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kandi X-RAY | Compiler Summary
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Lines of Code : 28License : Non-SPDX (Apache License 2.0)
Copydef set_cc_opt_flags(environ_cp):
"""Set up architecture-dependent optimization flags.
Also append CC optimization flags to bazel.rc..
Args:
environ_cp: copy of the os.environ.
"""
if is_ppc64le():
# gcc on ppc64le does not suppor def set_gcc_host_compiler_path(environ_cp):
"""Set GCC_HOST_COMPILER_PATH."""
default_gcc_host_compiler_path = which('gcc') or ''
cuda_bin_symlink = '%s/bin/gcc' % environ_cp.get('CUDA_TOOLKIT_PATH')
if os.path.islink(cuda_bin_symlink):
def set_tf_cuda_clang(environ_cp):
"""set TF_CUDA_CLANG action_env.
Args:
environ_cp: copy of the os.environ.
"""
question = 'Do you want to use clang as CUDA compiler?'
yes_reply = 'Clang will be used as CUDA compiler.'
no_reply = ' Community Discussions
Trending Discussions on Compiler
QUESTION
I wrote a demo with some inline assembly (showing how to shift an array of memory right one bit) and it compiles and functions fine in GCC. However, the with Clang, I'm not sure if it's generating bad code or what but it's unhappy that I'm using memory despite the "rm" constraint.
I've tried many compilers and versions via Godbolt and while it works on all x86/x86_64 versions of GCC, it fails with all versions of Clang. I'm unsure if the problem is my code or if I found a compiler bug.
Code:
...ANSWER
Answered 2021-Jun-16 at 00:48I'm unsure if the problem is my code or if I found a compiler bug.
The problem is your code. In GNU assembler, parentheses are used to dereference like unary * is in C, and you can only dereference a register, not memory. As such, writing 12(%0) in the assembly when %0 might be memory is wrong. It only happens to work in GCC because GCC chooses to use a register for "rm" there, while Clang chooses to use memory. You should use "r" (bytes) instead.
Also, you need to tell the compiler that your assembly is going to modify the array, either with a memory clobber or by adding *(unsigned char (*)[16])bytes as an output. Right now, it's allowed to optimize your printf to just hardcode what the values were at the beginning of the program.
Fixed code:
QUESTION
Giving a bit of context. I'm using c++17. I'm using pointer T* data because this will interop with cuda code. I'm trying write a parallel version (on CPU) of a histogram creator. The sequential version:
ANSWER
Answered 2021-Jun-16 at 00:46The issue you are having has nothing to do with templates. You cannot invoke std::async() on a member function without binding it to an instance. Wrapping the call in a lambda does the trick.
Here's an example:
QUESTION
So I created a poll model in my Django app. I'm going thorugh the polling app tutorial posted on the Django website, however, I'm using a remote MySQL database rather than a SQLite database.
...ANSWER
Answered 2021-Jun-15 at 20:06I'm thinking the suspect is an unsuccessful migration. Let's undo it and try again
QUESTION
I am trying to create an app in which the user has the option to query the database by entering information into one of two entry boxes. I want to be able to use a single select statement and conditionally query the database based on what box the user enter their information into. I currently am trying to use a CASE clause, but I believe that it is running into an error when I try to include a WHERE clause in the THEN argument. Here is what I am currently working with:
...ANSWER
Answered 2021-Jun-15 at 19:54Move the CASE expression to the WHERE clause:
QUESTION
My Question: What exactly does “compile-time” mean? I present my understanding below and where I am getting confused.
Compilation is the process that generates a single executable .exe file from the .vb file. There are several ways to do this, for example by using the VBC.EXE command from the developer command window or MSDOS. The way I understand “compile-time” is that it is time when such a command gets executed and the exe file is generated. The following are the what I find confusing:
- When I write Dim i = 5, the compiler infers or “knows” that the variable “i” is an integer.
- If I want to print an integer or a string using the Writeline method of the console class then the compiler automatically determines which overloaded version it should call. So in this case also the compiler “knows” – this is also known as compile-time polymorphism.
My confusion: Since in both the above cases the compiler infers or knows the type of variable or the version of the overloaded method to call just after we have finished typing the sentence, is this also called compile-time? We have not given any sort of compilation command here.
- Another confusion on the definition of compile-time refers to the case when we explicitly define overloaded methods. In the case of the writeline method, we know from the pop-up given by intellisense that immediately after we have finished typing the sentence the version with the correct signature is called. Now, when we define overloaded methods does the compiler know which version to call when we call the function (depending on signature) somewhere in the program right after we have finished typing the code? Or does the compiler know this after the exe file has been generated? This is a case of compile-time polymorphism. But then which time or which step is the “compile-time”?
ANSWER
Answered 2021-Jun-15 at 19:35We have not given any sort of compilation command here.
No, but most modern IDEs can do similar "static analysis" that compilers do to determine types, etc. Some even do a very lightweight "compile" to determine what overloads are appropriate, etc.
Also note that IDEs and the actual compiler may not always agree. IDE analysis is designed to be very fast, so the analysis done by the IDE may be less robust and less accurate than a static compiler.
So in a sense these are all "compile-time" in that the only information that is available is what is present in the code. This is opposed to "run-time" where other factors such as user input, environment, and state can change the flow and interpretation of the program in ways that the compiler could not account for.
QUESTION
I ran into less than ideal inlining behavior of the .NET JIT compiler. The following code is stripped of its context, but it demonstrates the problem:
...ANSWER
Answered 2021-Jun-15 at 19:35The functions Hash_Inline and Hash_FunctionCall are not equivalent:
- The first statement in
Hash_Inlinerotates by 1, but inHash_FunctionCallit rotates bycurIndex. - For
RotateLeftyou may have probably meant:
QUESTION
Consider the following code:
...ANSWER
Answered 2021-Jun-15 at 18:22i think you are looking for this:
QUESTION
I'm using glutin and so have a move closure for my program's main loop and I'm trying to play an audio file with the rodio crate. With the following code everything works and I get one beep every time the program loops:
ANSWER
Answered 2021-Jun-15 at 16:27Basically, the problem at hand is that rodio::Decoder::new consumes the value which it reads from (well, actually it is already consumed by BufReader::new). So, if you have a loop or a closure that can be called multiple times, you have to come up with a fresh value each time. This what File::open does in your first code snipped.
In your second code snipped, you only create a File once, and then try to consume it multiple times, which Rust's ownership concept prevents you from doing.
Also notice, that using reference is sadly not really an option with rodio since the decoders must be 'static (see for instance the Sink::append trait bound on S).
If you think your file system is a bit slow, and you want to optimize this, then you might actually want to read the entire file up-front (which File::open doesn't do). Doing this should also provide you with a buffer (e.g. a Vec) that you can clone, and thus allows to repeatedly create fresh values that can be consumed by the Decoder. Here is an example doing this:
QUESTION
Code 1
...ANSWER
Answered 2021-Jun-15 at 10:28For starters the compiler should issue a message for this code snippet
QUESTION
I am aware that floating-point numbers are tricky. But today I encountered a case that I cannot explain (and cannot reproduce using a standalone C++ code).
The code within a large project looks like this:
...ANSWER
Answered 2021-Jun-15 at 09:57Barring the undefined behavior which can be easily be fixed, you're seeing the effect of denormal numbers. They're extremely slow (see Why does changing 0.1f to 0 slow down performance by 10x?) so in modern FPUs there are usually denormals-are-zero (DAZ) and flush-to-zero (FTZ) flags to control the denormal behavior. When DAZ is set the denormals will compare equal to zero which is what you observed
Currently you'll need platform-specific code to disable it. Here's how it's done in x86:
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