A-Maze | Arduino maze game

 by   alojzjakob C++ Version: Current License: GPL-3.0

kandi X-RAY | A-Maze Summary

kandi X-RAY | A-Maze Summary

A-Maze is a C++ library typically used in Internet of Things (IoT), Arduino, Pygame applications. A-Maze has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

Arduino maze game
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            kandi-support Support

              A-Maze has a low active ecosystem.
              It has 8 star(s) with 5 fork(s). There are 3 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              A-Maze has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of A-Maze is current.

            kandi-Quality Quality

              A-Maze has no bugs reported.

            kandi-Security Security

              A-Maze has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              A-Maze is licensed under the GPL-3.0 License. This license is Strong Copyleft.
              Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

            kandi-Reuse Reuse

              A-Maze releases are not available. You will need to build from source code and install.

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of A-Maze
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            A-Maze Key Features

            No Key Features are available at this moment for A-Maze.

            A-Maze Examples and Code Snippets

            Solve a maze .
            pythondot img1Lines of Code : 67dot img1License : Permissive (MIT License)
            copy iconCopy
            def solve_maze(maze: list[list[int]]) -> bool:
                """
                This method solves the "rat in maze" problem.
                In this problem we have some n by n matrix, a start point and an end point.
                We want to go from the start to the end. In this matrix ze  
            Runs a maze .
            pythondot img2Lines of Code : 40dot img2License : Permissive (MIT License)
            copy iconCopy
            def run_maze(maze: list[list[int]], i: int, j: int, solutions: list[list[int]]) -> bool:
                """
                This method is recursive starting from (i, j) and going in one of four directions:
                up, down, left, right.
                If a path is found to destinatio  
            Recursively removes all the paths from a maze .
            javadot img3Lines of Code : 33dot img3no licencesLicense : No License
            copy iconCopy
            static void allPath(String p, boolean[][] maze, int r, int c) {
                    if (r == maze.length - 1 && c == maze[0].length - 1) {
                        System.out.println(p);
                        return;
                    }
            
                    if (!maze[r][c]) {
                        return;
                

            Community Discussions

            QUESTION

            How to run pynput.Listener simultaneously with tkinter.Tk().mainloop()
            Asked 2019-Jul-03 at 15:34

            I am a teacher. I teach math, but since education is facing human resources crisis, I have some additional duties. I teach kids a bit of programming, they do quite well. Now I'd like to make with them a snake game, but I have a problem achieving multithreading in my GUI app.

            I found similar cases but no solutions. Like here: Using the keyboard to move the character in a maze and here: Tkinter.Tk() and threading

            ...

            ANSWER

            Answered 2019-Jul-03 at 14:29

            Listener is a thread, so if you join it your main thread will wait until its end to continue processing.

            You can just create a Listener object without the with statement and it will run along the main thread (until a callback function will return False)

            Source https://stackoverflow.com/questions/56871975

            QUESTION

            Canvas maze game smooth animation
            Asked 2019-Feb-13 at 05:12

            I am building a maze game based on this tutorial. I successfully got the player rectangle to continue moving as long as you hold down the arrow keys. When you first start the game, the animation is really nice and fast, but it seems that after playing the game for a few seconds the animation gets slower and slower. Can anyone help me figure out why this is happening?

            I have created a code snippet, but unfortunately it doesn't work correctly because of a cross-origin error caused by the maze image I am using.

            ...

            ANSWER

            Answered 2019-Feb-13 at 05:12

            The biggest problem here?
            Your timer.

            Let's remove everything related to the canvas and just try to log how many times per frame you are drawing this little time counter:

            Source https://stackoverflow.com/questions/54657448

            QUESTION

            Recursive path finding until result of division is 1
            Asked 2019-Jan-27 at 11:48

            I am trying to solve an exercise in recursion that goes like this. Say you have a matrix of nxm with integers like this(just an example):

            1 1 1 5 2 2 3 5 2 1 3 1 1 1 5 1 1 5 1 1

            I want to find a path (starting from anywhere) that, given a number n, every step n changes by n/(number_at_that_position) and the path stops when n = 1.

            I am not looking for all paths, I am just looking for a path. So if you use symbols to map the path, you would end up with a matrix

            > > V - * - - V > ^ - - V ^ - - - > ^ -

            Where '>' means a step right, '<' means a step left, '^' is a step up and 'V 'is a step down. Once n becomes 1, we insert '*' to say the path ended. Most important: The path has to be continuous and you cannot visit a place you have visited before. Even more important: The function that finds the path MUST be recursive. If no path is found, the code exits with a message saying that no path was found.

            Up to now I've come up with the following code for the path finding. I've used ideas from different places, but one of them is this one Recursively finding a path through a maze c++

            ...

            ANSWER

            Answered 2019-Jan-27 at 11:48

            QUESTION

            How to randomly create a fair maze for a multiplayer game?
            Asked 2018-Sep-12 at 08:35

            [Updated my questions at the end] I am creating a 2d multiplayer RTS game which happens inside a maze. I have used Growing Tree algorithm to randomly generate the maze. I thought that the maze would be fair for each team as long as each team's shortest path to solving the maze is equal to the other team. I made sure of that by making a rule in my game which dictates that each team start point is the other team's finish point and vice versa, so the shortest path would always be equal for both teams. but in practice, I noticed something else.

            this question sprang up on me when I was trying to make the resulting perfect maze to a non-perfect maze using this solution, specifically @tobias-k answer.

            if you already have a maze with a single path form start to goal, use this variant:

            • Do a Breadth First Search from both the start and the goal, and for each cell in the maze record the number of steps that cell is away from both the start and the goal.

            • Subdivide the maze by putting all cells that are closer to the start into the start set and all cells that are closer to the goal into the goal set.

            • Remove a wall between the two regions to add an additional path from start to goal.

            The generated paths might have (maybe even substantial) parts in common, but they should be unique loop-free paths from start to goal. Here's an illustration of the first case:

            the result of seperating the maze according to each cell distance from start or end point

            However, when I use BFS to calculate all distances from my start and finish point, and before removing a wall to create a non-perfect maze, I mostly get something like this:

            in this picture, 336 cells are closer to team Red start point and only 105 are closer to Team Blue start point. Even removing a wall (or more than just one wall) between these two sections does not help the situation.

            My game is about collecting the treasures that are randomly spread throughout the maze and getting out before the other team exits the maze, this resulting mazes are totally unfair because it gives one team the higher chance of reaching more treasures in the maze sooner compared to the other team.

            so my qustions are:

            1. Does the mentioned results of growing tree maze generator means that the maze is not fair for a multiplayer game (for simplicity lets just imagine the game happens between two players)?
            2. Do I need to change my maze generator to something that produces a uniform texture, like Wilson's or Aldous-Broder Algorithm? (this is based on algorithms introduced by Astrolog)
            3. @btilly suggest to use a Symmetric maze to solve the problem of the maze being fair, but now I have to ask which one guarantees to create a fair random maze: a symmetric approach (like the one proposed in this article or a uniform one (like Wilson's algorithm)?
            ...

            ANSWER

            Answered 2018-Sep-10 at 20:31

            One solution is to build a rotationally symmetric maze. Start from each end, growing, growing the other at the same time. Then when you have filled things, open a wall to a point where the length from one is close to the length from the other.

            Now you'll have a maze where both teams have the same length path and very, very fair opportunities.

            Source https://stackoverflow.com/questions/52261293

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install A-Maze

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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          • HTTPS

            https://github.com/alojzjakob/A-Maze.git

          • CLI

            gh repo clone alojzjakob/A-Maze

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            git@github.com:alojzjakob/A-Maze.git

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