LameXP | Audio Encoder Front-End

 by   lordmulder C++ Version: Release_420 License: Non-SPDX

kandi X-RAY | LameXP Summary

kandi X-RAY | LameXP Summary

LameXP is a C++ library. LameXP has no bugs, it has no vulnerabilities and it has low support. However LameXP has a Non-SPDX License. You can download it from GitHub.

Audio Encoder Front-End
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            kandi-support Support

              LameXP has a low active ecosystem.
              It has 153 star(s) with 14 fork(s). There are 19 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 5 open issues and 84 have been closed. On average issues are closed in 96 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of LameXP is Release_420

            kandi-Quality Quality

              LameXP has no bugs reported.

            kandi-Security Security

              LameXP has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              LameXP has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

            kandi-Reuse Reuse

              LameXP releases are available to install and integrate.

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            LameXP Key Features

            No Key Features are available at this moment for LameXP.

            LameXP Examples and Code Snippets

            No Code Snippets are available at this moment for LameXP.

            Community Discussions

            QUESTION

            Haskell how to determine if an expression is simple or not?
            Asked 2020-Jun-20 at 15:18

            I am writing a function to determine if an expression is simple or not. A simple expression, in my case, is an expression that does not have an available function call. I have the following Exp types:

            ...

            ANSWER

            Answered 2020-Jun-20 at 15:18

            TL;DR A lambda expression is simple if (and only if) its body is simple.

            A lambda expression is, in some sense, just a special case of an operator expression, except the semantics of the operation are encoded in the grammar. You could imagine, for example, splitting OpExp into multiple operator-specific cases:

            Source https://stackoverflow.com/questions/62483591

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install LameXP

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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