backstage | Backstage is an open platform for building developer portals | Continuous Deployment library
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kandi X-RAY | backstage Summary
Backstage is an open platform for building developer portals. Powered by a centralized software catalog, Backstage restores order to your microservices and infrastructure and enables your product teams to ship high-quality code quickly — without compromising autonomy. Backstage unifies all your infrastructure tooling, services, and documentation to create a streamlined development environment from end to end.
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QUESTION
I cannot get item container from the ListBox
in Backstage
. Say, I have the following Backstage
:
ANSWER
Answered 2022-Mar-01 at 23:17The reason that ContainerFromIndex
returns null
is that the container simply is not realized.
Returns the element corresponding to the item at the given index within the ItemCollection or returns
null
if the item is not realized.
This is controlled by the ItemContainerGenerator that is responsible for the following actions.
Maintains an association between the data view of a multiple-item control, such as
ContainerFromElement
and the correspondingUIElement
tasks.Generates
UIElement
items on behalf of a multiple-item control.
A ListBox
is an ItemsControl
that exposes the ItemsSource
property for binding or assigning a collection.
A collection that is used to generate the content of the ItemsControl. The default is
null
.
Another option is to simply add items to the Items
collection in XAML or code.
The collection that is used to generate the content of the ItemsControl. The default is an empty collection. [...]
The property to access the collection object itself is read-only, and the collection itself is read-write.
The Items
property is of type ItemCollection
, which is also a view.
If you have an
ItemsControl
, such as aListBox
that has content, you can use theItems
property to access theItemCollection
, which is a view. Because it is a view, you can then use the view-related functionalities such as sorting, filtering, and grouping. Note that whenItemsSource
is set, the view operations delegate to the view over theItemsSource
collection. Therefore, theItemCollection
supports sorting, filtering, and grouping only if the delegated view supported them.
You cannot use both ItemsSource
and Items
at the same time, they are related.
[...] you use either the
Items
or theItemsSource
property to specify the collection that should be used to generate the content of yourItemsControl
. When theItemsSource
property is set, theItems
collection is made read-only and fixed-size.
Both ItemsSource
and Items
either maintain a reference to or bind your data items, these are not the containers. The ItemContainerGenerator
is responsible for creating the user interface elements or containers such as ListBoxItem
and maintaining the relationship between the data and these items. These containers do not just exist throughout the lifecycle of your application, they get created and destroyed as needed. When does that happen? It depends. Containers are created or realized (using the internal terminology) when they are shown in the UI. That is why you only gain access to a container after it was first shown. How long they actually exist depends on factors like interaction, virtualization or container recycling. By interaction I mean any form of changing the viewport, which is the part of the list that you can actually see. Whenever items are scrolled into view, they need to be realized of course. For large lists with tens of thousands of items, realizing all containers in advance or keeping all containers once they are realized would hit performace and increase memory consumption drastically. That is where virtualization comes into play. See Displaying large data sets for reference.
UI Virtualization is an important aspect of list controls. UI virtualization should not be confused with data virtualization. UI virtualization stores only visible items in memory but in a data-binding scenario stores the entire data structure in memory. In contrast, data virtualization stores only the data items that are visible on the screen in memory.
By default, UI virtualization is enabled for the ListView and ListBox controls when their list items are bound to data.
This implies that containers are deleted, too. Additionally, there is container recycling:
When an
ItemsControl
that uses UI virtualization is populated, it creates an item container for each item that scrolls into view and destroys the item container for each item that scrolls out of view. Container recycling enables the control to reuse the existing item containers for different data items, so that item containers are not constantly created and destroyed as the user scrolls the ItemsControl. You can choose to enable item recycling by setting theVirtualizationMode
attached property toRecycling
.
The consequence of virtualization and container recycling is that containers for all items are not realized in general. There are only containers for a subset of your bound or assigned items and they may be recycled or detached. That is why it is dangerous to directly reference e.g. ListBoxItem
s. Even if virtualization is disabled, you can run into problems like yours, trying to access user interface elements with a different lifetime than your data items.
In essence, your approach can work, but I recommend a different approach that is much more stable and robust and compatible with all of the aforementioned caveats.
A Low-Level ViewWhat is actually happening here? Let us explore the code in medium depth, as my wrists already hurt.
Here is the ContainerFromIndex
method in the reference source of .NET.
- The
for
loop in line 931 iteratesItemBlock
s using theNext
property of the_itemMap
. - When your items were not shown, yet in the user interface, they are not realized.
- In this case,
Next
will return anUnrealizedItemBlock
(derivative ofItemBlock
). - This item block will have a property
ItemCount
of zero. - The
if
condition in line 933 will not be met. - This continues until the item blocks are iterated and
null
is returned in line 954..
Once the ListBox
and its items are shown, the Next
iterator will return a RealizedItemBlock
which has an ItemCount
of greater than zero and will therefore yield an item.
How are the containers realized then? There are methods to generate containers.
DependencyObject IItemContainerGenerator.GenerateNext()
, see line 230.DependencyObject IItemContainerGenerator.GenerateNext(out bool isNewlyRealized)
, see line 239.
These are called in various places, like VirtualizingStackPanel
- for virtualization.
protected internal override void BringIndexIntoView(int index)
, see line 1576, which does exactly what it is called. When an item with a certain index needs to be brought into view, e.g. through scrolling, the panel needs to create the item container in order to show the item in the user interface.private void MeasureChild(...)
, see line 8005. This method is used when calculating the space needed to display aListView
, which is influenced by the number and size of its items as needed.- ...
Over lots of indirections from a high-level ListBox
over its base type ItemsControl
, ultimately, the ItemContainerGenerator
is called to realize items.
For all the previously stated issues, there is a simple, yet superior solution. Separate your data and application logic from the user interface. This can be done using the MVVM design pattern. For an introduction, you can refer to the Patterns - WPF Apps With The Model-View-ViewModel Design Pattern article by Josh Smith.
In this solution I use the Microsoft.Toolkit.Mvvm NuGet package from Microsoft. You can find an introduction and a detailed documentation here. I use it because for MVVM in WPF you need some boilerplate code for observable objects and commands that would bloat the example for a beginner. It is a good library to start and later learn the details of how the tools work behind the scenes.
So let us get started. Install the aforementioned NuGet package in a new solution. Next, create a type that represents our data item. It only contains two properties, one for the index, which is read-only and one for the checked state that can be changed. Bindings only work with properties, that is why we use them instead of e.g. fields. The type derives from ObservableObject
which implements the INotifyPropertyChanged
interface. This interface needs to be implemented to be able to notify that property values changed, otherwise the bindings that are introduced later will not know when to update the value in the user interface. The ObservableObject
base type already provides a SetProperty
method that will take care of setting a new value to the backing field of a property and automatically notify its change.
QUESTION
I am working on MS Word application. When we click in file tab in word , it opens backstage view. How do I know programmatically in C# if I am in backstage view or not. I tried checking with if ActiveWindow or ActiveDocument is null or not. But they are not working . I don't want to create/customize the ribbon xml for checking this. Is there any property in window/document/application by which I can get to know I am in backstage view of word or not.
Thanks in Advance
...ANSWER
Answered 2022-Jan-03 at 21:12The Backstage UI provides the following two callbacks (events) that allow to be aware when the UI is shown and closed:
onHide
QUESTION
How can I override the theming of a component in Material-UI that has styles applied to it through withStyles
?
When I look at the component in question I see the following in the DOM:
I'm attempting to restyle Backstage and am looking at the MuiSelect component right now. Backstage has adjusted the styling of the MuiSelect by overriding CSS with withStyles
. Looking at the DOM I am trying to adjust CSS that is being applied through the WithStyles(ForwardRef(InputBase))-input-75764
class.
In Backstage's Select.tsx
component file, the styles are defined this way:
ANSWER
Answered 2021-Dec-14 at 22:30There's a guide here on how to override styles for named Backstage components.
For Backstage components that don't have override names available, they can be added such as in this pull request.
QUESTION
Here is what I am doing:
...ANSWER
Answered 2021-Oct-21 at 04:24You need to define bar
before Foo
. In your current configuration, the name bar
does not exist in the global namespace when the class body is executed.
You might consider adding a newline or some sort of divider between the docs:
QUESTION
I'm trying to mock a fetch call using thisfetch-mock-jest but it the code still trys to go to the remote address and eventually fail with error message FetchError: request to https://some.domain.io/app-config.yaml failed, reason: getaddrinfo ENOTFOUND some.domain.io]
.
Here the the test code
...ANSWER
Answered 2021-Oct-14 at 10:50replaced
QUESTION
I am trying to create a searching component using Vue 3 to allow a user to insert text and have it display all available results. I am basing my code off this example: https://codepen.io/thaekeh/pen/PoGJRKQ
However, it does not seem to want to work, as I am sure it has something to do with v-model for the search bar. The search bar also seems to be floating and wont stay in one place, so if anyone has a fix for that also that would be great.
This is my code thus far (excuse the missing pictures):
...ANSWER
Answered 2021-Sep-24 at 03:00your problem was found in
QUESTION
I'm using ForgeRock v7.1.0, running in Docker v3.6.0 on MacOS 11.5.2 (Big Sur).
I'm trying to exchange an OAuth 2.0 access token (subject token) I've already retrieved to be an ID Token (with a JWT Payload) and it's giving me an error every time I call it, specifically related I believe to the subject_token_type
parameter.
The steps I am following are as follows:
- Generate an OAuth2 access token:
ANSWER
Answered 2021-Aug-26 at 14:47Doh! Always the way, after posting a question you manage to work it out!
OK, this is what I needed to do:
Navigate to Realm > [RealmName] > Scripts
Modify the "OAuth 2.0 May Act" Groovy script to be something like this (alter as appropriate):
QUESTION
Hi I am working on react recently, and I have a question here: so if we want to pass props to multi-level components, how to do it efficiently??
Say that I have three components, Parent, Child, ChildOfChild. I want to pass a props from Parent to ChildOfChild.
What I did is to use componentWillReceiveProps in Child and ChildOfChild.
like this: Parent:
...ANSWER
Answered 2021-Aug-09 at 02:48Storing passed props in local component state is anti-pattern in React, you should pass them on to children. componentWillReceiveProps for all intents and purposes has been deprecated and shouldn't be used. For this you should implement the componentDidUpdate lifecycle method and check the previous props/state to the current state/props value in order to issue any side-effects.
Parent
QUESTION
I am trying to develop a simple plugin on Backstage for the first time. I thought I installed and configured everything right
...ANSWER
Answered 2021-Jun-12 at 09:39Solved by running the backend like this:
QUESTION
Could someone guide me, I have tried many different ways but can't find out the problems.
...ANSWER
Answered 2021-Jun-10 at 21:19I modified your html and provide some fake data of mine and sent two emails. I also modified the recipient portion of the code it needed to be flattened and joined with a comma.
The gs:
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