Button2 | ESP button library that provides callback functions
kandi X-RAY | Button2 Summary
kandi X-RAY | Button2 Summary
This library allows you to use callback functions to track single, double, triple and long clicks. It takes care of debouncing. Using this lib will reduce and simplify your source code significantly. It has been tested with Arduino, ESP8266 and ESP32 devices.
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Trending Discussions on Button2
QUESTION
I am new to using tkinter and am struggling to get my buttons to render at the very bottom of the screen, evenly spaced out, filling the entire bottom row.
I have been using grid() to try to do this but no luck. I want these three buttons to render without impacting other components of the page(such as the text at the top). I am trying to accomplish a window that has three buttons, each button rendering a different page that you can interact with.
Here is my full code below, I appreciate any insight at all more than you know.
...ANSWER
Answered 2022-Mar-31 at 22:34You are using grid along with pack. You should never mix these two layout managers as it results in unknown buggy behiviour. Maybe your code will work after culling that pack call.
QUESTION
We know that ListExpression
has a method ObjectBinding valueAt(ObservableIntegerValue)
. We can use this method to listen to an element of a ListProperty
exactly.
I expect it will both bind to the ListProperty
and the ObservableNumberValue
. So either the list changes or the observable number value changes will make the binding invalid and recompute. But in the following code, the binding is computed only once! (Actually twice, if we don't ignore the initial computation)
The label will display a random string at the beginning. And the property
will have 100 Bean as the initial value. If we click button1
, the indexProperty
will increase by 1. If we click button2
, the Bean located at the current index of the ListProperty will change. Both effects will make the binding invalid and recompute the label text.
But in practice, the text will change the first time when one button is clicked. And will not change anymore.
I'm using Liberica JDK17 which contains jmods of JavaFX by default.
...ANSWER
Answered 2022-Mar-17 at 17:49I'm going to reply in Java, as I'm more familiar with it. The reasoning applies to kotlin too.
Bindings.createStringBinding(function, dependencies)
creates a binding that is invalidated any time any of the dependencies are invalidated. Here "invalidated" means "changes from a valid state to an invalid state". The problem with your code is that you define the dependency as property.valueAt(index)
, which is a binding to which you have no other reference.
When you change either the index or the bean at that index in the list, then the binding becomes invalid. Since you never compute the value of that binding again, it never becomes valid again (i.e. it never holds, or has returned, a valid value). So subsequent changes will not change its validation state (it is simply still invalid; it cannot transition from valid to invalid).
Changing the code to
QUESTION
ANSWER
Answered 2021-Dec-11 at 19:02You are trying to change the inner working of a third party component. This is normally a bad practice. In this case probably the best way is to open a new issue on their Github repository. Ask them exactly what you need and maybe they will implement the requested feature for you.
QUESTION
Hi i think i don't really now how live data works.
I am having a 2D Array with prefilled Values.
...ANSWER
Answered 2022-Feb-19 at 19:14Seeing the new state after a screen rotation (after a configuration change) is not related to how LiveData works. You are observing your LiveData correctly.
So i want that only the current State of my Array and no future states are pushed to my LiveData Objects so i gave it a copy of my Array.
A slight correction here, you gave it a shallow copy of your array. A shallow copy is a copy of the original array, but if the items are instances (references to objects), they will be copied by reference. Which means that changes on items in the copy of the array will affect the items in the original array as well, since it is the same references (= same instances).
And since you have an array of arrays, items in your array are instances of 4 other arrays. And when you change the values inside randomboard
in your trySetValue
function, you access the same 4 array instances every time.
The arrayOf
calls create a new array instance and fill it with the values provided as parameters. So your initial assignment to randomboard
creates 5 array instances:
- 4 are of type Integer[] and contain values 0, 0, 0, 0
- 1 is of type Integer[][] and contains references to the 4 arrays above. The reference to this array is stored into the field
randomboards
This snippet of code compares the values by reference and shows that the main array is a new instance (because of the copyOf
call), but the arrays inside are the same instances.
QUESTION
So it is exactly as the title suggests. I've created an app of which I will put the code beneath here, and when I call a fragment from the automaticly generated Home fragment which generates when you choose the template Navigation Drawer Activity
, it pops up fine, and when I swipe back it dissapears again.
However, then when I press the button to call a fragment the second time, it just shows an empty screen.
MainActivity.java:
...ANSWER
Answered 2022-Feb-01 at 22:34I forgot the fm.popBackStackImmediate();
in the onBackPressed()
method in the MainActivity.java
. Which, when actually placed in onBackPressed()
made everything work perfectly.
QUESTION
I'm trying to replicate the tab bar in the iPad version of Safari, which looks like this:
(Is there a third party library which does this? I can't find one)
I'm using the code below. Which results in this:
I guess I need to turn the Views into arrays somehow, and have a button (on the tab, or page) to add and remove tabs. Any idea how to do this?
...ANSWER
Answered 2022-Jan-17 at 14:21Like a lot of problems with SwiftUI, this seems overly complex because you're mixing the concept of state with how that state is drawn on screen.
Removing the visuals for a moment, what you have in terms of data is:
- an ordered collection of pages, each with a title and image
- a concept of which page in that collection is active
(Note that I call them 'pages' here to try and separate them from the visual representation as tabs.)
You also have some actions which will alter that data:
- your user can choose which page should be the active one
- they can add a new page to the collection
- they can remove an existing page from the collection
Now, if you think of those small steps as your data model, you can build an object or objects which cleanly encapsulate that.
Then, you can go on to determine how SwiftUI represents that data and how it might include the action triggers. For example:
- A list of horizontal tabs loops through the ordered collection of pages and renders each one
- Each tab has a button action which, when tapped, sets that button to be the active one
- Each tab has a close button which, when tapped, removes it from the pages collection
- A separate button, when tapped, can add a new page to the collection
And so on. Hopefully, you can see that each view in SwiftUI would now have a specific purpose, and should be easier for you to think about.
And you might even decide on a different UI – you could list your pages vertically in a List
, for example, or in a grid like the iPhone's Safari page view. But even if you did, your underlying data wouldn't change.
QUESTION
i write a code for calculator in gtk3 c the code is total numbers, in i write 1+1+1+1 the result is 3+1 i want to fix to 4 calcul result
in i write sprintf(result,"%d%s",temp,rest); the result for 1+1+1+1 is 3+1 i want to result 4 i check for sprintf(result,"%d",temp); is not correct.
the code of application :
...ANSWER
Answered 2022-Jan-21 at 18:03First of all, if you remove all the unrelated code from your example, we get this MCVE:
QUESTION
I have a list of Qt buttons like this: self.buttons = [button1, button2, button3]
When one is clicked, I want all the buttons that come before the one that was clicked in the list to change their colors.
I made a for loop to loop through the buttons and connect each one to a function that I defined, but when I click a button and the connected function runs, it does not know the order of the button in the buttons list, therefore I cannot make the other buttons change colors. I was thinking that I need to somehow pass the button's id or something to the function but couldn't figure out how to do it as I cannot pass arguments to the connected function: self.button1.clicked.connect(self.change_color)
One argument is automatically passed to the connected function by Qt itself but it is the main window and it does not help my situation:
...ANSWER
Answered 2022-Jan-19 at 20:18Add all the buttons to a QButtonGroup (using their index as id) and then connect to the group's idClicked signal. This will automatically send the index of the clicked button. Below is a simple demo that shows how to do it:
QUESTION
i'm learning JavaScript now, and for practicing, i'm trying to make a text editor. Where you can type something, click a button and make it to upper or lower case, bold and talic. It worked with lower and upper case, but for some reason it doesn't work with bold.
Here's my HTML:
...
ANSWER
Answered 2022-Jan-11 at 18:47The problem is you are changing the input.value
to bold. You can't style the input.value
you should directly change the input
style.
Also, you can't use the input.value =
it is not built-in function like toUpperCase
, it is style.
Use input.value.style.fontWeight
may work, but you need to apply it back which click on other element which is messy. The easiest way is to so you don't have to worry to change it back.
Also, I problem I have to mentioned, you should declare the input value inside the function, you declare it at the beginning which will always be empty since you assign the value at page loading.
QUESTION
I'd like to I using the button Yes!
could begin game again not quit from program and come in regularly. How to create it?
ANSWER
Answered 2021-Dec-14 at 20:13The problem with your approach is that it is recursive. beginning
invokes game
, game
invokes game_over
and game_over
again invokes beginning
:
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