swy | educational research programming language | Natural Language Processing library

by Naios C++ Version: Current License: Apache-2.0

X-Ray Key Features Code Snippets Community Discussions(2)Vulnerabilities Install Support

kandi X-RAY | swy Summary

swy is a C++ library typically used in Artificial Intelligence, Natural Language Processing applications. swy has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A compiler for my educational research programming language that supports homogeneous metaprogramming

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Support

swy has a low active ecosystem.

It has 19 star(s) with 1 fork(s). There are 1 watchers for this library.

It had no major release in the last 6 months.

swy has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of swy is current.

Quality

swy has no bugs reported.

Security

swy has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

swy is licensed under the Apache-2.0 License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

swy releases are not available. You will need to build from source code and install.

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swy Key Features

No Key Features are available at this moment for swy.

swy Examples and Code Snippets

No Code Snippets are available at this moment for swy.

Community Discussions

Trending Discussions on swy

Joining xts objects using try fails in R

Passing a Constant Integer in a CUDA Kernel

QUESTION

Joining xts objects using try fails in R

Asked 2019-Apr-18 at 22:19

My aim is to download stock prices using the quantmod library for a large number of ticker symbols (~700) and merge the results in a single dataframe which I will save as a csv file. I have a list of ticker symbols but not all of them are downloadable by quantmod.

So when I pass the list with the ticker symbols to the getSymbols() method, once it encounters a problem with a particular ticker symbol it stops and returns an exception. I am trying to circumvent this behavior with a for loop and the try method, but I fail.

Let's look at some code:

When I try to download two ticker symbols that are downloadable and then merge them into one xts object I succeed:

...

ANSWER

Answered 2019-Apr-18 at 08:59

Here is a code I tried. It seems working (although I tried only a subset of the vector):

Source https://stackoverflow.com/questions/55740392

QUESTION

Passing a Constant Integer in a CUDA Kernel

Asked 2017-Jun-29 at 19:19

I am having a problem with the following code. In the global kernel, loop_d, M has an integer value of 84. When I try to create a shared array, temp, and use M as the size of the array, I get the following error:

error: expression must have a constant value

I am not sure why that is. I know that if I declare M as a global variable, then it works, but the problem is that I get the value of M by calling the function d_two in a different Fortran program, so I am not sure how to get around that. I know that if I replace temp[M] with temp[84], then my program runs perfectly, but that is not very practical, since different problems might have different values of M. Thank you for your help!

The program

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ANSWER

Answered 2017-Jun-29 at 19:19

The compiler needs M to be a compile-time constant. At compile time it cannot determine what M is actually going to be (it doesn't know you will just pass it 84 eventually).

When you want to use shared memory of size you only know at runtime, you use dynamic shared memory.

See this example here on the site or Using Shared Memory in CUDA on the Parallel4All blog.

Source https://stackoverflow.com/questions/44813437

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install swy

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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