MAJOR | Meta-Analysis for JAMOVI | Data Visualization library
kandi X-RAY | MAJOR Summary
kandi X-RAY | MAJOR Summary
Meta-Analysis Module for JAMOVI. If there’s something missing please open an issue and I’ll be sure to give it a look. You will first need to download Jamovi. To install this module download the file MAJOR.jmo and select it using the sideload feature in Jamovi.
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QUESTION
ANSWER
Answered 2022-Apr-08 at 15:31Consider a typical use case of a std::any
: You pass it around in your code, move it dozens of times, store it in a data structure and fetch it again later. In particular, you'll likely return it from functions a lot.
As it is now, the pointer to the single "do everything" function is stored right next to the data in the any
. Given that it's a fairly small type (16 bytes on GCC x86-64), any
fits into a pair of registers. Now, if you return an any
from a function, the pointer to the "do everything" function of the any
is already in a register or on the stack! You can just jump directly to it without having to fetch anything from memory. Most likely, you didn't even have to touch memory at all: You know what type is in the any
at the point you construct it, so the function pointer value is just a constant that's loaded into the appropriate register. Later, you use the value of that register as your jump target. This means there's no chance for misprediction of the jump because there is nothing to predict, the value is right there for the CPU to consume.
In other words: The reason that you get the jump target for free with this implementation is that the CPU must have already touched the any
in some way to obtain it in the first place, meaning that it already knows the jump target and can jump to it with no additional delay.
That means there really is no indirection to speak of with the current implementation if the any
is already "hot", which it will be most of the time, especially if it's used as a return value.
On the other hand, if you use a table of function pointers somewhere in a read-only section (and let the any
instance point to that instead), you'll have to go to memory (or cache) every single time you want to move or access it. The size of an any
is still 16 bytes in this case but fetching values from memory is much, much slower than accessing a value in a register, especially if it's not in a cache. In a lot of cases, moving an any
is as simple as copying its 16 bytes from one location to another, followed by zeroing out the original instance. This is pretty much free on any modern CPU. However, if you go the pointer table route, you'll have to fetch from memory every time, wait for the reads to complete, and then do the indirect call. Now consider that you'll often have to do a sequence of calls on the any
(i.e. move, then destruct) and this will quickly add up. The problem is that you don't just get the address of the function you want to jump to for free every time you touch the any
, the CPU has to fetch it explicitly. Indirect jumps to a value read from memory are quite expensive since the CPU can only retire the jump operation once the entire memory operation has finished. That doesn't just include fetching a value (which is potentially quite fast because of caches) but also address generation, store forwarding buffer lookup, TLB lookup, access validation, and potentially even page table walks. So even if the jump address is computed quickly, the jump won't retire for quite a long while. In general, "indirect-jump-to-address-from-memory" operations are among the worst things that can happen to a CPU's pipeline.
TL;DR: As it is now, returning an any
doesn't stall the CPU's pipeline (the jump target is already available in a register so the jump can retire pretty much immediately). With a table-based solution, returning an any
will stall the pipeline twice: Once to fetch the address of the move function, then another time to fetch the destructor. This delays retirement of the jump quite a bit since it'll have to wait not only for the memory value but also for the TLB and access permission checks.
Code memory accesses, on the other hand, aren't affected by this since the code is kept in microcode form anyway (in the µOp cache). Fetching and executing a few conditional branches in that switch statement is therefore quite fast (and even more so when the branch predictor gets things right, which it almost always does).
QUESTION
the problem seems to be with mongoose & mongodb packages as it works fine when
...ANSWER
Answered 2021-Sep-03 at 04:51Check your node version, if it's lower than 12 it won't work, if that's the case updating node should do do the job. You could downgrade your mongoose version too.
There's an issue closed on Mongoose github page. https://github.com/Automattic/mongoose/issues/10638
QUESTION
I was setting up my new Mac for my eks environment. After the installation of kubectl, aws-iam-authenticator and the kubeconfig file placement in default location. I ran the command kubectl command and got this error mentioned below in command block.
My cluster uses v1alpha1 client auth api version so basically i wanted to use the same one in my Mac as well.
I tried with latest version (1.23.0) of kubectl as well, still the same error. Whereas When i tried to do with aws-iam-authenticator (version 0.5.5) I was not able to download lower version.
Can someone help me to resolve it?
...ANSWER
Answered 2022-Mar-28 at 09:41I have the same problem
You're using aws-iam-authenticator
0.5.5
, AWS changed the way it behaves in 0.5.4
to require v1beta1
.
It depends on your configuration, but you can try to change the K8s context you're using to v1beta1
Otherwise switch back to aws-iam-authenticator
0.5.3
- you might need to build it from source if you're using the M1 architecture as there's no darwin-arm64
binary built for it
QUESTION
I am getting a
...ANSWER
Answered 2022-Mar-18 at 20:51std::lower_bound
takes a Cpp17ForwardIterator, which must also be a Cpp17InputIterator. The Cpp17InputIterator requirements include:
*a
reference
, convertible to T
Here, a
is a "value of type X
or const X
", so MSVC is justified in requiring a const-qualified unary indirection operator; the "or" means that the code using the iterator can use either, and the author of the iterator has to support both. (Note that Cpp17InputIterator differs from Cpp17OutputIterator, where the required operation is *r = o
, with r
a non-const reference, X&
.)
So your operator*
should have const
qualification, and return a reference; specifically, a reference to T
or const T
(this is a Cpp17ForwardIterator requirement). You can satisfy this straightforwardly with using reference = const T&
and by making cur_
and cur_valid_
mutable
.
The use of mutable
here is entirely legitimate; since operator*() const
is idempotent, it is "logically const" and the modifications to the data members are non-observable.
QUESTION
I tried to run it and it said an error like the title. and this is my code:
...ANSWER
Answered 2021-Aug-28 at 07:49From the Mongoose 6.0 docs:
useNewUrlParser, useUnifiedTopology, useFindAndModify, and useCreateIndex are no longer supported options. Mongoose 6 always behaves as if useNewUrlParser, useUnifiedTopology, and useCreateIndex are true, and useFindAndModify is false. Please remove these options from your code.
QUESTION
I have installed Android Studio Canary 2020.3.1.22
and trying to run Flutter
project on Apple Silicon(ARM) Mac
. Unfortunately, it is giving me this error when I try to run default
flutter counter app.
Here is the error I am getting:
...ANSWER
Answered 2022-Jan-03 at 06:03Basically, I installed jdk using brew install java
which was not compatible with my current gradle I guess. So
- I uninstalled java first using:
brew uninstall java
- installed
JDK 8 or JDK 11
from azul. - Installed gradle: gradle-6.9-all.zip
When done, everything worked smoothly.
QUESTION
When I open Android Studio I receive a notification saying that an update is available:
...ANSWER
Answered 2022-Feb-10 at 11:09This issue was fixed by Google (10 February 2022).
You can now update Android Studio normally.
Thank you all for helping to bring this problem to Google's attention.
QUESTION
I am sorry but I am really confused and leery now, so I am resorting to SO to get some clarity.
I am running Android Studio Bumblebee and saw a notification about a major new release wit the following text:
...ANSWER
Answered 2022-Feb-10 at 11:10This issue was fixed by Google (10 February 2022).
You can now update Android Studio normally.
QUESTION
I am using MongoDB(Mongo Atlas) in my Django app. All was working fine till yesterday. But today, when I ran the server, it is showing me the following error on console
...ANSWER
Answered 2021-Oct-03 at 05:57This is because of a root CA Let’s Encrypt uses (and Mongo Atals uses Let's Encrypt) has expired on 2020-09-30 - namely the "IdentTrust DST Root CA X3" one.
The fix is to manually install in the Windows certificate store the "ISRG Root X1" and "ISRG Root X2" root certificates, and the "Let’s Encrypt R3" intermediate one - link to their official site - https://letsencrypt.org/certificates/
Copy from the comments: download the .der field from the 1st category, download, double click and follow the wizard to install it.
QUESTION
I have a ring buffer that looks like:
...ANSWER
Answered 2021-Dec-31 at 12:49Previous answers may help as background:
c++, std::atomic, what is std::memory_order and how to use them?
https://bartoszmilewski.com/2008/12/01/c-atomics-and-memory-ordering/
Firstly the system you describe is known as a Single Producer - Single Consumer queue. You can always look at the boost version of this container to compare. I often will examine boost code, even when I work in situations where boost is not allowed. This is because examining and understanding a stable solution will give you insights into problems you may encounter (why did they do it that way? Oh, I see it - etc). Given your design, and having written many similar containers I will say that your design has to be careful about distinguishing empty from full. If you use a classic {begin,end} pair, you hit the problem that due to wrapping
{begin, begin+size} == {begin, begin} == empty
Okay, so back synchronisation issue.
Given that the order only effects reording, the use of release in Publish seems a textbook use of the flag. Nothing will read the value until the size of the container is incremented, so you don't care if the orders of writes of the value itself happen in a random order, you only care that the value must be fully written before the count is increased. So I would concur, you are correctly using the flag in the Publish function.
I did question whether the "release" was required in the Consume, but if you are moving out of the queue, and those moves are side-effecting, it may be required. I would say that if you are after raw speed, then it may be worth making a second version, that is specialised for trivial objects, that uses relaxed order for incrementing the head.
You might also consider inplace new/delete as you push/pop. Whilst most moves will leave an object in an empty state, the standard only requires that it is left in a valid state after a move. explicitly deleting the object after the move may save you from obscure bugs later.
You could argue that the two atomic loads in consume could be memory_order_consume. This relaxes the constraints to say "I don't care what order they are loaded, as long as they are both loaded by the time they are used". Although I doubt in practice it produces any gain. I am also nervous about this suggestion because when I look at the boost version it is remarkably close to what you have. https://www.boost.org/doc/libs/1_66_0/boost/lockfree/spsc_queue.hpp
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