World | quality speech analysis , manipulation and synthesis system | Speech library
kandi X-RAY | World Summary
kandi X-RAY | World Summary
I introduce useful software in WORLD. If you want to introduce your project in WORLD, please contact me. PyWorldVocoder (is a Python wrapper for World Vocoder. Python-WORLD (is line-by-line implementation of WORLD vocoder (Matlab, C++) in python. world-class (is a C++ library of WORLD. World.JS (is a JavaScript Wrapper for World Vocoder. World.NET (is a C# Wrapper for World Vocoder. WorldInApple (is a Swift wrapper for World Vocoder. DotnetWorld (is a C# wrapper for WORLD. Note: To avoid making the project complicated, I decided not to merge it to my repository and introduce your project here. The other reason is that I can't support some computer languages.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of World
World Key Features
World Examples and Code Snippets
package rxjava.examples;
import io.reactivex.rxjava3.core.*;
public class HelloWorld {
public static void main(String[] args) {
Flowable.just("Hello world").subscribe(System.out::println);
}
}
package rxjava.examples;
import io.reactivex.rxjava3.core.*;
public class HelloWorld {
public static void main(String[] args) {
Flowable.just("Hello world").subscribe(System.out::println);
}
}
public String greet(String name) {
HelloWorld helloWorld = new HelloWorld() {
@Override
public String greet(String name) {
return "Welcome to " + name;
}
};
return helloWorld.
def world_covid19_stats(url: str = "https://www.worldometers.info/coronavirus") -> dict:
"""
Return a dict of current worldwide COVID-19 statistics
"""
soup = BeautifulSoup(requests.get(url).text, "html.parser")
keys = soup.fin
public String findExpiringHelloWorld() {
String cacheKey = "expiring-hello";
String helloWorld = simpleHelloWorldCache.get(cacheKey);
if (helloWorld == null) {
helloWorld = repository.getHelloWorld();
s
Community Discussions
Trending Discussions on World
QUESTION
I understand that after calling fork() the child process inherits the per-process file descriptor table of its parent (pointing to the same system-wide open file tables). Hence, when opening a file in a parent process and then calling fork(), both the child and parent can write to that file without overwriting one another's output (due to a shared offset in the open-file table entry).
However, suppose that, we call open() on some file after a fork (in both the parent and the child). Will this create a separate entries in the system-wide open file table, with a separate set of offsets and read-write permission flags for the child (despite the fact that it's technically the same file)? I've tried looking this up and I don't seem to be able to find a clear answer.
I'm asking this mainly since I was playing around with writing to files, and it seems like only one the outputs of the parent and child ends up in the file in the aforementioned situation. This seemed to imply that there are separate entries in the open file table for the two separate open calls, and hence separate offsets, so the slower process overwrites the output of the other process.
To illustrate this, consider the following code:
...ANSWER
Answered 2021-May-03 at 20:22There is a difference between a file and a file descriptor (FD).
All processes share the same files. They don't necessarily have access to the same files, and a file is not its name, either; two different processes which open the same name might not actually open the same file, for example if the first file were renamed or unlinked and a new file were associated with the name. But if they do open the same file, it's necessarily shared, and changes will be mutually visible.
But a file descriptor is not a file. It refers to a file (not a filename, see above), but it also contains other information, including a file position used for and updated by calls to read
and write
. (You can use "positioned" read and write, pread
and pwrite
, if you don't want to use the position in the FD.) File descriptors are shared between parent and child processes, and so the file position in the FD is also shared.
Another thing stored in the file descriptor (in the kernel, where user processes can't get at it) is the list of permitted actions (on Unix, read, write, and/or execute, and possibly others). Permissions are stored in the file directory, not in the file itself, and the requested permissions are copied into the file descriptor when the file is opened (if the permissions are available.) It's possible for a child process to have a different user or group than the parent, particularly if the parent is started with augmented permissions but drops them before spawning the child. A file descriptor for a file opened in this manner still has the same permissions uf it is shared with a child, even if the child would itself be able to open the file.
QUESTION
Or, more specifically, does it use the default shell, or actually running the actual file. Example: system("echo Hello, World!")
. Would this run using, lets say Bash, or would this run by telling to kernal to run a command? Also, is this on topic, or would this fit better somewhere else?
ANSWER
Answered 2021-Jun-15 at 21:28man system
is your friend here. This is what is says on my system:
The system() library function uses fork(2) to create a child process that executes the shell command specified in command using execl(3) as follows:
QUESTION
I am working in react application and founded this stubborn thing. This is my state in react to which i am working on
...ANSWER
Answered 2021-Jun-15 at 20:51You seem to be confusing useState
with the class component's state.
Running setState({ testInfo: testInfoArray });
sets the entire state to { testInfo: testInfoArray }
, removing state.selectedParagraph
entirely, causing it to be undefined
.
You'll want to use useState
multiple times, like this:
QUESTION
I am trying to check if latitude
and longitude
exist in my SQL database, as currently when they are undefined, it leaves my web app blank on load with the following error TypeError: Cannot read property 'latitude' of undefined
My code was originally
...ANSWER
Answered 2021-Jun-15 at 18:36Looking at error TypeError: Cannot read property 'latitude' of undefined
. My guess is value of device.deviceData
is undefined
.
So,Please do verify with console.log(device)
if deviceData field exists in device.
And, to fix above issue you can try
QUESTION
So I initialized CAS using cas-initializr
with the following command inside the cas
folder:
ANSWER
Answered 2021-Jun-15 at 18:37Starting with 6.4 RC5 (which is the version you run as of this writing and should provide this in your original post):
The collection of thymeleaf user interface template pages are no longer found in the context root of the web application resources. Instead, they are organized and grouped into logical folders for each feature category. For example, the pages that deal with login or logout functionality can now be found inside login or logout directories. The page names themselves remain unchecked. You should always cross-check the template locations with the CAS WAR Overlay and use the tooling provided by the build to locate or fetch the templates from the CAS web application context.
https://apereo.github.io/cas/development/release_notes/RC5.html#thymeleaf-user-interface-pages
Please read the release notes and adjust your setup.
All templates are listed here: https://apereo.github.io/cas/development/ux/User-Interface-Customization-Views.html#templates
QUESTION
I'm making a POC with Lumen and Vue.JS. For now it just has to send a "hello world" message from the Lumen back-end to the Vue.JS front-end (which works). I have made an event which is triggered upon loading the page like this:
...ANSWER
Answered 2021-Jun-15 at 16:42Fix composer.json
I have created an issue on the PHP package: https://github.com/pusher/pusher-http-php/issues/295
It is true this version is broken, but the fix should be in the composer.json
file. Mine looked like this:
QUESTION
I'm struggling to use the Micronaut HTTPClient for multiple calls to a third-party REST service without receiving a io.micronaut.http.client.exceptions.ReadTimeoutException
To remove the third-party dependency, the problem can be reproduced using a simple Micronaut app calling it's own service.
Example Controller:
...ANSWER
Answered 2021-Jun-15 at 09:51If this isn't going to throw an exception then I don't know what is going to.
This is caused by using blocking
code within Netty's event loop
.
The code over here is making a blocking request 20 times in a row which cause the machine to break. I don't know what data is coming from the client but I would never recommend to do it in this manner.
QUESTION
I am attempting to add another checkbox to this program but for some reason it will not display when I run the program. Only the check box for the blue pill displays. I have attempted to add a couple things or change the way the program is structured, but nothing I have done so far has helped.
Code Below:
...ANSWER
Answered 2021-Jun-15 at 04:38When you're stuck on a problem, it never hurts to go back and consult the documentation.
You'll find information like this:
A border layout lays out a container, arranging and resizing its components to fit in five regions: north, south, east, west, and center. Each region may contain no more than one component, and is identified by a corresponding constant: NORTH, SOUTH, EAST, WEST, and CENTER. When adding a component to a container with a border layout, use one of these five constants...
When you add your button, you do this:
QUESTION
I have a Drilldown world map(continent map + country map) where the second map(the country map) is zoomed-in onload by using fitExtent
function. Since it is zoomed-in, I wanted to implement a draggable feature where I can drag the map and see other part of the map.
ANSWER
Answered 2021-Jun-15 at 12:55var svg = d3.select("#mapDiv")
.append("svg")
.attr("width", width)
.attr("height", height)
.style("background-color", "white")
.style("border", "solid 1px black")
.call(d3.zoom()
.on("zoom", function (event) {
svg.attr("transform", event.transform)
})
.scaleExtent([1, 1])
)
.append("g");
QUESTION
I am trying to understand the example with incorrect sync code from The Go Memory Model.
...Double-checked locking is an attempt to avoid the overhead of synchronization. For example, the twoprint program might be incorrectly written as:
ANSWER
Answered 2021-Jun-14 at 19:18According to the Go memory model:
There are no guarantees that one goroutine will see the operations performed by another goroutine unless there is an explicit synchronization between the two using channels, mutex. etc.
In your example: the fact that a goroutines sees done=true
does not imply it will see a
set. This is only guaranteed if there is explicit synchronization between the goroutines.
The sync.Once
probably offers such synchronization, so that's why you have not observed this behavior. There is still a memory race, and on a different platform with a different implementation of sync.Once
, things may change.
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