thrust | based cross-platform / cross-language application framework

 by   breach C++ Version: v0.7.6 License: MIT

kandi X-RAY | thrust Summary

kandi X-RAY | thrust Summary

thrust is a C++ library. thrust has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

Thrust is based on Chromium's Content Module and is supported on Linux, MacOSX and Windows:.
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              thrust has a medium active ecosystem.
              It has 2781 star(s) with 130 fork(s). There are 95 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 47 open issues and 140 have been closed. On average issues are closed in 219 days. There are 3 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of thrust is v0.7.6

            kandi-Quality Quality

              thrust has no bugs reported.

            kandi-Security Security

              thrust has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              thrust is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              thrust releases are available to install and integrate.
              Installation instructions are not available. Examples and code snippets are available.

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            thrust Key Features

            No Key Features are available at this moment for thrust.

            thrust Examples and Code Snippets

            No Code Snippets are available at this moment for thrust.

            Community Discussions

            QUESTION

            calling a __host__ function from a __host__ __device__ functon is not allowed
            Asked 2021-Jun-14 at 14:06

            I am trying to use thrust with Opencv classes. The final code will be more complicated including using device memory but this simple example does not build successfully.

            ...

            ANSWER

            Answered 2021-Jun-14 at 14:06

            As pointed out in the comments, for the code you have shown, you are getting a warning and this warning can be safely ignored.

            For usage in CUDA device code:

            For a C++ class to be usable in CUDA device code, any relevant member functions that will be used explicitly or implicitly in CUDA device code, must be marked with the __device__ decorator. (There are a few exceptions e.g. for defaulted constructors which don't apply here.)

            The OpenCV class you are attempting to use (cv::KeyPoint), doesn't meet these requirements for use in device code. It won't be usable as-is.

            There may be a few options:

            1. Recast your work using cv::KeyPoint to use some class that provides similar functionality, that you write yourself, in such a way as to be properly designed and decorated.

            2. Perhaps see if OpenCV built with CUDA has an alternate version here (properly designed/decorated) (my guess would be it probably doesn't)

            3. Rewrite OpenCV itself, taking into account all necessary design changes to allow the cv::KeyPoint class to be usable in device code.

            4. As a variant of suggestion 1, copy the relevant data .response to a separate set of classes or just a bare array, and do your selection work based on that. The selection work done there can be used to "filter" the original array.

            Source https://stackoverflow.com/questions/67966538

            QUESTION

            Amazon S3 redundancy over Availability Zones vs. over Regions
            Asked 2021-Jun-11 at 13:30

            This https://aws.amazon.com/blogs/storage/architecting-for-high-availability-on-amazon-s3/#:~:text=Amazon%20S3%20maintains%20redundancy%20even%20within%20one%20of,can%20still%20access%20their%20data%20with%20no%20downtime states the following:

            Amazon S3 storage classes replicate their data on more than three Availability Zone (except for S3 One Zone-Infrequent Access).

            What's the point of this article https://aws.amazon.com/blogs/startups/large-scale-disaster-recovery-using-aws-regions/ stating:

            S3 snapshots: We rely on the cross s3 sync and this works like a charm. We are able to copy the data from our primary to the DR region within a matter of few minutes.

            The latter seem superfluous now and is from 2017, so may be it is out-dated? Or is it the thrust that we should also be be placing Amazon S3 copies over over Regions? I see no such need as the AZ's within a Region are physically separated from each other. What am I missing?

            ...

            ANSWER

            Answered 2021-Jun-11 at 13:30

            S3 buckets are region specific. When you create a new bucket you need to select the target region for that bucket.

            For DR reasons, you can keep backups in another region. Should the primary region fail in a way that the entire region is affected, then you could restore in the backup region.

            Your DR strategy will depend on your use case, and your needs for returning services back to normal in case of region wide failure.

            For example, let's say you rely on ec2/ebs to operate your service and those services suffer region wide outage for 5 hours. In order to recover your service you would need to move to a region where the resources are available. Assuming you need S3 data for operational processing you would want to have that data ready in the Target recovery region.

            Source https://stackoverflow.com/questions/67937412

            QUESTION

            Pytorch custom CUDA extension build fails for torch 1.6.0 or higher
            Asked 2021-May-10 at 13:55

            I have a custom CUDA extension for pytorch (https://pytorch.org/tutorials/advanced/cpp_extension.html), which used to work fine with pytorch1.4, CUDA10.1, and Titan Xp GPUs. However, recently we changed our system to new A40 GPUs and CUDA11.1. When I try to build my custom pytorch extension using CUDA11.1, pytorch 1.8.1, gcc 9.3.0, and Ubuntu 20.04 I get the following errors:

            ...

            ANSWER

            Answered 2021-May-10 at 13:55

            I found the issue. The Intel MKL module wasn't loaded properly and caused the error. After fixing this the compilation worked just fine also with CUDA 11.1 and pytorch 1.8.1!

            Source https://stackoverflow.com/questions/67386709

            QUESTION

            Pattern finding
            Asked 2021-May-10 at 13:40

            I have a pretty long string(called 'my_string') without new lines included. I have been trying to use regexp in JavaScript to find specific words in 'my_string'. Below is the code description

            ...

            ANSWER

            Answered 2021-May-10 at 13:40

            Other than a few minor mistakes in your regex, you need to use .+? instead of .+, because the second one is "greedy" which means, it will match as much as it can get.

            Source https://stackoverflow.com/questions/67471225

            QUESTION

            trackbar in visualbasic windowsform cannot be deselected
            Asked 2021-May-07 at 08:11

            I am making a basic lunar lander program in visual basic using windows forms. I have a track bar to adjust thrust. I am also using WASD to control the landers direction. WASD works fine if I haven't used the track bar to adjust the thrust. But the moment I adjust the thrust the trackbar becomes selected and I cannot use the WASD keys anymore. What do I need to do to fix this issue?picture of program

            ...

            ANSWER

            Answered 2021-May-07 at 08:11

            To expand on Ahmed's comment, if you set KeyPreview to true then the form will experience the key events before any selected control on the form does.

            Source https://stackoverflow.com/questions/67426258

            QUESTION

            Operator '*' cannot be applied to operands of type 'void' and 'float'
            Asked 2021-May-05 at 02:51
            ***
            
            ...

            ANSWER

            Answered 2021-May-05 at 02:51

            forceDirection.Normalize() alters the forceDirection vector and returns void, rather than returning the normalized vector. So you'll need to split the Normalize() call and the multiplication into separate statements:

            Source https://stackoverflow.com/questions/67394468

            QUESTION

            Pass thrust device_vectors to device function and modify them
            Asked 2021-May-04 at 20:52

            when I'm running this piece of code, the compiler says I'm calling a host function from global function. I want to assing something a bit more complicated than zeros to A[i] and B[i] but I just wanted to test the functionality. I need to modify values in both vectors. Later I'd like to reduce the table A.

            ...

            ANSWER

            Answered 2021-May-04 at 20:52

            In spite of its naming, a thrust::device_vector is not directly usable in CUDA device code. The device_vector is an object/container, and it is intended to be usable in host code only. This is why you get the messages about "calling a host function..."

            For the example you have shown here, to access the data directly, you would (in host code) extract device pointers to the underlying data in each container (A and B) and pass those pointers to your CUDA kernel.

            Something like this:

            Source https://stackoverflow.com/questions/67391625

            QUESTION

            Passing a ColorPicker selection to a different view in SwiftUI
            Asked 2021-May-02 at 17:07

            I think I'm close but also missing something fundamental here with SwiftUI and passing data.

            1. I have a top-level Color var called "masterColor" which I house in my "DataModel" struct.
            2. Then in my view "NightLight", I have a system "ColorPicker", where I use a local var "localColor" to reflects whatever value the ColorPicker has.
            3. Finally I have a "BackgroundControllerView", which sets a background color (which I would like to read the dataModel.masterColor)

            What I'm trying to do set the dataModel.masterColor (which my whole app can see) equal to my localColor, which only NightLight can see. I've simplified the structure here a bit but the thrust of the question is about how to take local data and set something global equal to it for the rest of the app to see.

            ...

            ANSWER

            Answered 2021-May-02 at 17:07

            There's no need to have a separate localColor. You can directly pass in $dataModel.masterColor to the picker.

            Source https://stackoverflow.com/questions/67358721

            QUESTION

            CUDA: Using device functors in kernels
            Asked 2021-Apr-23 at 11:50

            I tried to make a device functor that essentially performs (unoptimized) matrix-vector multiplication like so

            ...

            ANSWER

            Answered 2021-Apr-23 at 11:50

            Forgot to use ceil when calculating grid dimensions.

            Source https://stackoverflow.com/questions/67229383

            QUESTION

            Is it necessary do a cudaMalloc and cudaMemcpy with a thrust::device_vector?
            Asked 2021-Apr-20 at 15:54

            I am a newbie with CUDA. I have read that it is necesary to allocate variables with cudaMalloc and then use cudaMemcpy to copy the values to the device variables. Something like this:

            ...

            ANSWER

            Answered 2021-Apr-20 at 15:54

            Thrust does all CUDA API calls for you. So while you can use Thrust algorithms on manually allocated memory or pass the memory from a thrust::device_vector to a kernel, you don't need cudaMalloc and cudaMemcpy, as everything is already included in the standard C++ vector interface.

            The memory allocated by thrust::device_vector lives on the GPU (if you are using one. One can use Thrust for parallelizing on the CPU as well). So the constructor calls cudaMalloc for you.

            For data transfer you can use different thrust::device_vectors and thrust::host_vectors like normal std::vectors (e.g. constructors and operator= are implemented for the different combinations). Thrust knows what to do with each type of vector and will call cudaMemcpy for you. If this isn't explicit enough for you, you can also use thrust::copy.

            Your code could look the following way:

            Source https://stackoverflow.com/questions/67181635

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

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            Install thrust

            You can download it from GitHub.

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