aabbcc | Dynamic AABB trees in C++ with support for periodic systems
kandi X-RAY | aabbcc Summary
kandi X-RAY | aabbcc Summary
A C++ implementation of a dynamic bounding volume hierarchy (BVH) using axis-aligned bounding boxes (AABBs). The data structure provides an efficient way of detecting potential overlap between objects of arbitrary shape and size and is commonly used in computer game engines for collision detection and ray tracing. Because of their speed and flexibility, AABB trees are also well suited to overlap detection in physics applications, such as molecular simulation. They are particularly helpful for systems where there is a large size disparity between particle species, or whenever the particle density is extremely inhomogeneous. In such situations, traditional neighbour finding tools, such as cell lists, can become extremely inefficient (both in terms of memory footprint, and search speed). A good overview of the pros and cons of various neighbour finding algorithms can be found here. (Note that this only discusses the cost of querying different data structures, not the additional overhead of building them, or maintaining them as objects move around.). In statistical physics, a common means of approximating a bulk (infinite) system is through the use of periodic boundary conditions. Here, particles that are on opposite sides of the unit box can interact through its periodic image. This library supports periodic and non-periodic systems in an arbitrary number of dimensions (>= 2). Support is also provided for simulation boxes that are partially periodic, i.e. periodic along specific axes. At present, only orthorhombic simulation boxes are supported. The code in this library was adapted from parts of the Box2D physics engine.
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QUESTION
My question is simple. I am saving my listbox into txt file according to below code:
...ANSWER
Answered 2021-Apr-18 at 14:31Use readlines
instead of read
:
QUESTION
i'm try to create kibana space through ansible uri module here is my task
...ANSWER
Answered 2021-Apr-07 at 10:04Could you try adding the option
QUESTION
The idea is to complete the function and produce a compressed form of the string given. An example would be if the given string was aabbcc
then you would get a2b2c2
The issue with the code I created is for some reason it does not work with anything right away that is consecutive or consecutive letters at the end. wwww
turns into w4
but aa
does not turn into a2
and wuenuneubgnjfniwfibwiebfaaa
will not turn into wuenuneubgnjfniwfibwiebfa3
ANSWER
Answered 2021-Mar-10 at 21:43Your issue is the way you are handling it in the end. What happens to the variable next
when the loop is on the last iteration? You need to add an extra check on your if
.
Try this:
QUESTION
Suppose I have the following data frame. I want to transform it in way where it is ordered by "Days Left". IDs can be used more than once, and all Report numbers are unique. But I want every ID to appear once, before an already used ID is used again.
Like, AABBCC -> ABCABC or AABCCC -> ABCACC.
How would I turn this.
ID Report Days Left 171 11 5 171 12 9 182 13 1 182 14 2into this?
ID Report Days Left 182 13 1 171 11 5 182 14 2 171 12 9 ...ANSWER
Answered 2021-Feb-18 at 18:31cumcount should work
QUESTION
I have a React app that uses recharts to draw a bar graph. I use a function to check the data and decide whether to round the corners of a cell. It looks like the following:
...ANSWER
Answered 2021-Feb-15 at 16:03To fix your type problem, you could first turn each value from number to string by putting them in quotes: 30 => '30'.
However, afterwards there will be a type error on the radius
prop. To fix this one, you can translate its type to unknown
, and a second time to string
to remove the type warning.
Both changes should look like the following:
QUESTION
How to check if a given string has the same characters or their probability is the same, which gives me True?
For example, if there is
string = "aaaa"
the result is True
and:
ANSWER
Answered 2020-Nov-07 at 19:07Have you try ?
QUESTION
Json file sample (test1.json) :
...ANSWER
Answered 2020-Dec-16 at 08:12Unfortunately the jq documentation in trying to be helpful about Windows ends up being a bit misleading. Perhaps it would have been better to provide a pointer to comprehensive documentation, with the suggestion to avoid the headaches by using the -f command-line option.
One of the important details that is missing is that the caret character ^
serves as an escape character for symbols such as |
. So you could write:
QUESTION
I have the following schemas (removed most fields for readability):
...ANSWER
Answered 2020-Dec-04 at 02:11This could be what you are looking for:
QUESTION
Example: Given S="abccd" C=[0,1,2,3,4], the function should return 2. You can delete the 1st occurrence of 'c' to achieve "abcd". Given S="aabbcc" C=[1,2,1,2,1,2], the function should return 3, By deleting all letters with a cost of 1, you achieve string "abc". Given S="aaaa" & C=[3,4,5,6],the function should return 12, you need to delete all 'a' remaining one a, and the lowest cost of deletion is 3+4+5=12 Given S="abcde" C=[10,5,10,5,10],the function should return 0, there is no need to delete any letter.
I tried to solve by creating empty HashSet and find out the duplicate elements and returned the calculated costs else New string is added to set. I hope this solution is going to help.
...ANSWER
Answered 2020-Jun-27 at 01:17This type of question should not be asked on this platform. You want the solution you need to visit the forum of CodeChef, HackerEarth, codeforces, and soon.
Although I am coder, so I have coded for your problem and the solution is:
QUESTION
I use the aggregate function to count the most occurring unique values (which lets say is 5). I now want to list these unique values that were counted in a column - struggling with how to do that. Can I even do that? I'm using PostgreSQL.
...ANSWER
Answered 2020-Oct-14 at 04:20You could use the aggregate function ARRAY_AGG
or STRING_AGG
for that:
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