range-v3 | Range library for C++14/17/20 , basis for C++20 's std : :ranges | Hashing library
kandi X-RAY | range-v3 Summary
kandi X-RAY | range-v3 Summary
Range library for C14/17/20. This code was the basis of [a formal proposal] to add range support to the C standard library. That proposal evolved through a Technical Specification, and finally into [P0896R4 "The One Ranges Proposal"] which was merged into the C++20 working drafts in November 2018.
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Community Discussions
Trending Discussions on range-v3
QUESTION
I'm new to range-v3. I started by write a program that generates a range of integers, modifies it, and prints out the resulting range. I used a modifier from the actions
library, which rendered my code non-iterable.
Could someone help me understand how to convert a ranges::action::action_closure
into an iterable?
Here's the example I started with - a function that generates and prints out a range of numbers. This code works fine and compiles.
...ANSWER
Answered 2022-Mar-27 at 21:22Actions do not return a light-weight ephemeral object that can be lazily iterated over like view operations do. Actions are applied eagerly to actual containers and return actual containers, but still can be composed together.
In the following std::vector()
is an r-value that gets filled via push_back
which returns an r-value that is then passed to the reverse action. All of this processing happens eagerly, akin to normal nested function calls but using the pipeline syntax:
QUESTION
In the following code, auto [i, e]
and auto&& [i, ee]
both bind std::pair
rather than std::pair
. Could some explain how could have known this without testing empirically? I assume it's the range-v3 implementation. Is there a case where you would want to use auto&&
rather than auto
?
ANSWER
Answered 2022-Jan-14 at 20:05To find the type when you dereference an iterator to a given range, you can
QUESTION
I am trying to convert a vector to a string and join with C++20(MSVC on visual studio 19 v142, c++latest).
...ANSWER
Answered 2021-Sep-21 at 14:30In the original design of views::join
, it didn't just join any range of ranges, it had to be a range of reference to ranges.
This worked:
QUESTION
C++20 ranges::sort
supports projections, and that is great, but I want to do stuff that is more complex, in particular sort on result of function that operates on projected member.
For function call I tried the transform and then sort that view, but C++20 sort seems to not work on views, this answer explains why(for range-v3).
In other words can I write this without using a lambda/functor?
...ANSWER
Answered 2021-Sep-09 at 13:01You can use views::transform
if your S
has only one member:
QUESTION
I'm using range-v3 by Eric Niebler and using the ranges::views::group_by
function.
In the documentation for group_by
it says: "Given a source range and a binary predicate, return a range of ranges where each range contains contiguous elements from the source range such that the following condition holds: for each element in the range apart from the first, when that element and the first element are passed to the binary predicate, the result is true. In essence, views::group_by groups contiguous elements together with a binary predicate."
So, it returns a range and ranges. My question is how do I access the range of ranges individually? I've tried all the using ways of accessing ranges: p[0].first, p.at(0).first, p.begin.first etc. but no joy.
I have the following code:
...ANSWER
Answered 2021-Sep-08 at 13:53p
isn't a random access range (it can't be), so there isn't going to be support for indexing (i.e. [0]
). And then p
isn't a range of pairs, it's a range of range of pairs.
All views have a front()
member function that they inherit from view_interface
so if you want to print the first
and second
members of the first subrange of the first range, you can do:
QUESTION
I've been trying to understand the Range-v3 join
documentation but I'll be honest, I don't understand it. And I've not been able to find any relevant examples either.
Could someone show me how to create a joined view of two deque vectors please. I've already tried these methods but to no avail.
...ANSWER
Answered 2021-Jun-29 at 09:52As a general suggestion, whenever you want the doc for something which is in Range-v3, pray it is in C++20 too, and refer to that. That's the case for join
(but not for concat
, apparently).
You're looking for concat
, not join
:
QUESTION
I have a pair of iterator, and I would like to use ranges::views::filter(some_predicate)
on it (with the pipe operator). AFAIU I should first convert my pair of iterator into a view. I tried to use ranges::subrange(first, last)
to do so, but I’m getting horrible error messages.
Note1: I’m using C++14 and range-v3 version 0.9.1 (the last version compatible with gcc-5.5). If the solution differs when using C++17/20 and/or when using C++20 std::ranges, I’m also interested to know what changed.
Note2: I find the documentation of range-v3 severely lacking, so I’m using cppreference.com. If you know a better documentation, I’m very interested.
EDIT:
In my real code, I’m wrapping a java-style legacy iterator (that has a next()
method instead of operator++
/operator*
. I’m wrapping them in a C++-compatible wrapper. Then I tried to convert that wrapper into a view, and finally filter it. I reproduce a minimal example on godbolt. This use iterator_range
as suggested, but it still doesn’t compile (see the second edit below).
ANSWER
Answered 2021-Apr-08 at 16:24In ranges-v3, there is iterator_range
which you can use to wrap the iterators into a range object.
In C++20, you can use std::span
to wrap those iterators into an range object
QUESTION
I'm trying to link OpenGL to an application for Windows (building on Windows).
I'm using Conan as package manager, CMake for building and MSVC as compiler (and CLion as IDE).
The program compiles, but I have linker errors, for what I believe to be extension functions in OpenGL:
...ANSWER
Answered 2021-Jun-10 at 14:30I'm compiling with
GL_GLEXT_PROTOTYPES=1
.
Well, don't do that. That is never going to work in a portable way. On windows, the opengl32.dll
always exports only the functions which are in OpenGL 1.1, and for everything beyond that, you have to rely to the OpenGL extension loading mechanism at runtime.
I have tried:
- [...]
- Adding GLEW
That's a step in the right direction. But this does not make things to magically work. A GL loader like GLEW typically brings its own header as a replacement for GL.h
and glext.h
etc., and the typical GL loader (like GLEW) simply re-define every GL functions as a macro, like this:
QUESTION
I found that c++20 ranges::basic_istream_view
is slightly different from the range-v3 version.
The most important difference is that the std::ranges::basic_istream_view
does not cache its begin()
, so that each begin()
s will return the next iterator with the value that has been read (godbolt):
ANSWER
Answered 2021-May-14 at 12:53input iterators are such that as soon as you have dereferenced one, you need to instantly increment it. The same is with output iterators, such as back_insert_iterator. This is something that you are just not supposed to be doing. If you need the first value cached, cache it yourself.
The reason input and output iterators need to be incremented after dereferencing is that they are by design single pass.If you have read something from a stream, you cannot read it again. Operator * actually reads from the stream. What does ++ do? Nothing! Same goes for back_insert_iterator
QUESTION
Here in a simple pipeline of views
adaptors, there is the gen
function called to generate a sequence of values (using an internal state) and then a filter on it.
What is surprising and counterintuitive (at least for me) is the fact that the generator function is called twice at each iteration, so that the next check on the same filter fails (the filtered value is not reused in the pipeline).
Do you have an idea if this is the correct expected behavior (and why)?
Tested with libstdc++
in GCC 10.3, 11.1 & trunk (code) and range-v3
with GCC & clang (code).
ANSWER
Answered 2021-Apr-29 at 17:43Do you have an idea if this is the correct expected behavior (and why)?
Yes: this is the expected behavior. It is an inherent property of the iteration model where we have operator*
and operator++
as separate operations.
filter
's operator++
has to look for the next underlying iterator that satisfies the predicate. That involves doing *it
on transform
's iterator which involves invoking the function. But once we find that next iterator, when we read it again, that will again invoke the transform. In a code snippet:
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