Espeon | Gameboy emulator for the ESP32

by Ryuzaki-MrL C++ Version: 1.0 License: GPL-3.0

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | Espeon Summary

Espeon is a C++ library typically used in Internet of Things (IoT), Arduino applications. Espeon has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

This emulator is being developed primarily with the M5Stack device in mind. You can find more info about it here: M5Stack Arduino API, M5Stack TreeView library, and M5Stack FACES are required. If you don't own a M5Stack, feel free to adapt this codebase to your setup.

Support

Quality

Security

License

Reuse

Support

Espeon has a low active ecosystem.

It has 79 star(s) with 4 fork(s). There are 10 watchers for this library.

It had no major release in the last 12 months.

There are 9 open issues and 5 have been closed. On average issues are closed in 68 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of Espeon is 1.0

Quality

Espeon has 0 bugs and 0 code smells.

Security

Espeon has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

Espeon code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

Espeon is licensed under the GPL-3.0 License. This license is Strong Copyleft.

Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

Reuse

Espeon releases are available to install and integrate.

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Espeon Key Features

No Key Features are available at this moment for Espeon.

Espeon Examples and Code Snippets

No Code Snippets are available at this moment for Espeon.

Community Discussions

Trending Discussions on Espeon

how to compare a string with items in a list , character by character in python

QUESTION

how to compare a string with items in a list , character by character in python

Asked 2018-Jul-14 at 15:02

I have a list and I want to compare user input with that list , but character by character. for example user can only input some character and leave the rest by dots. (for example : V...r..n ) How do I can compare strings character by character, and if it only includes all characters by user input (skip the dots)

...

ANSWER

Answered 2018-Jul-14 at 15:02

Here's one way. There are two steps. First make a dictionary mapping indices to relevant characters. Then check for equality for those indices.

Source https://stackoverflow.com/questions/51337721

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install Espeon

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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