a fresh Uppy instance every time, causing state to be reset and resources to be wasted.

            The @uppy/react package provides a hook useUppy() that can manage an Uppy instance’s lifetime for you. It will be created when your component is first rendered, and destroyed when your component unmounts.

            You could also re-factor your app in other ways if it feels like too much is happening in a single component. But the guiding principle would be: "don't create the uppy instance more than once in a single user flow".

            Source https://stackoverflow.com/questions/69859986

            QUESTION

            How to do the program will terminate if your user input's first letter of a word is not capitalize?
            Asked 2021-Dec-01 at 14:09

            How do I make this program accepts only a user input that's been typed while following a proper capitalization. Like it won't accept "robin hood" unless it's "Robin Hood". When I run it, it says...

            ...

            ANSWER

            Answered 2021-Dec-01 at 12:44

            You are checking if list is isupper . You'll need to do

            Source https://stackoverflow.com/questions/70180663

            QUESTION

            Creating a Factory in Typescript using infer and typeof
            Asked 2021-Nov-03 at 16:28

            Main Goal: I am trying to learn (and understand, not just copy and paste) how to create a Factory in Typescript but have a few points of confusion related to types and type inference. I'd like to have a "MyCloner" class be able to create multiple instances of an IClonable. For instance if I have a Truck class and a Motorcycle class that both implement IClonable.

            I would like to be able to do something like:

            ...

            ANSWER

            Answered 2021-Nov-03 at 16:28

            In the future try to limit yourself to one question per question but the answers to your questions are pretty succinct, so...

            Let's turn that conditional type declaration into some psuedo code that more clearly indicates what's going on:

            type InstanceType(T) = if T is a class then the type of the thing constructed by newing that class else type never

            And lets gradually move back towards the actual code (these are all representations of the same thing):

            Source https://stackoverflow.com/questions/69690959

            QUESTION

            What does this return type with never do vs just using an Interface?
            Asked 2021-Oct-23 at 21:07

            In trying to create a factory in Typescript I came across this article and I am confused by this part :

            ...

            ANSWER

            Answered 2021-Oct-23 at 21:07

            I am not sure why we need ExtractInstanceType & why we don't want to just use IStaff?

            Because the whole point of the userMap and the associated static method is to map names to specific, concrete classes, not the interface they implement. If any of those classes implement class-specific stuff on top of the general IStaff interface (and they almost certainly will) your code would be littered with instanceof or other checks every time you called a method not in IStaff if you didn't nip it in the bud by narrowing the type with that static method to satisfy the compiler.

            I thought it was just one of the keys in the dictionary that userMap can hold, which would be a string?

            As I suggested in the comments on my answer to your other question I think the problem is that you are still conflating types and values. TBF it doesn't help that there's some overlap.

            Consider the string 'a'. In Typescript, there is the value 'a' but there is also the literal type 'a', which is a subset of type string:

            Source https://stackoverflow.com/questions/69691672

            QUESTION

            Django error: "ModuleNotFoundError: No module named 'classroom' "
            Asked 2021-Oct-17 at 13:09

            I have been working on this project for the last month and this is the first time I have encountered this error: ModuleNotFoundError: No module named 'classroom' in countless times of running manage.py check on the app. The last change I remember making was commenting out some deprecated views and models, in preparation for removal, but I believe I have restored the code to the last known working version, however I am still receiving this error.

            "classroom" is the main application underneath the project. Here is the main directory structure:

            ...

            ANSWER

            Answered 2021-Oct-17 at 05:45

            you have to move classroom folder to root of project beside manage.py or use codex.classroom instead of classroom

            Source https://stackoverflow.com/questions/69601430

            QUESTION

            Import .tsv while filtering data in r
            Asked 2021-Oct-16 at 10:10

            I have a very large dataset in .tsv format (about 5 gb). After trying to open the file in R (As it was too large I got problems with R). I thought it might be a good idea filtering data while I import dataset in R in order to remove all the data that I don't need, making easier the task for R. I was wondering if anyone can give me some suggestions in order to do this with R. I found "sqldf package" that seems work with this kind of tasks, but only with .csv file.

            I would ask to R to import db.tsv data at the same time filtering "codEx" column to delete all values lower than 0, something like this:

            db <- (read.tsv(db.tsv), .... codEX >0)

            Thank you in advance for any help or suggestion!

            ...

            ANSWER

            Answered 2021-Oct-16 at 10:10

            You can pass your own separator in read.csv.sql function from sqldf. Here is an answer with a small example.

            Source https://stackoverflow.com/questions/69593843

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