jackpot | Jackpot , tcp connection pooling for Node.js | Runtime Evironment library
kandi X-RAY | jackpot Summary
kandi X-RAY | jackpot Summary
Jackpot is a fault tolerant connection pool for Node.js, it automatically cleans up after it self and detects broken connections. It does not need to be released, as it will allocate connections based on their readyState / write abilities.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of jackpot
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jackpot Examples and Code Snippets
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Trending Discussions on jackpot
QUESTION
i would like to scrape the header-element from these both links - For me this 2 sites look absolute identical - pics see below
Why is only the scraping for the second link working and not for the first?
...ANSWER
Answered 2021-Jun-10 at 19:06The page is sometimes loaded by JavaScript, so request won't support it.
You can use a while loop to check if header appears in the soup and then break
QUESTION
What I'm trying to do is create a jackpot game in the python terminal that basically requires randomization. so I created a function that defines what the jackpot does.
it'll automatically start when typed the specific word. here is the code that I created.
...ANSWER
Answered 2021-May-04 at 19:33This line:
QUESTION
It's me again. We were tasked in our class to make a Slot Machine with 2 panels. Everything is working great except for the if else conditions. It seemed that the JOptionPane is not working or showing when it met the condition, but it shows no error in the console. I see the alert on the right it says that the JTextField is unrelated to String, but I converted the Random Number Integers to String to show it on the panel since it seemed that only String are accepted in JTextField. Please help! Thank you!
...ANSWER
Answered 2021-Feb-24 at 14:34You are comparing a JTextField with a String by typing
QUESTION
Now VueJS display me date in format 2021-02-24 00:12:42, but how i can change display only 00:12? Without year, month, date and seconds?
In vue i use:
ANSWER
Answered 2021-Feb-23 at 21:54One way to do this is to create a component method that converts the string into a Date object, uses Date.prototype.toTimeString(), and takes only the first 5 characters, which contains only the hh:mm portion. Another simpler way is to just extract the substring with String.prototype.substr(), assuming the format never changes.
QUESTION
I am trying to build a lucky draw system. There are 8 cards in each category and 8 people to assign those cards. I want to make a flipping animation on cards that all cards flip till 10 seconds then only one card appear on screen as jackpot. How can I achieve that with CSS and JavaScript?
My current code:-
CSS
...ANSWER
Answered 2021-Feb-17 at 06:56I set the required functions. You can call them depending on the usage you want
QUESTION
I have a Node script with Typescript, where i want to extract an object (from a file), that occasionally is null. Therefore i want to use operational chaining (or some other operator) that allows me to have a fallback to null if the object does not exists
ANSWER
Answered 2021-Feb-13 at 11:20Change your target field to ES2020 which is suitable to Node v14.
QUESTION
I'm working on an assignment where I need to create a jackpot game. But I'm having trouble driving the register that controls the win condition and I can't figure out why. As far as I know, the always@(posedge zero) block should be able to run whenever I flip my switch to the up position. Then, so long as the right hot register value happens in the same instant, it should be able to set the win register. However, this is not the case. Nothing seems to happen, and I'm not sure why. I've tried running the always block from different sensitivities but nothing seems to effect it. Maybe I'm just mis-understanding how always blocks work or how the switch works, any help is appreciated.
...ANSWER
Answered 2021-Feb-09 at 17:10Thanks to Serge's comment I've realized the issue. Like his comment says, driving a register from multiple always blocks throws a critical warning, and Vivado picks one of the blocks to use over the other. Once I made sure to isolate a reg to an always block the behavior started to look like I expected. This must just be something that got glossed over during class, or maybe I wasn't paying attention enough.
QUESTION
I have a problem about implementing recommendation system by using Euclidean Distance.
What I want to do is to list some close games with respect to search criteria by game title and genre.
Here is my project link : Link
After calling function, it throws an error shown below. How can I fix it?
Here is the error
...ANSWER
Answered 2021-Jan-03 at 16:00The issue is that you are using euclidean distance for comparing strings. Consider using Levenshtein distance, or something similar, which is designed for strings. NLTK has a function called edit distance that can do this or you can implement it on your own.
QUESTION
please take a look at this: This should echo X10, but echoes jackpot... can anyone see why it doesn't behave as it should? Probably just some mistake I made that do not throw errors?
...ANSWER
Answered 2020-Nov-18 at 13:38When used with [[, the < and > operators sort lexicographically using the current locale.
I see two options.
Do the comparison in arithmetic context:
QUESTION
public static String determiner(String userResponse, int playerHand, int AiHand) {
if (userResponse.equals("hit") && playerHand < 21 && AiHand <21) {
int RandomGen = (int) (Math.random()*11 + 1);
int newHand = playerHand + RandomGen;
int AIRandomGen = (int) (Math.random()*11 + 1);
int newAIHand = AiHand + AIRandomGen;
return "Your current hand is " + newHand;
}
else if (userResponse.equals("stay") && playerHand > 21 && AiHand < 21) {
if (playerHand > AiHand) {
String x = "You won!";
return x;
}
else if (AiHand > playerHand) {
String x = "Sorry, you lost.";
return x;
}
else if (playerHand == 21) {
String x = "You won! You hit the jackpot :0";
return x;
}
else if (AiHand == 21) {
String x = "Sorry, you lost. Enemy hit the jackpot";
return x;
}
}
else if (userResponse.equals("hit") && playerHand > 21) {
String x = "Game over, you lost. You went boom boom";
return x;
}
else {
return null;
}
}
ANSWER
Answered 2020-Nov-07 at 03:15else if (AiHand == 21) {
String x = "Sorry, you lost. Enemy hit the jackpot";
return x;
}
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