CrossWindow | cross platform system abstraction library written in C++

by alaingalvan C++ Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | CrossWindow Summary

CrossWindow is a C++ library. CrossWindow has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A basic cross platform system abstraction library for managing windows and performing OS tasks.

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Quality

Security

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Support

CrossWindow has a low active ecosystem.

It has 438 star(s) with 42 fork(s). There are 16 watchers for this library.

It had no major release in the last 6 months.

There are 17 open issues and 4 have been closed. On average issues are closed in 57 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of CrossWindow is current.

Quality

CrossWindow has 0 bugs and 0 code smells.

Security

CrossWindow has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

CrossWindow code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

CrossWindow is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

CrossWindow releases are not available. You will need to build from source code and install.

Installation instructions, examples and code snippets are available.

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CrossWindow Key Features

No Key Features are available at this moment for CrossWindow.

CrossWindow Examples and Code Snippets

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Community Discussions

Trending Discussions on CrossWindow

What is the purpose of declaring a function as a pointer?

QUESTION

What is the purpose of declaring a function as a pointer?

Asked 2021-Feb-06 at 06:38

I was looking through the source code of a project called CrossWindow-Graphics today when I saw an interesting function declaration. The code seemed to be declared as a function pointer. Here is a similar example I wrote.

...

ANSWER

Answered 2021-Feb-06 at 06:38

All you've really done here is add an extra pair of () that doesn't do anything. We could write the same functin as

Source https://stackoverflow.com/questions/66074159

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