aco | A C Ant Colony Optimization algorithm

 by   diogo-fernan C++ Version: Current License: Non-SPDX

kandi X-RAY | aco Summary

kandi X-RAY | aco Summary

aco is a C++ library. aco has no bugs, it has no vulnerabilities and it has low support. However aco has a Non-SPDX License. You can download it from GitHub.

aco is an ISO C++ Ant Colony Optimization (ACO) algorithm (a metaheuristic optimization technique inspired on ant behavior) for the traveling salesman problem. It releases a number of ants incrementally whilst updating pheromone concentration and calculating the best graph route. In the end, the best route is printed to the command line. aco was developed a few years back for academic and research purposes based on "Computational Intelligence: An Introduction" (first edition from 2002) by Andries Engelbrecht. This algorithm is available for anyone interested in ACO methods, so feel free to explore it and tweak parameters.
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              aco has a low active ecosystem.
              It has 31 star(s) with 29 fork(s). There are 5 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 3 have been closed. On average issues are closed in 140 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of aco is current.

            kandi-Quality Quality

              aco has no bugs reported.

            kandi-Security Security

              aco has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              aco has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

            kandi-Reuse Reuse

              aco releases are not available. You will need to build from source code and install.

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            aco Key Features

            No Key Features are available at this moment for aco.

            aco Examples and Code Snippets

            No Code Snippets are available at this moment for aco.

            Community Discussions

            QUESTION

            MySQL query to calculate distance between two coordinates but too slow with HAVING clause
            Asked 2021-Jun-10 at 17:47

            I have the following query that calculates the distance between two coordinates. However, I want to select the users that are within the range of n km. Say, for example, I want to select all users that are within a distance of 100km. Therefore, I have to use HAVING clause here. However, I see that the execution is damn too slow. Even with just two records it's returning the results very slowly. I wonder what would happen with a million user records (in future). Therefore, I am seeking an optimization to my current query for efficient and faster running.

            ...

            ANSWER

            Answered 2021-Jun-10 at 08:01

            The way to do what you want would be repeating the code on your select in the where section

            Source https://stackoverflow.com/questions/67916945

            QUESTION

            Optimize c++ Monte Carlo simulation with long dynamic arrays
            Asked 2021-Jun-10 at 13:17

            This is my first post here and I am not that experienced, so please excuse my ignorance.

            I am building a Monte Carlo simulation in C++ for my PhD and I need help in optimizing its computational time and performance. I have a 3d cube repeated in each coordinate as a simulation volume and inside every cube magnetic particles are generated in clusters. Then, in the central cube a loop of protons are created and move and at each step calculate the total magnetic field from all the particles (among other things) that they feel.

            At this moment I define everything inside the main function and because I need the position of the particles for my calculations (I calculate the distance between the particles during their placement and also during the proton movement), I store them in dynamic arrays. I haven't used any class or function,yet. This makes my simulations really slow because I have to use eventually millions of particles and thousands of protons. Even with hundreds it needs days. Also I use a lot of for and while loops and reading/writing to .dat files.

            I really need your help. I have spent weeks trying to optimize my code and my project is behind schedule. Do you have any suggestion? I need the arrays to store the position of the particles .Do you think classes or functions would be more efficient? Any advice in general is helpful. Sorry if that was too long but I am desperate...

            Ok, I edited my original post and I share my full script. I hope this will give you some insight regarding my simulation. Thank you.

            Additionally I add the two input files

            parametersDiffusion_spher_shel.txt

            parametersIONP_spher_shel.txt

            ...

            ANSWER

            Answered 2021-Jun-10 at 13:17

            I talked the problem in more steps, first thing I made the run reproducible:

            Source https://stackoverflow.com/questions/67905839

            QUESTION

            How to calculate the area of two circles' intersection?
            Asked 2021-May-28 at 04:06

            The topic link: https://codeforces.com/problemset/problem/600/D

            For the question, I'm wrong answer on test28, which could look like this:

            correct answer:119256.95877838134765625000

            my answer: 120502.639190673828125

            I guess it is caused by calculation accuracy, but I don't have evidence. Maybe algorithm itself is faulty, please point it out.

            Algorithm ideas:

            For any given two circles, in order to simplify the calculation, we can translate the origin of the coordinates to the center of one of the circles, and then rotate the other circle to the x-axis by rotating. For calculating the intersection area of the circles, before and after are equivalent, and finally a purple circle and a red circle are formed. In fact, the final intersection area is equal to the sum of the areas of the two sectors minus the area of the diamond in the middle(the figure below, Horizontal axis x, vertical axis y). However, before that, we must first calculate the intersection point of the two circles.

            The coordinates of the center of the first circle at the beginning: .

            The coordinates of the center of the second circle at the beginning: .

            The coordinates of the center of the first circle after a series of transformations: .

            The coordinates of the center of the second circle after a series of transformations: ,

            .

            The equations of two circles are combined:

            are the radius of the first and second circles respectively,so:

            we can use the sector area formula : ,

            , .

            In this place, there will be problems with the positive and negative values of the radian(the two figures below), but it can be proved that they can be absorbed in the final result.

            The final result is the sum of the areas of the two arcs minus the area of the middle diamond.

            mycode:

            ...

            ANSWER

            Answered 2021-May-27 at 06:10

            Don't use too many intermediate floating variables to get to the final answer. Small inaccuracies when add up lead to huge inaccuracy which you can clearly see in the expected and real output in your question. What you can do is to minimize these intermediate floating variables. For example

            Source https://stackoverflow.com/questions/67715025

            QUESTION

            Product Search using geolocation of shops
            Asked 2021-May-23 at 16:47

            I am new to Laravel and I am trying to search for product using nearby shops Here is my code

            ...

            ANSWER

            Answered 2021-May-23 at 16:47

            I am really confused, why are you using products() after orderBy and all the other clauses ?

            If you are trying to get products from a shop, you do not have to do products(), you have to use Product::...., but if you want to get shops related to products you have to use whereHas('products', ....), read more about it here.

            Your code should be like this:

            Source https://stackoverflow.com/questions/67661730

            QUESTION

            Converting 3D rotation to 2D rotation
            Asked 2021-May-23 at 14:17

            I've been trying to figure out the 2D rotation value as seen from orthographic "top" view for a 3D object with XYZ rotation values in Maya. Maybe another way to ask this could be: I want to figure out the 2D rotation of a 3D obj's direction.

            Here is a simple image to illustrate my question:

            I've tried methods like getting the twist value of an object using quaternion (script pasted below), to this post I've found: Component of a quaternion rotation around an axis.

            If I set the quaternion's X and Z values to zero, this method works half way. I can get the correct 2D rotation even when obj is rotated in both X and Y axis, but when rotated in all 3 axis, the result is wrong.

            I am pretty new to all the quaternion and vector calculations, so I've been having difficulty trying to wrap my head around it.

            ;)

            ...

            ANSWER

            Answered 2021-May-22 at 10:03

            I'm not familiar with the framework you're using, but if it does what it seems, I think you're almost there. Just don't zero out the X and Z components of the quaternion before calling quaternionTwist().

            The quaternions q1 = (x,y,z,w) and q2 = (0, y, 0, w) don't represent the same rotation about the y-axis, especially since q2 written this way becomes unnormalized, so what you're really comparing is (x,y,z,w) with (0, y/|q2|, 0, w/|q2|) where |q2| = sqrt(y^2 + w^2).

            Source https://stackoverflow.com/questions/67647973

            QUESTION

            Table with mapped object only getting the last value
            Asked 2021-May-22 at 07:33

            I have an data object with an array of data that I mapped inside a table. It looks fine, but when I console.log() the id of the item of any of the table´s rows, it always get the value of the last item of the array.

            This is my data:

            ...

            ANSWER

            Answered 2021-May-22 at 07:33

            The reason it always log 'uuid4' in the console, is because menu with the id uuid4 is rendered last and it overlaps the other menus. all your menu share the same ancherEl so they will render on the same position. And you can only see the last menu.(uuid4). when you close your menu, they will close together, And click another button, they will render that position, and so on.

            I think it can help you.

            Source https://stackoverflow.com/questions/67645426

            QUESTION

            How to make clusters based on a fixed capacity of each cluster in R?
            Asked 2021-May-21 at 07:53

            So I have a dataset with 600 points, their latitude, longitude, and demands. I have to make clusters such that for each cluster the points will be near each other and the total capacity of that cluster will not exceed a certain limit.

            A sample dataset for the problem:

            ...

            ANSWER

            Answered 2021-May-18 at 12:21

            Something like this might get you started?

            Source https://stackoverflow.com/questions/67582530

            QUESTION

            ld: undefined reference to `lua_`. I don't know why ld cannot reference lua even though its there
            Asked 2021-May-19 at 14:49

            I'm trying to install the code from this git-repo for a university project and I'm stuck because ld does not seem to be able to link lua properly. I followed the install instructions and compile the code with:

            ...

            ANSWER

            Answered 2021-May-19 at 13:22

            Lua can be compiled both as C ans C++ languages. This is an advertised feature of it. For that reason, Lua authors decided not to include the classic extern "C" in the headers.

            Your liblua5.2.so.5.2 library was compiled in C language and the symbols are not mangled. You compiled your application in C++ mode with just including Lua headers without extern "C", so your Lua included symbols are mangled.

            Solution: wrap your include with extern "C":

            Source https://stackoverflow.com/questions/67603835

            QUESTION

            Why cannot get the distance using both location which fetch from firebase realtime database
            Asked 2021-May-18 at 11:39

            I am new in Java and Firebase. Now I have try to using the geolocation of two location that get from database and calculate the distance in km using the geolocation formula. The coding as shown below.

            ...

            ANSWER

            Answered 2021-May-18 at 11:39

            use this function for calculating the distance of two location. I used that in my last project and I'm sure about that:

            Source https://stackoverflow.com/questions/67585250

            QUESTION

            Laravel doubles the route when navigating between navbar links
            Asked 2021-May-16 at 13:34

            I have a problem with laravel routes. I have a navbar with the urls /products and /employee. I manage to switch between perfectly perfectly without giving error. However, when I access the link /products/new and from there I try to go back to /products or go to /employees through the navbar, the link is /products/products or /employee/employee. How do I not replicate the links?

            Routes

            ...

            ANSWER

            Answered 2021-May-16 at 13:34

            Can show you the navbar ? Maybe it's because you redefine the value of the variable $current every time you extend "layout.app". If in your return links in your navbar you use the value of the variable $current, by redefining them in each blade the values will be changed.

            Another remark you should use the following syntax for your href: For the new Product for exemple

            Source https://stackoverflow.com/questions/67554709

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

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            You can download it from GitHub.

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