gargoyle | A memory scanning evasion technique | Hacking library

 by   JLospinoso C++ Version: Current License: AGPL-3.0

kandi X-RAY | gargoyle Summary

kandi X-RAY | gargoyle Summary

gargoyle is a C++ library typically used in Security, Hacking applications. gargoyle has no bugs, it has a Strong Copyleft License and it has low support. However gargoyle has 2 vulnerabilities. You can download it from GitHub.

gargoyle is only implemented for 32-bit Windows (64-bit Windows on Windows is fine). You must have the following installed:.
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            kandi-support Support

              gargoyle has a low active ecosystem.
              It has 710 star(s) with 111 fork(s). There are 28 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 1 open issues and 4 have been closed. On average issues are closed in 68 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of gargoyle is current.

            kandi-Quality Quality

              gargoyle has 0 bugs and 0 code smells.

            kandi-Security Security

              gargoyle has 2 vulnerability issues reported (0 critical, 1 high, 1 medium, 0 low).
              gargoyle code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              gargoyle is licensed under the AGPL-3.0 License. This license is Strong Copyleft.
              Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

            kandi-Reuse Reuse

              gargoyle releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of gargoyle
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            gargoyle Key Features

            No Key Features are available at this moment for gargoyle.

            gargoyle Examples and Code Snippets

            No Code Snippets are available at this moment for gargoyle.

            Community Discussions

            QUESTION

            Is there a cleaner method to this?
            Asked 2022-Jan-24 at 17:42
            public class ChartData {
                //lv22 double charts
                public String[] walkInThePark = {"CanCan", "Cleaner", "Meteo5cience", "FFF22", "Wedding Crasher", "Hyponosis22", "Redline", "1950", "Monolith", "Just hold on", "Revolution", ""};
                //lv23 double charts
                private String[] timeToSuffer = {"Travel To Future", "Nililism", "Creed", "HTTP", "Cross Over", "Final Autition 2-1", "Love is a Danger Zone", "Gargoyle", "Broken Karma", "BS Explosion", "Windmill", "Prime Time", "Clematis", "Nyar", "Your Mind", "D&D", "Red Snow", "Stardream", "Crossing Delta", "Video Out C"};
                //lv24 double charts
                private String[] chooseDeath = {"la Cinq", "Gloria", "Vanish", "Harma", "Conflict", "Sarabande", "Bedlam", "Final Audition", "Achluoias", "FFF24", "Full moon", "Full moon FULL", "Annihilator", "Creed FULL", "BrainPower", "lolite", "Dement", "Destri", "Cross Soul", "TFTMN FULL", "Errorcode", "Dignity", "A Site De La Rue", "Trashy", "Paved Garden", "V3"};
            
                Random r = new Random();
                Scanner sc = new Scanner(System.in);
            
                public void select(){
            
            
                    do{
                        System.out.println("Please choose from the following: \n 1. WalkInThePark(lv22 double charts) \n 2. timeToSuffer(lv23 Double Charts) \n 3. chooseDeath(lv24 double charts)");
                        int select = sc.nextInt();
            
                        switch (select){
                            case 1:
                                System.out.println("That's sorta weak, my dude... :");
                                chill();
                                break;
                            case 2:
                                System.out.println("I see you:");
                                suffer();
                                break;
                            case 3:
                                System.out.println("You decided to not B**** out. Here's your list:");
                                death();
                                break;
                        }
            
                    }while(true);
            
            
            
                }
            
            
                public void chill(){
            
                    Set set = new HashSet<>();
                    for(int i = 0 ; i < 4 ; i++){
                        int r_int = r.nextInt(11);
                        String chooseChill = (walkInThePark[r_int]);
                        if(!set.contains(chooseChill)){
                            set.add(chooseChill);
                            System.out.println(chooseChill);
                        }else{
                            i--;
                            continue;
                        }
            
                    }
            
                }
            
                public void suffer(){
            
                    Set set = new HashSet<>();
                    for(int i = 0 ; i < 4 ; i++){
                        int r_int = r.nextInt(19);
                        String chooseSuffer = (timeToSuffer[r_int]);
                        if(!set.contains(chooseSuffer)){
                            set.add(chooseSuffer);
                            System.out.println(chooseSuffer);
                        }else{
                            i--;
                            continue;
                        }
            
                    }
            
                }
            
                public void death(){
            
                    Set set = new HashSet<>();
                    for(int i = 0 ; i < 4 ; i++){
                        int r_int = r.nextInt(26);
                        String chosenDeath = (chooseDeath[r_int]);
                        if(!set.contains(chosenDeath)){
                            set.add(chosenDeath);
                            System.out.println(chosenDeath);
                        }else{
                            i--;
                            continue;
                        }
            
            
                    }
            
            
            
                }
            
            
            
            
            
            }
            
            ...

            ANSWER

            Answered 2022-Jan-24 at 16:50

            The only ways in which your chill(), suffer() and death() functions differ are in the range of the random integer as well as the array used (chooseDeath, timeToSuffer or walkInThePark), both of which you could pass to the function as an argument instead to unify them into one function.

            Source https://stackoverflow.com/questions/70837362

            QUESTION

            Counting player kills in text rpg python
            Asked 2021-Sep-27 at 09:21

            I've been learning Python by doing random projects here and there. My newest project is a simple text roguelike RPG. The player starts with base stats and just has to survive

            Players can attack, heal or run. Which for the most part does work, however, I'm trying to display a kill count beside the player name and visible stats(exp and HP). I'm pretty sure my count variable is just misplaced as it resets to 0 after every enemy death. I want this because it SHOULD mimic b_count for boss appearance. My code is as follows:

            ...

            ANSWER

            Answered 2021-Sep-26 at 15:21

            Inside the battle function, you're setting the count variable at the beginning of the function, but also resetting it in a loop before it gets displayed.

            Source https://stackoverflow.com/questions/69336086

            QUESTION

            Python 3: How Do I Invert A Dictionary That Has A List As A Value
            Asked 2021-Mar-15 at 12:16

            So for class I need to take a dictionary that has a list as a value and invert it. I have found several ways to do this, but the issue is when there are non-unique values. I found a way to do this but I feel like there must be much easier and streamlined ways to do this.

            ...

            ANSWER

            Answered 2021-Mar-15 at 12:05

            You can replace your if else :

            Source https://stackoverflow.com/questions/66637332

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install gargoyle

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            CLONE
          • HTTPS

            https://github.com/JLospinoso/gargoyle.git

          • CLI

            gh repo clone JLospinoso/gargoyle

          • sshUrl

            git@github.com:JLospinoso/gargoyle.git

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